BASIC HYDRAULICS
LESSON
Force
in
W
W
330 ft.
330 ft.
100 lbs.
100
lbs.
100 min.
1 min.
Power
Power = The rate of doing work per unit of time
Power=
F X D
Time
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Force
in
PASCALS LAW
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Force
in
PASCALS LAW
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Force
in
PASCALS LAW
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Area = 10 in
2
Force = 200 lbs
Pressure = 20 psi
F
pA
Force = Pressure x Area
PASCALS LAW
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Force =
in
Area =
1
Area =
2
Force =
out
A
PASCALS LAW
F
pA
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Area =
Pressure =
F
pA
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D
= D x .7854
2
Cap-End Area
Cap-End
CAP-END AREA
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D
1
D
2
A
ann
A
ann A
cap A
rod
= (D - D ) x .7854
12
22
Rod-End Area
Rod-End or
annulus area
Annulus area = area of cap end - area of rod
ANNULUS OR
ROD END AREA
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Pressure = Pressure =
Area = Area =
F
pA
= D x .7854
2
Area
PASCALS LAW
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Volume = Area x Length
L
e
n
g
t
h
Area
diam =
Volume to Extend = ?
L
e
n
g
t
h
=
2
0
in
.
CYLINDER VOLUME
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Work = Force x Distance
ForceForce
Distance
WORK
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W
W
330 ft.
330 ft.
100 lbs.
100
lbs.
100 min.
1 min.
Power
Power = The rate of doing work per unit of time
Power=
F X D
Time
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Force =
in
Force =
out
FORCE MULTIPLICATION
WORK AND POWER
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Force =
in
Force =
out
Area =
in
Area =
out
Pressure =
FORCE MULTIPLICATION
WORK AND POWER
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Force =
in
Force =
out
Area =
in
Area =
out
Work =
in Work =
out
FORCE MULTIPLICATION
WORK AND POWER
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WHO DOES THE MOST WORK ?
WHO HAS THE MOST POWER?
2500# Coal pile
Move the pile 500ft.
5 min
8 hr
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A
A
12 in
2
6 in
2
WHO HAS THE POWER ?
1 GPM
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1 cubic foot of oil weighs approx. 58 lbs
12 in.
12 in.
12 in.
Area = 144 in
2
Pressure = = 0.4 psi
Force
Area
=
58 lbs
144 in
2
10 ft.
4 psi
2 psi
0.4 psi
PRESSURE AT THE BOTTOM
OF A COLUMN OF OIL
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p =
F
A
=
58 lbs
144 in
2= 0.4 psi p =
F
A
=
4(58) lbs
2(144) in
2= 0.8 psi
PRESSURE AT THE BOTTOM
OF A COLUMN OF OIL
12 in.
12 in.
12 in.
12 in.
12 in.
p
12 in.
12 in.
12 in.
p
wt.of water = 62.4 lb/ft
wt. of oil = 55 - 58 lb/ft (use 58)
3
3
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Area = 1 in
2
A column of air one square inch in
cross-section and as high as the
atmosphere ...
... weighs 14.7 pounds at sea level.
Atmospheric pressure is therefore
14.7 psia.
ATMOSPHERIC PRESSURE
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On the earth's surface we are
swimming in a sea of air. The
pressure exerted is caused by the
weight of the air above us. This
pressure is referred to as
"atmospheric pressure". As we
gain altitude above sea level, the
atmospheric pressure decreases.
W h e n w e g o
u n d e r w a t e r, t h e
pressure gets greater
the deeper we go. This
pressure is caused by
the weight of the water
column above us.
1 in
2
ATMOSPHERIC PRESSURE
Earth
Atmosphere
h
h
h
Atmospheric Pressure = 14.7 psia @ sea level
wt. = 14.7 lbs
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Reduced pressure
here allows...
Atmospheric pressure here
to force fluid up the straw.
Pressure differential causes fluid
to flow from the high pressure
area to the low pressure area.
ATMOSPHERIC PRESSURE
WORKS FOR US
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CAVITATION OF HYDRAULIC PUMP
Restriction
Erosion
Vapor
Bubbles
Implode
Vapor
Bubbles
Form
Cavitation of Hydraulic Pump
Due to Overspeeding
Erosion
Atmospheric
Pressure
Reservoir
Overspeeding
Pump
Imploding
Bubbles
Fluid velocity, due to
excessive pump
speed, is higher than
the pump inlet can
accommodate
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AERATION OF HYDRAULIC PUMP
Air
Leaky
Fitting Erosion
Air Bubbles
Implode
Air Bubbles
Expand
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Causes of Cavitation Causes of Aeration
1. Clogged or restricted strainer
2. High fluid viscosity
3. Low fluid temperature
4. Clogged reservoir breather
5. Pump inlet line too small
6. Pump too far above reservoir
7. Pump too far from reservoir
8. Excessive pump RPM
9. Too many bends in pump inlet line
10. Collapsed hose on pump inlet line
11. Restriction on pump inlet line
12. Failure of supercharge pump
1. Low reservoir fluid level
2. Defective pump shaft seal
3. Return line above fluid level
4. Improper baffling in the reservoir
5. Loose fitting on pump inlet line
6. Defective seal on pump inlet line
7. Incorrect reservoir design
8. Porous hose on pump inlet line
CAUSES OF CAVITATION AND AERATION
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SERIES CIRCUIT
50 psi100 psi150 psi
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F
out
Q
A
out
p
p
p
PRESSURE DROP
10,000#
1000 PSI
1700 PSI
10 In
2
1500 PSI
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STEEL TUBING
Nominal Size
Wall Thickness
Stainless steel tubing is used for high pressure and corrosive applications.
Easily bent and flared.
Terminated with compression fittings (flared of ferrule types) or welded connections.
Nominal size specifies outside diameter.
Each size available in several wall thicknesses to withstand higher pressures.
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FLEXIBLE HOSE
Cover Carcass
Inner
Tube
Used when hydraulic lines subject to movement, flexing, and/or vibration.
Some fittings require the hose to be skived (the cover removed at connection),
others do not.
Nominal size specifies inside diameter.
Hose fittings may be reusable (screw together, bolt together),
or non-reusable (crimp or swage).
Dash numbers specify 1/16ths of an inch. (e.g. -6 specifies 6/16" = 3/8")
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W
W
330 ft.
330 ft.
100 lbs.
100
lbs.
100 min.
1 min.
Work = 100 lbs. x 330 ft.
= 33,000 ft-lb
Work = 100 lbs. x 330 ft.
= 33,000 ft-lb
Power = 33,000 ft-lb
100 min.
= 330 ft-lb/min
= .01 hp
Power = 33,000 ft-lb
1 min.
=33,000 ft-lb/min
= 1 hp
HORSEPOWER
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HORSEPOWER CONVERSIONS
1 Horsepower
heat 1 Horsepower
elec= 2547 BTU per hour
= 42.5 BTU per minute
= 746 watts
1 BTU = heat required to raise 1 lb of water 1 F.
o Watts = amps x volts
pressure
drop (psi)
flow (gpm)
heat
Electric MotorHydraulic Restriction
electric current is
converted to mechanical
horsepower
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Electric Motor
Hydraulic Pump
electric power in
hydraulic power out
Pump output HP =GPM X PSI X .000583Pump input HP =GPM X PSI X .0007 (83%)
Pump input HP
X PSI GPM X .000583
Pump Efficiency
=
PUMP HORSEPOWER FORMULAS
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P
P
T
T
A
A
B
B
HORSEPOWER
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