AVL Tree The AVL stands for Adelson-Velskii and Landis , who are the inventors of the AVL tree.AVL tree is a self-balancing binary search tree in which heights of the left sub trees and right sub trees of any node differ by at most one.
Balancing Factor Balance factor=height of left sub tree – height of the right sub tree. The value of balance factor should always be -1, 0 or +1 .
Need for height balanced trees If the binary search tree is either left skewed or right skewed(not balanced) , the searching time will be increased. Because searching time depends upon the height of the tree. h=log(n) where h is the height of the tree and n is the number of nodes in the binary tree.It takes log(n) for searching.
Need for height balanced trees The disadvantage of a binary search tree is that its height can be as large as N-1 This means that the time needed to perform insertion and deletion and many other operations can be O(N) in the worst case We want a tree with small height A binary tree with N node has height at least Q(log N) Thus, our goal is to keep the height of a binary search tree O(log N) Such trees are called balanced binary search trees. Examples are AVL tree, red-black tree.
How to balanace AVL tree (Rotation) An insertion or deletion may cause an imbalance in an AVL tree. An AVL tree causes imbalance when any of following condition occurs: i . An insertion into Right child’s right subtree . ii. An insertion into Left child’s left subtree . iii. An insertion into Right child’s left subtree . iv. An insertion into Left child’s right subtree .
How to balanace AVL tree (Rotation) Whenever the tree becomes imbalanced due to any operation we use rotation operations to make the tree balanced. Rotation is the process of moving nodes either to left or to right to make the tree balanced.
Single Left Rotation (LL Rotation) If a tree becomes unbalanced, when a node is inserted into the right subtree of the right subtree , then we perform a single left rotation . If BF(node) = +2 and BF(node -> left-child) = +1, perform LL rotation.
Single Right Rotation (RR Rotation) AVL tree may become unbalanced, if a node is inserted in the left subtree of the left subtree . The tree then needs a right rotation. If BF(node) = -2 and BF(node -> right-child) = 1, perform RR rotation.
Left Right Rotation (LR Rotation) (Double Rotation) AVL tree may become unbalanced, if a node is inserted in the left subtree of the right subtree .The tree needs LR Rotation is a sequence of single left rotation followed by a single right rotation. If BF(node) = -2 and BF(node -> right-child) = +1, perform RL rotation .
Right Left Rotation (RL Rotation) (Double Rotation) AVL tree may become unbalanced, if a node is inserted in the right subtree of the left subtree .The tree needs The RL Rotation is sequence of single right rotation followed by single left rotation. If BF(node) = +2 and BF(node -> left-child) = -1, perform LR rotation.
node * RR(node *T) //insert right subtree of right { T= rotateleft (T); return(T); } node * LL(node *T) //insert left subtree of left { T= rotateright (T); return(T); } node * LR(node *T) // insert left subtree of right { T->left= rotateleft (T->left); T= rotateright (T); return(T); } node * RL(node *T) //insert right subtree of left { T->right= rotateright (T->right); T= rotateleft (T); return(T); }
Left Rotation Right Rotation
Left-Right Rotation
Right-Left Rotation
Operations on an AVL Tree The following operations are performed on AVL tree... Search Insertion Deletion search operation is similar to Binary search tree.
Insertion Operation in AVL Tree Step 1 - Insert the new element into the tree using Binary Search Tree insertion logic. Step 2 - After insertion, check the Balance Factor of every node. Step 3 - If the Balance Factor of every node is 0 or 1 or -1 then go for next operation. Step 4 - If the Balance Factor of any node is other than 0 or 1 or -1 then that tree is said to be imbalanced. In this case, perform suitable Rotation to make it balanced and go for next operation.
Rotating conditions If BF(node) = +2 and BF(node -> left-child) = +1, perform LL rotation. If BF(node) = -2 and BF(node -> right-child) = 1, perform RR rotation. If BF(node) = -2 and BF(node -> right-child) = +1, perform RL rotation. If BF(node) = +2 and BF(node -> left-child) = -1, perform LR rotation.
Operations on an AVL Tree The following operations are performed on AVL tree... Search Insertion Deletion search operation is similar to Binary search tree.
Deletion in AVL Trees Step 1: Find the element in the tree. Step 2: Delete the node, as per the BST Deletion. Step 3: Two cases are possible:- Case 1: Deleting from the right subtree . Case 2 : Deleting from left subtree .
Case 1: Deleting from the right subtree . 1A. If BF(node) = +2 and BF(node -> left-child) = +1, perform LL rotation. 1B. If BF(node) = +2 and BF(node -> left-child) = -1, perform LR rotation. 1C. If BF(node) = +2 and BF(node -> left-child) = 0, perform LL rotation.
Case 2 : Deleting from left subtree . 2A. If BF(node) = -2 and BF(node -> right-child) = -1, perform RR rotation. 2B. If BF(node) = -2 and BF(node -> right-child) = +1, perform RL rotation. 2C. If BF(node) = -2 and BF(node -> right-child) = 0, perform RR rotation.
AVL Tree Example: Now remove 53(leaf Node) 14 17 7 4 53 11 12 8 13
AVL Tree Example: Now remove 53, unbalanced 14 17 7 4 11 12 8 13
AVL Tree Example: Balanced! Remove 11(node with two children) 14 17 7 4 11 12 8 13
AVL Tree Example: Remove 11, replace it with the largest in its left branch tree balanced 14 17 7 4 8 12 13
AVL Tree Example: Remove 8(place with inorder predessor )replace with largest element in the left subtree , unbalanced 14 17 4 7 12 13
Applications of AVL Tree AVL trees are used for frequent insertion. It is used in Memory management subsystem of linux kernel to search memory regions of processes during preemption. Sort the following database: Dictioonary Google search engine some sites to take data faster sites which have large amount of data example is Facebook .
In Class Exercises Build an AVL tree with the following values: 15, 20, 24, 10, 13, 7, 30, 36, 25