lowering of vapour pressure, elevation of boiling point, depression of freezing point and osmotic pressure including necessary thermodynamic derivations.
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Md. Imran NurManik
Lecturer
Department of Pharmacy
Northern University Bangladesh
Derivation of Raoult’sLaw
Let,pisthevapourpressureofthesolventandp
sthatofthesolution,thevaporpressu
reofthesolutionisdirectlyproportionaltothemolefractionofthesolvent.Thevapor
pressureofthesolutionis,therefore,determinedbythenumberofmolecules
ofthesolventpresentatanytimeinthesurfacewhichisproportionaltothe
molefraction.
Thatis,
WhereN=molesofsolventandn=molesofsolute.
Where,k=proportionalityfactor.
Incaseofpuresolvent,n=0
Andhencemolefractionofsolvent
Nowfromequation(1),thevaporpressureofthesolventp=k
Thereforetheequation(1)assumestheform
ThisisRaoult’sLaw.Nn
N
ps
)1(
Nn
N
kps 1
0
N
N
Nn
N Nn
n
p
pp
Nn
N
p
p
Nn
N
p
p
Nn
N
pp
s
s
s
s
11
Ideal Solutions and Deviations from Raoult’sLaw
AsolutionwhichobeysRaoult’slawstrictlyiscalledanIdealsolution
. A solution which shows
deviationsfromRaoult’slawiscalledaNonidealorRealsolution.
Supposethemoleculesofthesolventandsolutearerepresentedby
AandBrespectively.
Nowletγ
ABbetheattractiveforcebetweenAandB,andγ
AAbetween
AandA.
Ifthesolutionshowsthesamevapourpressurethenallcomponents
havesameforceofattractionandthusitisanidealsolution.γ
AB=γ
A
A
Inreality,therearefewsolutionswhichobeyRaoult’slawstrictly.The
more dilute a solution the
moredoesitapproachideality.
However,ifγ>γmoleculeAwillescapelessreadilyandthevapo
Determination of Molecular Mass from Vapour Pressure Lowering
Themolecularmassofanon-volatilesolutecanbedeterminedbymeasuringtheloweringof
vapourpressure(p–p
s)producedbydissolvingaknownweightofitinaknownweightofthe
solvent.IfinadeterminationwgramsofsoluteisdissolvedinWgramsofthesolvent,mandM
aremolecularmassesofthesoluteandsolventrespectively,wehave:
No.ofMolesofsolute andNo.ofMolesofsolvent
Weknowthat,Raoult’sLaw
SubstitutingthesevaluesintheRaoult’slawEquation, -----------------(1)
Sinceforverydilutesolution,thenumberofmoles(molecules)ofsolute(w/m),isverysmall,it
canbeneglectedinthedenominator.
Theequation(1)cannowbewrittenas ----------------------------------------------(2)
Knowingtheexperimentalvalueofp–p
s/p,andthemolecularmassofthesolvent(M),the
molecularweightofsolute(m)canbecalculatedfrom(1)or(2).
Elevation of Boiling Point
Whenaliquidisheated,itsvapourpressurerisesandwhenit
equalstheatmosphericpressure,theliquidboils.Theadditionof
anon-volatilesolutelowersthevapourpressureand
consequentlyelevatestheboilingpointasmoreheatisneeded
tosupplyadditionalkineticenergytoraisethevapourpressure
toatmosphericpressure.ItisCalledboiling-pointelevation.
IfT
bistheboilingpointofthepuresolventandTistheboiling
pointofthesolutionofanonelectrolyteinthatsolvent,the
differenceintheboilingpoints(ΔT
b)iscalledtheelevationof
boilingpoint.T–T
b=ΔT
b
Fordilutesolutions,thecurvesBDandCEareparalleland
straightlinesapproximately.ThereforeforsimilartrianglesACE
andABD,wehave
or,
Wherep–p
1andp–p
2areloweringofvapourpressurefor
solution1andsolution2respectively.
Hencetheelevationofboilingpointisdirectlyproportionaltothe
loweringofvapourpressure.orΔT
b∝(p–p
s).
Raoult’sLaw of boiling point elevation
(i)Theelevationofboilingpointofasolutionis
proportionaltoitsmolalconcentrationi.e.toitsmolality,m.
T
b∝m
Or,T
b=K
b.mwhereKisknownasBoilingpointconstant,or
EbbulioscopicconstantorMolalelevationconstant.
Whenm=1,thenT
b=K
b
So,molalelevationconstantmaybedefinedasboilingpoint
elevationproducedwhen1moleofsoluteisdissolvedinonekg
(1000g)ofthesolvent.
(ii)Equimolecularquantitiesofdifferentsubstancesdissolvedinthe
samequantityofaparticularsolventraiseitsboilingpointtothe
sameextent.
Depression of
Freezing point
Thefreezingpointofasolutionisalwayslowerthanthatofthe
puresolvent.
Thedifferenceofthefreezingpointofthepure
solventandthesolutionisreferredtoasthe
Depressionoffreezingpoint.Itisrepresentedbythesymbol
ΔTorΔT
f.AndDepressionoffreezingpoint.IsT
f–T
1=ΔT
Derivation
Thevapourpressurecurveofasolution(solution1)ofa
non-volatilesolutemeetsthefreezingpointcurveatF,indicating
thefreezingpointofthesolution,T
1.Additionofmoresolute
causesafurtherloweringoffreezingpointtoT
2.Herethefreezing
pointofpuresolvent,T
f.
For dilute solutions FD and CE are approximately parallel straight
lines and BC is also a straight line. Since the triangles
BDF and BEC are similar, thus
whereP
1andP
2arevapourpressureofsolution1andsolution2
respectively.Hencedepressionoffreezingpointisdirectlyproporti
onaltotheloweringofvapourpressure.
orΔT
f∝(p–p
s).
Raoult’sLaw of depression of freezing point
(i)Thedepressionoffreezingpointofasolutionisproportional
toitsmolalconcentrationi.e.toitsmolality,m.
T
f∝m
T
f=K
f.mwhereK
fisknownasmolaldepressionoffreezing
pointconstantorcryoscopicconstant.
Whenm=1,thenT
b=K
b.
So,cryoscopicconstantmaybedefinedasfreezingpoint
reductionproducedwhen1moleofsoluteisdissolvedin1000g
ofthesolvent.
(ii)Equimolecularquantitiesofdifferentsubstancesdissolvedin
thesamequantityofaparticularsolventreduceitsfreezing
pointtothesameextent.