2.8 Function Operations and Composition

smiller5 409 views 24 slides Jan 05, 2021
Slide 1
Slide 1 of 24
Slide 1
1
Slide 2
2
Slide 3
3
Slide 4
4
Slide 5
5
Slide 6
6
Slide 7
7
Slide 8
8
Slide 9
9
Slide 10
10
Slide 11
11
Slide 12
12
Slide 13
13
Slide 14
14
Slide 15
15
Slide 16
16
Slide 17
17
Slide 18
18
Slide 19
19
Slide 20
20
Slide 21
21
Slide 22
22
Slide 23
23
Slide 24
24

About This Presentation

Arithmetic operations on functions
The Difference Quotient
Composition of Functions


Slide Content

2.8 Function Operations
Chapter 2 Graphs and Functions

Concepts and Objectives
Function operations
Arithmetic operations on functions
The Difference Quotient
Composition of Functions and Domain

Operations on Functions
Given two functions fand g, then for all values of xfor
which both fxand gxare defined, we can also define
the following:
Sum
Difference
Product
Quotient fgxfxgx  fgxfxgx fgxfxgx 


, 0
fxf
xgx
ggx





Operations on Functions (cont.)
Example: Let and . Find each
of the following:
a)
b)
c)
d)
2
1fxx 35gxx  1fg 1 1gf 
2
51 113  02 18  3fg  
2
353 31

 410 14 5fg  
2
35551

 02026 52 0
f
g


 
2
5
01
30


 5
1

Operations on Functions (cont.)
Example: Let and . Find
each of the following:
a)
b)
c)
d) 89fxx 21gxx  fgx 8921xx  fgx 8921xx fgx  8921xx 
f
x
g


 89
21
x
x


Operations on Functions (cont.)
Example: Let and . Find
each of the following:
e) What restrictions are on the domain?
There are two cases that need restrictions: taking the
square root of a negative number and dividing by zero.
We address these by making sure the inside of gx> 0:89fxx 21gxx 210
21
1
2
x
x
x



So the domain must be 11
or ,
22
x





The Difference Quotient
Suppose that point Plies on the graph of ,yfx
•Qx+h,fx+h
h

Px, fx
0
y= fx
Secant line
and suppose his a
positive number.

The Difference Quotient
Suppose that point Plies on the graph of ,yfx
•Qx+h,fx+h
h

Px, fx
0
y= fx
Secant line
and suppose his a
positive number. 

fxhfx
m
xhx



With these coordinates,
the slope of the line
joining Pand Qis

The Difference Quotient
Suppose that point Plies on the graph of ,yfx
•Qx+h,fx+h
h

Px, fx
0
y= fx
Secant line
and suppose his a
positive number. 

fxhfx
m
xhx


 fxhfx
h


With these coordinates,
the slope of the line
joining Pand Qis

The Difference Quotient
Suppose that point Plies on the graph of ,yfx
•Qx+h,fx+h
h

Px, fx
0
y= fx
Secant line
and suppose his a
positive number. 

fxhfx
m
xhx


 fxhfx
h


This slope is called the
difference quotientand the
line is called a secant line.
With these coordinates,
the slope of the line
joining Pand Qis

The Difference Quotient (cont.)
Example: Let . Find the difference
quotient and simplify the expression.
2
23fxxx

The Difference Quotient (cont.)
Example: Let . Find the difference
quotient and simplify the expression.
There are three pieces of the difference quotient:
fx+h, fx, and h. We already have fxand h, so we
just have to figure out fx+h:
2
23fxxx 
2
23fxhxhxh

The Difference Quotient (cont.)
Example: Let . Find the difference
quotient and simplify the expression.
There are three pieces of the difference quotient:
fx+h, fx, and h. We already have fxand h, so we
just have to figure out fx+h:
2
23fxxx 
2
23fxhxhxh  
22
223xxhhxh 22
24233xxhhxh

The Difference Quotient (cont.)
Example (cont.): Now we put everything together.  
2 2 2
2423323xxhhxhxxfxhfx
hh

 2 2 2
2423323xxhhxhxx
h

 2
423xhhh
h

  423
423
hxh
xh
h



Composition of Functions
If fand gare functions, then the composite function, or
composition, of gand fis defined by
The domain of g∘fis the set of all numbers xin the
domain of fsuch that fxis in the domain of g.
So, what does this mean? gfxgfx

Composition (cont.)
Example: A $40 pair of jeans is on sale for 25% off. If
you purchase the jeans before noon, the store offers an
additional 10% off. What is the final sales price of the
jeans?
We can’t just add 25% and 10% and get 35%. When
it says “additional 10%”, it means 10% off the
discounted price. So, it would be

25% off: .7540$30
10% off: .9030$27

Evaluating Composite Functions
Example: Let and .
(a) Find (b) Find 21fxx 
4
1
gx
x

 2fg 3gf

Evaluating Composite Functions
Example: Let and .
(a) Find (b) Find
(a) 21fxx 
4
1
gx
x

 2fg 3gf  22fgfg 
44
4
211
fff



 241817

Evaluating Composite Functions
Example: Let and .
(a) Find (b) Find
(b) 21fxx 
4
1
gx
x

 2fg 3gf   33gfgf   231617ggg 441
7182



Composites and Domains
Given that and , find
(a) and its domain
The domain of fis the set of all nonnegative real
number, [0, ∞), so the domain of the composite
function is defined where g≥ 0, thusfxx 42gxx fgx   42fgxfgxfx 42x 420x 1
2
x 1
so ,
2





Composites and Domains
Given that and , find
(b) and its domain
The domain of fis the set of all nonnegative real
number, [0, ∞). Since the domain of gis the set of all
real numbers, the domain of the composite function
is also [0, ∞).fxx 42gxx gfx  gfxgfxgx 42x

Composites and Domains (cont.)
Given that and , find
and its domain
6
3
fx
x

 
1
gx
x
 fgx 
1
fgxf
x



 6
1
3
x

 66
1313xx
xxx


 6
13
x
x

Composites and Domains (cont.)
Given that and , find
The domain of gis all real numbers except0, and the
domain of fis all real numbers except3. The expression
for gx, therefore, cannot equal 3:
6
3
fx
x

 
1
gx
x
 1
3
x
 13x 1
3
x 
11
,00,,
33





Classwork
2.8 Assignment (College Algebra)
2.8 –pg. 282: 2-14 (even); 2.7 –pg. 271: 24-36
(even); 2.6 –pg. 257: 48-52, 56 (even)
Classwork Check 2.8
Quiz 2.7
Tags