1. What quantity describes the length of the actual paths traveled by an object? A. acceleration B. distance C. displacement D. velocity
1. What quantity describes the length of the actual paths traveled by an object? A. acceleration B. distance C. displacement D. velocity
2. What quantity describes the length and direction of the change in position measured from the starting point? A. acceleration B. distance C. displacement D. velocity
3. What quantity describes the rate of change in displacement over the elapsed time? A. acceleration B. distance C. displacement D. velocity
4. What quantity describes the rate of change in velocity over the elapsed time? A. acceleration B. distance C. displacement D. velocity
5. What device is used to measure the speed of a moving object at any given instant? A. anemometer B. barometer C. speedometer D. thermometer
6. A car is moving at a uniform speed that travels a distance of 500 cm in 10 seconds. What is the average speed of the car? A. 0.5 m/s B. 0.5 m/s 2 C. 50 m/s D. 50 m/s 2
7. How long will it take for a man to cover a distance of 30 m having a speed of 5m/s? A. 0.17 s B. 5.0 s C. 6.0 s D. 150 s
For numbers 8-10, refer to the situation below. The speedometer of a car moving east reads 70 km/h. It passes another car that travels west at 70 km/h.
The speedometer of a car moving east reads 70 km/h. It passes another car that travels west at 70 km/h. 8. What can be inferred about the speed of the car? A. The car is not moving B. The carās speed is constant C. The carās speed is increasing D. The carās speed is decreasing
The speedometer of a car moving east reads 70 km/h. It passes another car that travels west at 70 km/h. 9. What can be inferred about the velocity of the car? A. The velocity of the car remains the same B. The velocity of the car is increasing from east to west C. The velocity of the car is decreasing from east to west D. The velocity of the car is not the same from east to west
For numbers 10-12, refer to the problem below. A car travels 27 km due east, then does a U-turn, and travels 33 km due west.
A car travels 27 km due east, then does a U-turn, and travels 33 km due west. 10. What is the total distance covered by the car? A. 27 m B. 33 m C. 60 m D. 65 m
A car travels 27 km due east, then does a U-turn, and travels 33 km due west. 11. What is the displacement of the car? A. 6 m due east B. 6 m due west C. 6 m due north D. 6 m due south
A car travels 27 km due east, then does a U-turn, and travels 33 km due west. 12. What is the average speed of the car, if the entire trip took 2.0 hours? A. 8.0 x 10 -2 m/s B. 8.0 x 10 -3 m/s C. 8.0 x 10 -4 m/s D. 8.0 x 10 -5 m/s
For numbers 13-15, refer to the problem below. A car was initially moving at 17.0 m/s. After 3.0 s, it was observed to be moving at 5.0 m/s.
A car was initially moving at 17.0 m/s. After 3.0 s, it was observed to be moving at 5.0 m/s. 13. What is the acceleration of the car? A. -4.0 m/s B. -5.0 m/s C. 4.5 m/s D. 5.0 m/s
A car was initially moving at 17.0 m/s. After 3.0 s, it was observed to be moving at 5.0 m/s. 14. Which of the following will be the velocity-time table of the car?
A car was initially moving at 17.0 m/s. After 3.0 s, it was observed to be moving at 5.0 m/s. 15. Based from your answer in no. 14, what conclusion can be drawn about the velocity-time table of the car? a. The acceleration is positive. From the table, the velocity of the car increased by 4.0 m/s after every second. b. The acceleration is negative. From the table, the velocity of the car increased by 4.0 m/s after every second. c. The acceleration is negative. From the table, the velocity of the car decreased by 4.0 m/s after every second. d. The acceleration is positive. From the table, the speed of the car increased by 4.0 m/s after every second.
Position-Time and Velocity-Time Graphs
Questions for Consideration What is a position-time graph? What is a velocity-time graph? How do features on one graph translate into features on the other?
Distance-Time Graphs Show an objectās position as a function of time. x-axis: time y-axis: distance
Distance-Time Graphs Imagine a ball rolling along a table, illuminated by a strobe light every second. You can plot the ballās position as a function of time. 0 s 1 s 2 s 3 s 4 s 5 s 6 s 7 s 8 s 9 s 10 s
Distance-Time Graphs What are the characteristics of this graph? Straight line, upward slope What kind of motion created this graph? Constant speed 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 time (s) position (cm)
Distance-Time Graphs Each type of motion has a characteristic shape on a D-T graph. Constant speed Zero speed (at rest) Accelerating (speeding up) Decelerating (slowing down)
Distance-Time Graphs Constant speed is represented by a straight segment on the D-T graph. time (s) pos. (m) Constant speed in positive direction. time (s) pos. (m) Constant speed in negative direction.
