Contour & Contouring Surveying

Bahzad5 775 views 39 slides Sep 11, 2022
Slide 1
Slide 1 of 39
Slide 1
1
Slide 2
2
Slide 3
3
Slide 4
4
Slide 5
5
Slide 6
6
Slide 7
7
Slide 8
8
Slide 9
9
Slide 10
10
Slide 11
11
Slide 12
12
Slide 13
13
Slide 14
14
Slide 15
15
Slide 16
16
Slide 17
17
Slide 18
18
Slide 19
19
Slide 20
20
Slide 21
21
Slide 22
22
Slide 23
23
Slide 24
24
Slide 25
25
Slide 26
26
Slide 27
27
Slide 28
28
Slide 29
29
Slide 30
30
Slide 31
31
Slide 32
32
Slide 33
33
Slide 34
34
Slide 35
35
Slide 36
36
Slide 37
37
Slide 38
38
Slide 39
39

About This Presentation

Surveying Engineering
Contour & Contouring
In this lecture we will cover
 definitions.
Characteristics of contour lines.
Contours used by Engineers .
Methods of locating contour.
Method of Interpolation Contours.
Contour & Contouring
A map showing the natural and cultural fea...


Slide Content

Erbil Polytechnic University
Technical Engineering College
Civil Engineering Department
Surveying Engineering
Contour & Contouring
1
Prepared by
Asst. Prof. Salar Khudhur Hussein
Ass. Lecturer Mr. Kamal Yaseen
Ass. Lecturer Ms. Dilveen H. Omar
2021-2022

In this lecture we will cover
definitions.
Characteristics of contour lines.
Contours used by Engineers .
Methods of locating contour.
Method of Interpolation Contours.
2

Contour & Contouring
Amapshowingthenaturalandculturalfeaturesaswell
asshowingthenatureofthesurfaceoftheland(topographyofthe
land)oftheupanddownsanditsrepresentationin(3D)three
dimensions.
Acontourisalinedrawnonaplanjoiningallpointsofthesame
heightaboveorbelowadatum.
Or
Acontourline
isalinethatpassesthroughpointshavingthesameelevation.
3

contourinterval
istheconstantverticaldistance(VD)betweenanytwo
consecutivecontoursiscalledthecontourinterval
.Thecontourintervalonthismapis20m
4

5

The choice of suitable contour interval dependson several
factors:
1-The nature of the ground surface.
2-The scale of the map.
3-The purpose of the map.
4-The area of the ground.
5-The time and cost.
6

Topographic Maps
7

1.Contour lines are continuous.
2.All points in a contour line have the same elevation .
3.Contour lines are relatively parallel.
Characteristics of contour lines
8

4-A series of closed contour lines on the map
represent a hill if the values higher inside.
9

5
10
15
(contours with increasing elevation indicates a hill).
20
25
5
10
15
20
25
10

5-A series of closed contour lines on the map
indicate a depression if the higher values are outside
11

Characteristics of contour lines continued
6-Evenly(Equal)spacedlinesindicateanareaofuniformslope.
7.Thedistancebetweencontourlinesindicatesthesteepnessof
theslope.Thegreaterdistancebetweentwocontoursindicates
lessslope.Theoppositeisalsotrue.
12

8-Contour lines cannot merge or cross one another on map
except in the case of an overhanging cliff ,cave.

Contours are used by Engineers to:
1-Construct longitudinal sections and cross-sections for initial investigation.
2-Compute volumes.
3-Construct route lines of constant gradient.
4-Draw the limits of constructed dams, roads, railways, & tunnels, etc.
5-Draw and measure drainage areas.
IF the ground is reasonably flat, the optical level can be used for contouring
using either the direct or indirect methods.
14

Methods of locating contour:-
A-The direct methods
1-Level and staff method.
2-Plan table and alidade method.
Directmethodprocedure:
Inthismethodtheactualcontourispeggedoutonthegroundandits
planimetricpositionlocated.Aback-sightistakentoanappropriateBMand
theHPCoftheinstrumentisobtained,say(34.800m.)Astaffreadingof
0.800mwouldthenplacethefootofthestaffatthe(34m)contourlevel.The
staffisthenmovedthroughouttheterrainarea,withitspositionpeggedat
every0.800mreading.Inthiswaythe34mcontourislocated.Similarlya
staffreadingof(1.800m)givesthe33mcontourandsoon.Theplanimetric
positionofthecontourneedstobelocatedusinganappropriatesurvey
technique
15

