Break and continue statement in C

Explanation of break and continue statements in C language.

1. Break and Continue statement

2. Break Statement

3. June
Result
December
Result
Normal Study Period
Re-valuation
Result
Study Period if subject
is cleared in the
revaluation process

4. #include<stdio.h>
#include<conio.h>
main()
{
……………………………….
……………………………….
……………………………….
while(condition)
{
…………….
…………….
if(condition)
break;
…………….
…………….
…………….
increment or decrement;
}
………………………………….
………………………………….
………………………………….
getch();
}
If condition becomes true

5. Prime Number
. , , , ,
, , :
….!
, , , , , ,
….!

6. #include<stdio.h>
#include<conio.h>
void main()
{
int num, i;
clrscr();
printf(“Enter Number\t”);
scanf(“%d”, &num);
i = 2;
while(i < num –1)
{
if(num % i == 0)
{
printf(“Numbers is not prime\n”);
break;
}
i++;
}
if(i == num)
printf(“Number is prime\n”);
getch();
}

7. Enter Number 5
Number is prime
_

8. Enter Number 37
Number is prime
_

9. Enter Number 25
Number is Not prime
Number is prime
_

10. Enter Number 25
Number is Not prime
_

11. #include<stdio.h>
#include<conio.h>
void main()
{
int num, i;
clrscr();
printf(“Enter Number\t”);
scanf(“%d”, &num);
i = 2;
while(i < num –1)
{
if(num % i == 0)
{
printf(“Numbers is not prime\n”);
break;
}
i++;
}
if(i == num)
printf(“Number is prime\n”);
getch();
}
25 2
num i

12. Continue statement
for(i = 1; i < 10; i++)
{
do this;
do this;
if(condition)
continue;
do this;
do this;
}
If condition is
true
If condition is
false

13. 5
10
15
20
25
30
35
40
45
50
_

14. #include<stdio.h>
#include<conio.h>
void main()
{
int j;
clrscr();
for(j=1; j<=50; j++)
{
if(j % 5 != 0)
continue;
printf(“%d\n”, j);
}
getch();
}
When j is not divisible
by 5