Distance-Time Graphs Constant speed is represented by a straight segment on the D-T graph. time (s) pos. (m) A horizontal segment means the object is at rest.
Distance-Time Graphs Curved segments on the D-T graph mean the objectās speed is changing. time (s) pos. (m) Speeding up in positive direction. time (s) pos. (m) Speeding up in negative direction.
Distance-Time Graphs Curved segments on the D-T graph mean the objectās speed is changing. time (s) pos. (m) Traveling in positive direction, but slowing down. time (s) pos. (m) Traveling in negative direction, but slowing down.
Distance-Time Graphs The slope of a D-T graph is equal to the objectās velocity in that segment. time (s) position (m) 10 20 30 40 10 20 30 40 50 slope = change in y change in x slope = (30 m ā 10 m) (30 s ā 0 s) slope = (20 m) (30 s) slope = 0.67 m/s
Distance-Time Graphs The following D-T graph corresponds to an object moving back and forth along a straight path. Can you describe its movement based on the graph? time (s) position (m) N S
Velocity-Time Graphs A velocity-time (V-T) graph shows an objectās velocity as a function of time. A horizontal line = constant velocity. A straight sloped line = constant acceleration. Acceleration = change in velocity over time. Positive slope = positive acceleration. Not necessarily speeding up! Negative slope = negative acceleration. Not necessarily slowing down!
Velocity-Time Graphs A horizontal line on the V-T graph means constant velocity. time (s) velocity (m/s) N S Object is moving at a constant velocity North.
Velocity-Time Graphs A horizontal line on the V-T graph means constant velocity. time (s) velocity (m/s) N S Object is moving at a constant velocity South.
Velocity-Time Graphs If an object isnāt moving, its velocity is zero. time (s) velocity (m/s) N S Object is at rest
Velocity-Time Graphs If the V-T line has a positive slope, the object is undergoing acceleration in positive direction. If v is positive also, object is speeding up. If v is negative, object is slowing down.
Velocity-Time Graphs V-T graph has positive slope. time (s) velocity (m/s) N S Positive velocity and positive acceleration: object is speeding up! time (s) velocity (m/s) N S Negative velocity and positive acceleration: object is slowing down.
Velocity-Time Graphs If the V-T line has a negative slope, the object is undergoing acceleration in the negative direction. If v is positive, the object is slowing down. If v is negative also, the object is speeding up.
Velocity-Time Graphs V-T graph has negative slope. time (s) velocity (m/s) N S Positive velocity and negative acceleration: object is slowing down, time (s) velocity (m/s) N S Negative velocity and negative acceleration: object is speeding up! (in negative direction)
If the displacement of the particle varies with respect to time and is given as (6t 2 Ā + 2t + 4) m, the instantaneous velocity can be found out at any given time by: s = (6t 2 Ā + 2t + 4)
velocity (v) = = = Ā
So, if we have to find out the instantaneous velocity at t = 5 sec, then we will put the value of t in the obtained expression of velocity. Instantaneous velocity at t = 5 sec = (12Ć5 + 2) = 62 m/s
Let us calculate the average velocity now for 5 seconds now. Displacement = (6Ć5 2 Ā + 2Ć5 + 4) = 164 m
Let us calculate the average velocity now for 5 seconds now. d isplacement = (6Ć5 2 Ā + 2Ć5 + 4) = 164 m average velocity = 164m/5s =32.8 m/s
ASSESSMENT
1. What quantity describes the slope of any nonvertical line in a position-time graph? A. acceleration B. displacement C. speed D. velocity
2. What can be inferred about the velocity in position-time graph if the graph is a horizontal line? A. the body is at rest B. the body is accelerating C. the body is decelerating D. the body is constantly moving
3. What conclusion can be drawn in a position-time graph if the slope is steep? A. the body indicates a faster speed B. the body indicates a slower speed C. the body indicates a faster velocity D. the body indicates a slower displacement
4. What quantity describes the slope of any nonvertical line in a velocity-time graph? A. acceleration B. distance C. speed D. velocity
5. In an acceleration-time graph, what can be inferred when a body has a uniform acceleration? A. The acceleration-time graph is a vertical line to the y-axis. B. The acceleration-time graph is a line parallel to the x-axis. C. The acceleration-time graph is a line parallel to the y-axis. D. The acceleration-time graph is a diagonal line to the x-axis.