16

TBM 7.34m AOD
1.241
TBM + BS = HPC i.e. 7.34 + 1.241 = 8.581
1.241
HPC = 8.581
O.625 O.543
O.581
17

TBM 7.34m AOD
HPC = 8.581
This process is repeated until the 8m contour line is set out.
Different colour marker pins are used for each contour.
Traditional surveying methods are then used to collect the
required data to locate these contour lines on the plan.
18

B-The indirect methods:-
1-Grid method (Square method).Use Level instrument
2-Profile and Cross-section method. Use Levelinstrument
3-Tachometric method (Radial line method).
Use either theodolite or tachometry instrument
4-Plan table method.Use Alidade instrument
5-Total Station .(TS)
6-Global Navigation Satellite System (GNSS)
19

1-Grid method:-
It is used when the area to be surveyed is small and the ground
is not very slope
Steps
1-The area is divided into squares. The size of the squares
may vary from (5 –20) m depending upon the nature of the
ground and contour interval.
2-The elevation of the corners of the squares are determined
using a level and staff, starting from a (B.M).
3-The contours are drawn by (interpolation).
20

Methods of Contouring
21

B-Indirect contouring
from random spot heights
from a grid of spot heights
22

23

24

25

26

27

28

7.45 8.23
8m
R.L.(C)R.L.(L) R.L.(H)
[ R.L.(C)
-R.L.(L)]
[ R.L.(H)
-R.L.(L) ]
[ R.L.(H) -R.L.(C) ]L
x
From large triangle :
[ R.L.(H) -R.L.(L) ]
L
From small triangle :
[ R.L.(H) -R.L.(C) ]
x
=
Hence :
[ R.L.(H) -R.L.(C) ]
x =
[ R.L.(H) -R.L.(L) ]
L .
This is a
calculation
method
29

To locate the position of the 8m contour between the two points
7.45 8.23
It is 0.55m above LH point
Draw a line 55 units long, below LH point
It is 0.23m below RH point
Draw a line 23 units long, above RH point
Join the ends of these two lines
The 8m contour point is at the intersection of the two lines
8m
This is a graphical method
30

7.45 8.23
To locate the 8m
contour point
Construct a transparent overlay
7
6
5
4
3
2
1
0
1
2
3
4
5
6
7
7.45 8.23
The 8m contour line is
55 units above LH point
and 23 units below RH pt.
7
6
5
4
3
2
1
0
1
2
3
4
5
6
7
31

7.45 8.238m
This is known as an overlay method
32

33

34

1.100
2.9052.510
A
B C
Plotting contours
The RL’s for points A, B and C have been
determined by leveling. We are now
required to determine the location of the
contours using a 0.5 m contour interval.
35

Plotting contours
LINE AB
H
AB= 2.51 -1.10 = 1.410
D
AB= 10 m
1.100
2.510
A
B
A
B
1.41
10 m
1.4
9.93
For the 2.5 m contour :
D = 10*(2.5 -1.1)/1.41 = 9.93
0.9
6.38
For the 2.0 m contour :
D = 10*(2.0 -1.1)/1.41 = 6.38
0.4
2.84
For the 1.5 m contour:
D = 10*(1.5 –1.1)/1.41 = 2.84
36

Plotting contours
LINE AC
H
AC= 2.905 -1.100 = 1.805
D
AC= 14.14 m
For the 1.5 m contour :
D = 14.14*(1.5 -1.1)/1.805 = 3.13
For the 2.0 m contour :
D = 14.14*(2.0 -1.1)/1.805 = 7.05
For the 2.5 m contour :
D = 14.14*(2.5 -1.1)/1.805 = 10.97
1.100
2.9052.510
A
B C
37

Plotting contours
LINE BC
DH
BC= 2.905 -2.510 = 0.395
D
BC= 10 m
no contours cross this line
1.100
2.9052.510
A
B C
38

1.100
2.9052.510
A
B C
Plotting contours
39