1.2 The fundamental cell lemma 7
Example 2.1. Let S1 act on e} via βη'ψ, with nj > 0. Then, Hj — {φ = Ink/tij, k —
0,...,«/ — 1} = Z„.. Let ñj — (η \ : • · • : rij) be the largest common divisor (l.c.d.)
of n\,..., nj, then Hj = [φ = 2πk/ñj, k = 0,..., ñj — 1} = Ζf¡ . Thus, k\ = oo,
kj = ñj-i/ñj.
Note that, since Γ/Η = (T/Hi)x(Hi/H2)x---x(.Hm+r-i/H) if dim Γ/Η = k,
then there are exactly k coordinates (which have to be complex) with kj = oo. In
fact, since Hj is the isotropy subgroup for the action of Hj-\ on χy, each factor, by
Lemma 1.1, is at most one-dimensional.
Lemma 2.3. Under the above circumstances, one may reorder the coordinates in such
a way that kj = oo for j = 1,..., k and kj < oo for j > k.
Proof. Assuming k > 0, there is at least one coordinate with dim Γ/Hj = 1: if
not, Hj > T" for all j's and hence Η > Tn with \Γ/Η\ < oo. Denote by z\ this
coordinate, then Γ/Η = (Γ/Ηι)(Ηι/Η), with dim H\/H = k - 1. If Hy/H is a
finite group, i.e., k = 1, then one has a decomposition into finite groups with kj < oo
for j > 1. On the other hand, if k > 1, then, by repeating the above argument, one
has a coordinate Z2 with H\ /Hi of dimension 1. •
The following result will be used very often in the book.
Lemma 2.4. Let T" act on V = Cm via expi (Nj, Φ), j = 1,..., m. Let A be the
m χ η matrix with NJ as its j-th row. Then:
(a) dim Γ/Η = k if and only if A has rank k.
(b) Assuming kj — oo for j = 1,..., k and that the k χ k matrix Β with B¡j = nlj,
1 < i, j < k, is invertible, then one may write ΛΦ = , with Φ = Φ + ΛΦ,
where Φτ — (ΦΓ, ΦΓ) and Φτ — {ψ\,..., <pk).
(c) With the same hypothesis, there is an action ofTk on Cm, generated by ΨΓ =
(Φι,..., Φ*) such that {NJ, Φ) = (Mj, Φ), with Mj = (m[,...,m[) such
thatmj — SijMjfor j = 1k, i.e., the action of Τk on the first k coordinates
reduces to elMi*j.
Proof (a) The relation {Ν^, Φ) ξ 0, [2ττ] gives parallel hyperplanes in M" with
normal Ν i. Thus, dim Η = η — k is equivalent to dim ker A = η — k.
(b) Write A = ^ ^ and let A = B~lC. Then, Λ Φ = 0 means Φ = -AÔand
(E - DA)Φ = 0. Since dim ker A = η - k, one has E = DA, ker A = (—ΑΦ, Φ)
and ΑΦ has the form given in the lemma.
(c) Let M be a k χ k diagonal matrix such that B~x M has integer entries. Define
Φ = Then, ΑΦ = Qß-'ΜΨ = (ο^Μα/ψ) 8ives the action of Tonce
one has noticed that the entries of DB~l M are integers. •