6. Which of the following graphs represents a body at rest in a position-time graph?
7. Which of the following graphs represents a uniform acceleration in an acceleration-time graph?
8. What quantity indicates the rise of the slope in a position-time graph? A. acceleration B. displacement C. speed D. velocity
9. What indicates the area in an acceleration-time graph? A. change in speed of the object B. change in time of the object C. change in velocity of the object D. change in distance of the object
For numbers 10-13, refer to the figure. Ford started walking at time zero and walked 6m for 3 seconds at a constant velocity. He then stayed still (at 6m) for 2 seconds (between 3-5 secs). He then walked back 3m (to the 3m mark) in the opposite direction for 3 seconds. Finally, he stood still for 2 seconds (between 8-10 secs).
10. Based from the figure, what can be observed about the velocity of Ford during his first three seconds? A. His average velocity is 1 m/s. B. His average velocity is 2 m/s. C. His average velocity is 3 m/s. D. His average velocity is 4 m/s.
11. What conclusion can be drawn about the movement of Ford during his 3-5 and 8-10 seconds movement? I. constant speed, II. faster speed, III. body at rest, IV. zero velocity A. III only B. II and IV C. III and IV D. I, III, and IV
12. What can be inferred about the slope of Ford during his 5-8 seconds movement? A. accelerating speed B. accelerating velocity C. negative slope D. positive slope
13. If Ford happens to go back to his origin after 10 seconds. What is the total displacement of Ford? A. 0 m B. 3m C. 6 m D. 8 m
For numbers 14-15, refer to the figure below.
14. Which best describes the figure above? A. The object is at rest. B. The object is moving with uniform acceleration. C. The object is moving toward the origin with constant velocity. D. The object is moving away from the origin with constant velocity.
15. What conclusion can be derived from the figure above? A. The velocity of the object is positive B. The velocity of the object is negative C. The acceleration of the object is positive. D. The acceleration of the object is negative.
Question: Imagine you are on top of a 10-storey building and were ask to throw down 2 things. Which would reach the ground first, the elephant or the small tennis ball? Why?
GALILEAN CONCEPTS OF MOTION Aristotelian Galilean vertical motion All objects, no matter how heavy or how light they are, fall to the ground with the same acceleration (9.8 m/s 2 ) which is due to gravity . gravity or free fall constant acceleration (9.8 m/s 2) Any object tossed upward will surely fall back to the ground due to the Earthās gravitational force.
A ball is thrown upward with an initial velocity of 40.0 m/s. Compute: a) The time to reach the maximum height b) Maximum height reached. c) Total time of flight d) Return velocity
A ball is thrown upward with an initial velocity of 40.0 m/s. Compute:
QUESTIONS
1. An airplane accelerates down a runway at 3.20 m/s 2 Ā for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff.
2. A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car.
3. Upton Chuck is riding the Giant Drop at Great America. If Upton free falls for 2.60 seconds, what will be his final velocity and how far will he fall?
4. A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled.
5. A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s 2 . Determine the time for the feather to fall to the surface of the moon.
6. Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated to a speed of 444 m/s in 1.83 seconds, then what is the acceleration and what is the distance that the sled travels?
7. A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike.
8. An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s 2 . The takeoff speed for this plane will be 65 m/s. Assuming this minimum acceleration, what is the minimum allowed length for the runway?
9. A car traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car (assume uniform acceleration).
10. A kangaroo is capable of jumping to a height of 2.62 m. Determine the takeoff speed of the kangaroo
11. If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)?
12. A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a uniform acceleration).
13. A baseball is popped straight up into the air and has a hang-time of 6.25 s. Determine the height to which the ball rises before it reaches its peak. (Hint: the time to rise to the peak is one-half the total hang-time.)
14. The observation deck of tall skyscraper 370 m above the street. Determine the time required for a penny to free fall from the deck to the street below.
15. A bullet is moving at a speed of 367 m/s when it embeds into a lump of moist clay. The bullet penetrates for a distance of 0.0621 m. Determine the acceleration of the bullet while moving into the clay. (Assume a uniform acceleration.)
