A is correct! The high electronegativity of fluor.pdf

sutharbharat59 22 views 1 slides Jun 30, 2023
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A is correct! The high electronegativity of fluorine (4.0 for F vs. 2.5 for carbon)
gives the carbon–fluorine bond a significant polarity/dipole moment. The electron density is
concentrated around the fluorine, leaving the carbon relatively electron poor. This introduces
ionic character to the bon...


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A is correct! The high electronegativity of fluorine (4.0 for F vs. 2.5 for carbon)
gives the carbon–fluorine bond a significant polarity/dipole moment. The electron density is
concentrated around the fluorine, leaving the carbon relatively electron poor. This introduces
ionic character to the bond through partial charges (Cd+—Fd-). The partial charges on the
fluorine and carbon are attractive, contributing to the unusual bond strength of the
carbon–fluorine bond. According to this same reason, with decreasing the Electronegativity (EN)
from F to I, the C-X bond become weaker.

Solution
A is correct! The high electronegativity of fluorine (4.0 for F vs. 2.5 for carbon)
gives the carbon–fluorine bond a significant polarity/dipole moment. The electron density is
concentrated around the fluorine, leaving the carbon relatively electron poor. This introduces
ionic character to the bond through partial charges (Cd+—Fd-). The partial charges on the
fluorine and carbon are attractive, contributing to the unusual bond strength of the
carbon–fluorine bond. According to this same reason, with decreasing the Electronegativity (EN)
from F to I, the C-X bond become weaker.
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