analisis de circuitos eléctricos para estudiantes de ingenieria.pptx

Un rectificador es el dispositivo electrónico que permite convertir la corriente alterna en corriente continua.1​ Esto se realiza utilizando diodos rectificadores, ya sean semiconductores de estado sólido, válvulas al vacío o válvulas gaseosas como las de vapor de mercurio (actualmente en desuso).

Dependiendo de las características de la alimentación en corriente alterna que emplean, se les clasifica en monofásicos, cuando están alimentados por una fase de la red eléctrica, o trifásicos cuando se alimentan por tres fases.

1. Circuit analysis

2. Series circuits A circuit consists of any number of elements joined at terminal points , providing at least one closed path through which charge can flow . The circuit of Fig. 5.4(a) has three elements joined at three terminal points (a, b, and c) to provide a closed path for the current I. Two elements are in series if 1. They have only one terminal in common (i.e., one lead of one is connected to only one lead of the other ). 2. The common point between the two elements is not connected to another current-carrying element . In general, to find the total resistance of N resistors in series, the following equation is applied :

3. It is totally unaware of how the elements are connected to establish R T . Once R T is known , the current drawn from the source can be determined using Ohm’s law , as follows :

4. The fact that the current is the same through each element permits a direct calculation of the voltage across each resistor using Ohm’s law ; that is , The power delivered to each resistor can then be determined using any one of three equations as listed below for R 1 : The power delivered by the source is The total power delivered to a resistive circuit is equal to the total power dissipated by the resistive elements . That is ,

5. EXAMPLE 5.1 a. Find the total resistance for the series circuit of Fig. 5.7. b. Calculate the source current I s . c. Determine the voltages V 1 , V 2 , and V 3 . d. Calculate the power dissipated by R 1 , R 2 , and R 3 . e. Determine the power delivered by the source , and compare it to the sum of the power levels of part (d).

6. For the circuits of Figure, the total resistance is specified . Find the unknown resistances and the current I for each circuit .

7. Parallel circuits The network of Figure is the simplest of parallel circuits . All the elements have terminals a and b in common . The total resistance is deter - mined by and the source current by . Throughout the text, the subscript s will be used to denote a property of the source. Since the terminals of the battery are connected directly across the resistors R 1 and R 2 , the following should be obvious: The voltage across parallel elements is the same. Using this fact will result in And with

8. For the Circuits Find the total resistance for the circuit of Figure. b. Calculate the source current I s . c. Determine the voltages of all the resistances . d. Calculate the power dissipated by all the resistances . e. Determine the power delivered by the source , and compare it to the sum of the power levels of part (d). R1= 1k Ω , R2= 2.7k Ω , R3=10k Ω , R4= 100k Ω , R5= 47 k Ω , R6 =470 k Ω R7= 1000k Ω