16. A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.
17. It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s 2 , determine the speed of the Jaguar before it began to skid.
18. A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed.
19. A dragster accelerates to a speed of 112 m/s over a distance of 398 m. Determine the acceleration (assume uniform) of the dragster.
20. With what speed in miles/ hr (1 m/s = 2.23 mi/ hr ) must an object be thrown to reach a height of 91.5 m (equivalent to one football field)? Assume negligible air resistance.
ANSWERS
1. An airplane accelerates down a runway at 3.20 m/s 2 Ā for 32.8 s until is finally lifts off the ground. Determine the distance traveled before takeoff. d = v i t + 0.5at 2 d = (0 m/s)(32.8 s)+ 0.5(3.20 m/s 2 )(32.8 s) 2 d = 1720 m
2. A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Determine the acceleration of the car. d = v i t + 0.5at 2 110 m = (0 m/s)(5.21 s)+ 0.5(a)(5.21 s) 2 110 m = (13.57 s 2 )a a = (110 m)/(13.57 s 2 ) a = 8.10 m/ s 2
3. Upton Chuck is riding the Giant Drop at Great America. If Upton free falls for 2.60 seconds, what will be his final velocity and how far will he fall? d = v i t + 0.5at 2 d = (0 m/s)(2.60 s)+ 0.5(-9.8 m/s 2 )(2.60 s) 2 d = -33.1 m (- indicates direction) 33.1 m downward v f Ā = v i Ā + at v f Ā = 0 + (-9.8 m/s 2 )(2.60 s) v f Ā = -25.5 m/s (- indicates direction) 25 .1 m/s downward
4. A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance traveled. a = ( v f - v i )/t a = (46.1 m/s - 18.5 m/s)/(2.47 s) a = 11.2 m/s 2 d = v i t + 0.5at 2 d = (18.5 m/s)(2.47 s)+ 0.5(11.2 m/s 2 )(2.47 s) 2 d = 45.7 m + 34.1 m d = 79.8 m (Note: the d can also be calculated using the equation v f 2 Ā = v i 2 Ā + 2ad)
5. A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s 2 . Determine the time for the feather to fall to the surface of the moon. d = v i t + 0.5at 2 -1.40 m = (0 m/s)(t)+ 0.5(-1.67 m/s 2 )(t) 2 -1.40 m = 0+ (-0.835 m/s 2 )(t) 2 (-1.40 m)/(-0.835 m/s 2 ) = t 2 1.68 s 2 Ā = t 2 t = 1.29 s
6. Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated to a speed of 444 m/s in 1.83 seconds, then what is the acceleration and what is the distance that the sled travels? a = ( v f - v i )/t a = (444 m/s - 0 m/s)/(1.83 s) a = 243 m/s 2 d = v i t + 0.5at 2 d = (0 m/s)(1.83 s)+ 0.5(243 m/s 2 )(1.83 s) 2 d = 0 m + 406 m d = 406 m
7. A bike accelerates uniformly from rest to a speed of 7.10 m/s over a distance of 35.4 m. Determine the acceleration of the bike. v f 2 Ā = v i 2 Ā + 2ad (7.10 m/s) 2 Ā = (0 m/s) 2 Ā + 2(a)(35.4 m) 50.4 m 2 /s 2 Ā = (0 m/s) 2 Ā + (70.8 m)a (50.4 m 2 /s 2 )/(70.8 m) = a a = 0.712 m/s 2
8. An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s 2 . The takeoff speed for this plane will be 65 m/s. Assuming this minimum acceleration, what is the minimum allowed length for the runway? v f 2 Ā = v i 2 Ā + 2ad (65 m/s) 2 Ā = (0 m/s) 2 Ā + 2(3 m/s 2 )d 4225 m 2 /s 2 Ā = (0 m/s) 2 Ā + (6 m/s 2 )d (4225 m 2 /s 2 )/(6 m/s 2 ) = d d = 704 m
9. A car traveling at 22.4 m/s skids to a stop in 2.55 s. Determine the skidding distance of the car (assume uniform acceleration). d = [(v i Ā + v f )/2]t d = [(22.4 m/s + 0 m/s)/2] 2.55 s d = (11.2 m/s)(2.55 s) d = 28.6 m
