Calculate the amount of Solute Grade 8.pptx

DerlynAgananMadia 46 views 33 slides Sep 25, 2024
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About This Presentation

a powerpoint presentation on how to calculate the amount of solute in a given solution.


Slide Content

SCIENCE 7 First QUARTER- lc 9.2 Matatag curriculum LESSON 2: Calculate the amount of solute in a given volume of solution (percent by volume)

Calculate the amount of solute in a given volume of solution (percent by volume) CONTENT The learners shall learn the properties of solutions such as solubility and reaction to litmus determine their use. LEARNING STANDARD The learners shall be able to identify the role of the solute and solvent in a solution and to express quantitatively the amount of solute present in a given volume of solution. LEARNING COMPETENCY

By the end of the lesson, the 80 percent of the learners will be able to: Define the term "percent by volume" Calculate the percent by volume of a solute in a given solution. Appreciate the concept of percent by volume by solving real-world problems involving solution concentrations. OBJECTIVES

I. Activating Prior Knowledge Think-Pair-Share: Pose the following question to the class. Give students a few minutes to think about the question individually. Instruct students to turn to a partner and discuss their understanding of the terms solute and solvent. Call on a few pairs to share their thoughts with the class. I. Activating Prior Knowledge

I. Activating Prior Knowledge Think-Pair-Share: "What is the difference between a solute and a solvent in a solution?“ I. Activating Prior Knowledge

I. Activating Prior Knowledge Think-Pair-Share: Individual Thinking Time Give students 2-3 minutes to think about the question individually. Encourage them to recall their prior knowledge and consider the definitions of solute and solvent. I. Activating Prior Knowledge

I. Activating Prior Knowledge Think-Pair-Share: Pair Discussion Instruct students to turn to a partner and discuss their understanding of the terms solute and solvent. Prompt them to share their thoughts and compare their ideas. Encourage them to ask each other questions and clarify any misconceptions. I. Activating Prior Knowledge

I. Activating Prior Knowledge Think-Pair-Share: Class Sharing Call on a few pairs to share their discussions with the class. Invite them to explain their understanding of the difference between solute and solvent. Encourage other students to add to the discussion or provide additional insights. I. Activating Prior Knowledge

I. Activating Prior Knowledge Think-Pair-Share: Key Takeaways Summarize the key differences between solute and solvent: The solute is the substance that is dissolved in the solution. The solvent is the substance that does the dissolving and forms the majority of the solution. I. Activating Prior Knowledge

Explain to students that understanding percent by volume is crucial in many areas of chemistry, such as in the preparation of chemical solutions, the analysis of mixtures, and the interpretation of experimental data. Highlight the real-world applications of percent by volume, such as in the formulation of pharmaceutical products, the dilution of household chemicals, and the analysis of fuel compositions. Emphasize that the ability to accurately calculate and interpret percent by volume will be an essential skill for students in their further studies and future careers in chemistry. B. Establishing Purpose of the Lesson 1. LESSON PURPOSE

B. Establishing Purpose of the Lesson B. Establishing Purpose of the Lesson 2. Unlocking Content Vocabulary: Match Type Activity Solvent Percent by volume Percent by mass The substance that does the dissolving and forms the majority of the solution - The concentration of a solute expressed as the volume of the solute divided by the total volume of the solution, multiplied by 100 - The ratio of the mass of a solute to the total mass of the solution, expressed as a percentage Solute The substance that is dissolved in a solution.

C. Developing and Deepening Understanding What is Percent by Volume? Percent by volume is the concentration of a solute expressed as the volume of the solute divided by the total volume of the solution, multiplied by 100. Define the term "Percent by Volume"

C. Developing and Deepening Understanding How to Calculate Percent by Volume: Identify the volume of the solute and the total volume of the solution. Divide the volume of the solute by the total volume of the solution. Multiply the result by 100 to express it as a percentage . Step-by-Step Calculation

C. Developing and Deepening Understanding Example: Volume of solute = 25 mL Total volume of solution = 100 mL 25 mL / 100 mL = 0.25 0.25 x 100 = 25% Therefore, the percent by volume of the solute in the solution is 25%. Step-by-Step Calculation

C. Developing and Deepening Understanding Problem 1: A solution contains 50 mL of acetic acid (the solute) in a total volume of 250 mL. Calculate the percent by volume of acetic acid in the solution. Step-by-Step Solution: Volume of solute (acetic acid) = 50 mL Total volume of solution = 250 mL Percent by volume = (Volume of solute / Total volume of solution) x 100 = (50 mL / 250 mL) x 100 = 0.2 x 100 = 20% Therefore, the percent by volume of acetic acid in the solution is 20%. Worked Example

C. Developing and Deepening Understanding Problem 2: A solution contains 75 mL of ethanol (the solute) in a total volume of 500 mL . Calculate the percent by volume of ethanol in the solution. Step-by-Step Solution: Volume of solute (ethanol) = 75 mL Total volume of solution = 500 mL Percent by volume = (Volume of solute / Total volume of solution) x 100 = (75 mL / 500 mL) x 100 = 0.15 x 100 = 15% Therefore, the percent by volume of ethanol in the solution is 15%. Worked Example

C. Developing and Deepening Understanding Problem No. 1 What is the percent volume of ethyl alcohol in a 100 mL of rubbing alcohol which contains 30 mL of ethyl alcohol? Lesson Activity Given information: Total volume of the solution (rubbing alcohol) is 100 mL Volume of ethyl alcohol (the solute) is 30 mL To calculate the percent by volume of ethyl alcohol, we use the formula: Percent by volume = (Volume of solute / Total volume of solution) x 100 Percent by volume = (30 mL / 100 mL) x 100 = 0.3 x 100 = 30% Therefore, the percent by volume of ethyl alcohol in the 100 mL of rubbing alcohol is 30%.

