Oxidation state
The elements of group 13 have to two electrons in the s- orbital and one electron in the p-orbital of the valence shell.
These elements are expected to show a uniform oxidation state of +3. Boron and aluminium which show an oxidation
state of +3 only but gallium, indium and thallium due to inert pair effect show oxidation state of both +1 and +3 .
As we move down the group, the stability of +3 oxidation state decreases while that of +1 oxidation state
increases. The order of stability of +1 oxidation states increases in the order : Al < Ga < In < Tl.
In gallium and indium +3 oxidation state is more stable than +1 oxidation state , therefore both Ga
+
and In
+
salts
undergo disproportionation reaction in aqueous solution.
3 GaX (s) ——->2 Ga (s) + Ga
3+
+ 3 X‾ (aq)
3 InX (s) ——->2 In (s) +In
3+
+ 3 X‾ (aq)
Thallous compounds such as thallous hydroxide ( TlOH) and thallous perchlorate(TlClO4) are more stable than their
corresponding thallic compounds.
Due to lesser stability of , Tl
3+
salts act as strong oxidising agent.
The stability of +1 oxidation State increases down the group.
Reason: As we move down the group, the tendency of s-electrons of the valence shell to participate in bond formation
decreases. This reluctance of the s-electrons to participate in bond formation is called inert pair effect. The
ns
2
electron pair in gallium ,indium and thallium tends to remain paired. This is due to poor or ineffective shielding of
the ns
2
electrons of the valence shell by intervening d and f electrons.
As the size of the atom increases from aluminium to thallium, the energy required to unpair the ns
2
electrons is not
compensated by the energy released in forming the two additional bonds.
The inert pair effect becomes more predominant as we go down the group because of increased nuclear charge
which outweighs the effect of the corresponding increase in atomic size. The s-electrons thus become more tightly
held ,and ,therefore ,becomes more reluctant to participate in bond formation. Thus down the group , +1 oxidation
State become more and more stable as compared to +3 oxidation state.
Trends in chemical reactivity
In +3 oxidation state , elements of this group are expected to form covalent bonds because of the following three
reasons :
1) According to Fajan’s rule, the small size of the ions and their high charge of +3 , favour the formation of covalent
bonds.
2) The sum of first three ionization enthalpies is very large. This also suggest that bonds will be largely covalent .
3) The electronegativity values of group 13 elements are higher than those of group 1 and 2 .When these elements
react with other elements, the electronegativity difference will be small. This also favours the formation of covalent
bond.
1) Boron because of its small size and high sum of first three ionization enthalpies, does not lose its 3 Valence
electrons to form B
3+
ions. It does not form ionic compounds. Instead , boron always form covalent compounds by
sharing is valence .
2) As we move from Boron to aluminium, the sum of first three ionization enthalpies decreases and thus aluminium
has only little tendency to form ionic compounds. It has a strong tendency to form covalent compounds.
For Ex: AlF3 and Al2(SO4)3 are ionic while AlCl3 , AlBr3 and AlI3 are covalent.
GaCl3 , InCl3 are covalent when anhydrous. Al , Ga , In and Tl all for metal ions in solution. The change from
covalent to ionic nature occurs due to the reason that in aqueous solution , these ions are hydrated and the amount of
hydration enthalpy released exceeds the ionization enthalpy.
Gallium, indium and thallium show two oxidation states of +1 and +3 due to inert pair effect . Since the ions in the +1
oxidation state are much larger than the ions in the +3 oxidation state, therefore ,these compounds in +1 oxidation
states are more ionic than in +3 oxidation state.
In the trivalent state , most of compounds being covalent are hydrolysed by water to form either tetrahedral species,
[M(OH)4]‾ in which the element is sp
3
hybridized or octahedral species, [M(H2O)6 ]
3+
in which the element is
sp
3
d
2
hybridized.
BCl3 on hydrolysis forms tetrahedral [B(OH)4]‾ species because boron due to the absence of d – orbital cannot
expand its covalency beyond 4.