Aptitude-Problems on Trains.pdf

Quantitative Aptitude: Problems on Trains
Dr. Manjunatha. P
[email protected]
Professor & Dean Academics
JNNCE Shimoga
Dept. of ECE
J.N.N. College of Engineering, Shimoga
October 19, 2022

Problems on Trains
Formula to convert Km/hr to m/s
1hour= 6060 = 3600seconds
1km= 1000meters
x km=hr=x
1000
3600
=x
10
36
=x
5
18
m=s
Formula to convert m/s to Km/hr
1second=
1
6060
=
1
3600
hour
1meter=
1
1000
km
x m=s=x
1=1000
1=3600
=x
3600
1000
=x
36
10
=x
18
5
km=hr
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 2 / 18

Problems on Trains
Important Points to be considered for solving problems on moving trains:
1
The distance traveled by a train to cross a pole or person is equal to the
length of the train.
2
The distance traveled by train when it crosses a platform is equal to the
sum of the length of the train and length of the platform.
3
When two trains are traveling in opposite directions at speedsv1m/s and
v2m=sthen their relative speed is the sum of their individual speeds
(v1+v2)m=s.
4
Two trains are traveling in the same direction atv1m/s andv2m/s
wherev1> v2then their relative speed will be equal to the dierence
between their individual speeds(v1v2)m=s.
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 3 / 18

Problems on Trains
5
When two trains of lengthxmeters andymeters are moving in opposite
direction atv1m=sandv2m=sthen the time taken by the trains to
cross each other is
x+y
v1+v2
6
When two trains of lengthxmeters andymeters are moving in same
direction atv1andv2wherev1> v2then the time taken by the faster
train to cross the slower train =
x+y
v1v2
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 4 / 18

Problems on TrainsProblems on Pole/Man standing in the platform
Q1 A train running at the speed of 60 km/hr. It crosses a certain
pole that is in the way in 9 seconds. What is the length of the train?
Solution:
60km=hr= 60
5
18
=
50
3
m=s
The length of both the train is
Distance=SpeedTime
=
50
3
9
= 150m
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 5 / 18

Problems on TrainsProblems on Pole/Man standing in the platform
Q2 A train running at the speed of 56 km/hr crosses a pole in 18
seconds. What is the length of the train?
Solution:
56km=hr= 56
5
18
=
140
9
m=s
The length of both the train is
Distance=SpeedTime
=
140
9
18
= 280m
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 6 / 18

Problems on TrainsProblems on Pole/Man standing in the platform
Q3 A train moving at speed of 90 km/hr crosses a pole in 7 seconds.
Find the length of the train.
Solution:
90km=hr= 90
5
18
= 25m=s
The length of both the train is
Distance=SpeedTime
= 257
= 175m
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 7 / 18

Problems on TrainsPlatform/Bridge/Tunnel
Q1 A 90 m long train is running at a speed of 54 km/hr. If it takes
30 seconds to cross a platform, nd the length of the platform.
Solution: 54kmph= 54
5
18
= 15m=s
Time to cross the bridge = 30 sec
Distance to cross the platform
Distance=SpeedTime
= 1530 = 450m
Distance to cross the platform =length of train + length of platform
Length of platform=450-90=360 m
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 8 / 18

Problems on TrainsPlatform/Bridge/Tunnel
Q2 A train 175 m long crosses a bridge which is 125 m long in 80
seconds. What is the speed of the train?
Solution: Length of Train = 175 m
Length of bridge = 125 m
Distance to cross the bridge =length of train + length of bridgeDistance to cross the bridge =175+125=400 mSpeed of the train is
Speed=
Distance
Time
=
400
80
= 5m=sec
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 9 / 18

Problems on TrainsPlatform/Bridge/Tunnel
Q3 A train 220 m long is running at a speed of 36 km/hr. What time
will it take to cross a 110 m long tunnel?
Solution:
Length of Train = 220 m, Length of tunnel = 110 m
Total length=220+110=330 m
Speed of train 36 km/hr
36kmph= 36
5
18
= 10m=s
The time taken by a train to cross the tunnel is:Time=
Distance
Speed
=
330
10
= 33seconds
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 10 / 18

Problems on TrainsPlatform/Bridge/Tunnel
Q4 Find the time taken by 150 m long train passes through a bridge
which is 100 m long, running at a speed of 72 km/hr.
Solution: Length of Train = 150 m, Length of bridge = 100 m
Total length=150+100=250 m
Speed of train 72 km/hr
72kmph= 72
5
18
= 20m=s
The time taken by a train to cross the tunnel is:Time=
Distance
Speed
=
250
20
= 12:5seconds
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 11 / 18

Problems on TrainsMoving in the Opposite direction
Q1 Two trains, each 100 m long, moving in opposite directions, cross
each other in 8 seconds. If one is moving twice as fast the other,
then the speed of the faster train is
Solution:
xis the speed of rst train
yis the speed of second trainSpeed of one train is twice the speed of the other trainy= 2x
Total length of both the trains is100 + 100 = 200m
Distance=SpeedT ime
In this case the length of both the trains is equal to
the distance traveled.
T ime=
Distance
Speed
8 =
200
x+y
=
200
x+ 2x
3x=
200
8
= 25
x=
25
3
m=sec
=
25
3