C. Developing and Deepening Understanding Problem No. 2 Calculate the percent volume of benzene in a solution made by dissolving 15 mL of benzene to 70 mL of toluene. Lesson Activity Given information: Volume of benzene (the solute) is 15 mL Total volume of the solution (benzene and toluene) is 70 mL + 15 mL = 85 mL To calculate the percent by volume of benzene, we use the formula: Percent by volume = (Volume of solute / Total volume of solution) x 100 Percent by volume = (15 mL / 85 mL) x 100 = 0.1765 x 100 = 17.65% Therefore, the percent by volume of benzene in the 85 mL solution is 17.65%.

C. Developing and Deepening Understanding Problem No. 3 What is the percent volume of acetone in a solution made from adding 10 liters of acetone to 25 liters of water? Lesson Activity Given information: Volume of acetone (the solute) is 10 liters Total volume of the solution (acetone and water) is 10 liters + 25 liters = 35 liters To calculate the percent by volume of acetone, we use the formula: Percent by volume = (Volume of solute / Total volume of solution) x 100 Percent by volume = (10 liters / 35 liters) x 100 = 0.2857 x 100 = 28.57% Therefore, the percent by volume of acetone in the 35 liter solution is 28.57%.

D. MAKING GENERALIZATION Learners’ Takeaways Has this lesson helped you to calculate the amount of solute in each volume of solution (percent by volume)? /If yes, how?

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________1. What is the formula for calculating percent by volume? Percent by volume = (Mass of solute / Total mass of solution) x 100 Percent by volume = (Volume of solute / Total volume of solution) x 100 Percent by volume = (Moles of solute / Total moles of solution) x 100 Percent by volume = (Concentration of solute / Total concentration of solution) x 100

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________2. A solution contains 20 mL of ethanol in a total volume of 100 mL. What is the percent by volume of ethanol in the solution? 10% 20% 50% 80%

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________3. How many milliliters of a solute must be added to 500 mL of a solution to make a 15% by volume solution? 50 mL 75 mL 100 mL 150 mL

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________4. A solution contains 40 mL of acetic acid in a total volume of 200 mL. What is the percent by volume of acetic acid in the solution? 10% 20% 25% 40%

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________5. What is the total volume of a solution that contains 25 mL of a solute with a percent by volume of 20%? 100 mL 125 mL 150 mL 175 mL

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________6. A solution contains 60 mL of isopropyl alcohol in a total volume of 300 mL. What is the percent by volume of isopropyl alcohol in the solution? 10% 15% 20% 25%

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________7. If a solution has a percent by volume of 35% and a total volume of 350 mL, what is the volume of the solute in the solution? 70 mL 105 mL 122.5 mL 175 mL

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________8. A solution contains 80 mL of glycerol in a total volume of 400 mL. What is the percent by volume of glycerol in the solution? 10% 15% 20% 25%

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________9. What is the percent by volume of a solute if the volume of the solute is 45 mL and the total volume of the solution is 150 mL? 15% 25% 30% 45%

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING __________10. A solution contains 12 mL of a solute in a total volume of 60 mL. What is the percent by volume of the solute in the solution? 10% 15% 20% 25%

E. EVALUATING LEARNING E. EVALUATING LEARNING E. EVALUATING LEARNING Answer Key: b) Percent by volume = (Volume of solute / Total volume of solution) x 100 b) 20% d) 150 mL c) 25% b) 125 mL c) 20% d) 175 mL c) 20% c) 30% 10. c) 20%

Reference : SCIENCE 7 LESSON EXEMPLAR Textbooks: Chang, R., & Goldsby, K. A. (2013). Chemistry (11th ed.). McGraw-Hill Education. Zumdahl, S. S., & Zumdahl, S. A. (2013). Chemistry (9th ed.). Cengage Learning. Tro, N. J. (2017). Chemistry: A Molecular Approach (4th ed.). Pearson. Online Resources: "Percent Composition and Empirical Formulas" from Khan Academy https://www.khanacademy.org/science/chemistry/chemical-bonding-and-reactions/percent-composition/a/percent-composition-and-empirical-formulas "Percent Composition by Mass" from Boundless Chemistry https://courses.lumenlearning.com/boundless-chemistry/chapter/percent-composition-by-mass/ "Percent Composition" from Chemistry LibreTexts https://chem.libretexts.org/Bookshelves/General_Chemistry/Book%3A_Chemistry_(OpenSTAX)/03%3A_Composition_of_Substances_and_Solutions/3.2%3A_Percent_Composition "Percent Composition and Empirical Formulas" from Crash Course Chemistry https://www.youtube.com/watch?v=RnGu3Xxayb0 "Percent Composition by Mass" from Purdue University ChemConnections https://www.chem.purdue.edu/chemconnections/PercentComposition.php
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