18
5
km=sec
= 30km=hr
y= 2x= 230km=hr
= 60km=hr
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 12 / 18

Problems on TrainsMoving in the Opposite direction
Q2 Two trains, each 100 m long, moving in opposite directions, cross
each other in 12 seconds. If one is moving twice as fast the other,
then the speed of the faster train is
Solution:
xis the speed of rst train
yis the speed of second trainSpeed of one train is twice the speed of the other trainy= 2x
Total length of both the trains is100 + 100 = 200m
Distance=SpeedT ime
In this case the length of both the trains is equal to
the distance traveled.
T ime=
Distance
Speed
12 =
200
x+y
=
200
x+ 2x
3x=
200
12
=
50
3
m=sec
x=
50
9
m=sec
=
50
9

18
5
km=sec
= 20km=hr
y= 2x= 220km=hr
= 40km=hr
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 13 / 18

Problems on TrainsMoving in the Opposite direction
Q3 Two trains, each 100 m long, moving in opposite directions, cross
each other in 20 seconds. If one is moving twice as fast the other,
then the speed of the faster train is
Solution:
xis the speed of rst train
yis the speed of second trainSpeed of one train is twice the speed of the other trainy= 2x
Total length of both the trains is100 + 100 = 200m
Distance=SpeedT ime
In this case the length of both the trains is equal to
the distance traveled.
T ime=
Distance
Speed
20 =
200
x+y
=
200
x+ 2x
3x=
200
20
= 10m=sec
x=
10
3
m=sec
=
10
3

18
5
km=sec
= 12km=hr
y= 2x= 212km=hr
= 24km=hr
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 14 / 18

Problems on TrainsMoving in the Opposite direction
Q4 Two trains of length 150 m and 170 m respectively are running at
the speed of 40 km/hr and 32 km/hr on parallel tracks in opposite
directions. In what time will they cross each other?
Solution:
Relative speed of train = (40+32) km/hr
72km=hr= 72
5
18
m=sec
= 20m=sec
Total length of both the trains is
150 + 170 = 320m
Time to cross each other is
T ime=
Distance
Speed
=
320
20
= 16sec
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 15 / 18

Problems on TrainsMoving in the Same Direction
Q1 A train of 900 m long moves at 90 kmph can cross another train
of 1200 m long moving in the same direction in 3 min. What is the
speed of the second train?
Solution:
time t= 3minortime t=
3
60
=
1
20
hrTotal length of both the trains is1200 + 900 = 2100 = 2:1km
Distance=SpeedTime
Speed=
Distance
Time
90x=
2:1
1=20
= 42
x= 9042 = 48km=hr
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 16 / 18

Problems on TrainsMoving in the Same Direction
Q2 Two trains 130 m and 140 m long are running on parallel tracks in
the same direction with a speed of 68 km/hr and 50 km/hr. How
long will it take to clear o each other from the moment they meet?
Solution:
Relative speed of trains
= 6850 = 18km=hr
= 18
5
18
= 5m=sec
Total length of both the trains
130+140=270 mTime to clear o each other
Time=
Distance
Speed
=
270
5
= 54sec
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 17 / 18

Problems on TrainsMoving in the Same Direction
Q3 The two trains are running on parallel tracks in the same direction
at 70 km/hr and 50 km/hr respectively. The faster train passes a
man 27 second faster than the slower train. Find the length of the
faster train.
Solution:
Relative speed of trains
= 7050 = 20km=hr
= 20
5
18
=
50
9
m=sec
Length of the faster train
Distance=TimeSpeed
=
50
9
27 = 150m
Dr. Manjunatha. P (JNNCE) Quantitative Aptitude: Problems on Trains October 19, 2022 18 / 18

Aptitude-Problems on Trains.pdf

About This Presentation

Slide Content

Tags

Categories

Download

Quick Actions

Statistics

Related Slideshows

Aptitude-Problems on Trains.pdf

About This Presentation

Slide Content

Slide 1

Slide 2

Slide 3

Slide 4

Slide 5

Slide 6

Slide 7

Slide 8

Slide 9

Slide 10

Slide 11

Slide 12

Slide 13

Slide 14

Slide 15

Slide 16

Slide 17

Slide 18

Slide 19

Slide 20

Slide 21

Slide 22

Slide 23

Slide 24

Slide 25

Slide 26

Slide 27

Slide 28

Slide 29

Slide 30

Slide 31

Slide 32

Slide 33

Slide 34

Slide 35

Slide 36

Slide 37

Slide 38

Slide 39

Slide 40

Slide 41

Slide 42

Slide 43

Slide 44

Slide 45

Slide 46

Slide 47

Slide 48

Slide 49

Slide 50

Slide 51

Slide 52

Slide 53

Slide 54

Slide 55

Slide 56

Slide 57

Slide 58

Slide 59

Slide 60

Slide 61

Slide 62

Slide 63

Slide 64

Slide 65

Slide 66

Slide 67

Slide 68

Slide 69

Slide 70

Slide 71

Slide 72

Slide 73

Slide 74

Slide 75

Slide 76

Slide 77