10. A kangaroo is capable of jumping to a height of 2.62 m. Determine the takeoff speed of the kangaroo v f 2 Ā = v i 2 Ā + 2ad (0 m/s) 2 Ā = v i 2 Ā + 2(-9.8 m/s 2 )(2.62 m) 0 m 2 /s 2 Ā = v i 2 Ā - 51.35 m 2 /s 2 51.35 m 2 /s 2 Ā = v i 2 v i Ā = 7.17 m/s
11. If Michael Jordan has a vertical leap of 1.29 m, then what is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)? v f 2 Ā = v i 2 Ā + 2ad (0 m/s) 2 Ā = v i 2 Ā + 2(-9.8 m/s 2 )(1.29 m) 0 m 2 /s 2 Ā = v i 2 Ā - 25.28 m 2 /s 2 25.28 m 2 /s 2 Ā = v i 2 v i Ā = 5.03 m/s To find hang time, find the time to the peak and then double it. v f Ā = v i Ā + at 0 m/s = 5.03 m/s + (-9.8 m/s 2 )t up -5.03 m/s = (-9.8 m/s 2 )t up (-5.03 m/s)/(-9.8 m/s 2 ) = t up t up Ā = 0.513 s hang time = 1.03 s
12. A bullet leaves a rifle with a muzzle velocity of 521 m/s. While accelerating through the barrel of the rifle, the bullet moves a distance of 0.840 m. Determine the acceleration of the bullet (assume a uniform acceleration). v f 2 Ā = v i 2 Ā + 2ad (521 m/s) 2 Ā = (0 m/s) 2 Ā + 2(a)(0.840 m) 271441 m 2 /s 2 Ā = (0 m/s) 2 Ā + (1.68 m)a (271441 m 2 /s 2 )/(1.68 m) = a a = 1.62 x 10 5 Ā m /s 2
13. A baseball is popped straight up into the air and has a hang-time of 6.25 s. Determine the height to which the ball rises before it reaches its peak. (Hint: the time to rise to the peak is one-half the total hang-time.) (NOTE: the time required to move to the peak of the trajectory is one-half the total hang time - 3.125 s.) First use:Ā v f Ā = v i Ā + a*t 0 m/s = v i Ā + (-9.8Ā m/s 2 )*(3.13 s) 0 m/s = v i Ā - 30.7 m/s v i Ā = 30.7 m/s Ā (30.674 m/s) Now use:Ā v f 2 Ā = v i 2 Ā + 2ad (0 m/s) 2 Ā = (30.7 m/s) 2 Ā + 2(-9.8Ā m/s 2 )(d) 0 m 2 /s 2 Ā = (940 m 2 /s 2 ) + (-19.6Ā m/s 2 )d -940Ā m 2 /s 2 Ā = (-19.6Ā m/s 2 )d (-940Ā m 2 /s 2 )/(-19.6Ā m/s 2 ) = d d = 48.0 m
14. The observation deck of tall skyscraper 370 m above the street. Determine the time required for a penny to free fall from the deck to the street below. d = v i t + 0.5at 2 -370 m = (0 m/s)(t)+ 0.5(-9.8 m/s 2 )(t) 2 -370 m = 0+ (-4.9 m/s 2 )(t) 2 (-370 m)/(-4.9 m/s 2 ) = t 2 75.5 s 2 Ā = t 2 t = 8.69 s
15. A bullet is moving at a speed of 367 m/s when it embeds into a lump of moist clay. The bullet penetrates for a distance of 0.0621 m. Determine the acceleration of the bullet while moving into the clay. (Assume a uniform acceleration.)
16. A stone is dropped into a deep well and is heard to hit the water 3.41 s after being dropped. Determine the depth of the well.
17. It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar skidded to a stop with a constant acceleration of -3.90 m/s 2 , determine the speed of the Jaguar before it began to skid.
18. A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Determine the acceleration of the plane and the time required to reach this speed.
19. A dragster accelerates to a speed of 112 m/s over a distance of 398 m. Determine the acceleration (assume uniform) of the dragster.
20. With what speed in miles/ hr (1 m/s = 2.23 mi/ hr ) must an object be thrown to reach a height of 91.5 m (equivalent to one football field)? Assume negligible air resistance.
ASSESSMENT
1. Which of the following quantities is an example of uniformly accelerated motion in one dimension? A. free fall B. momentum C. projectile motion D. uniform circular motion
2. What type of motion is being shown when you dropped an object from a certain height and gravity was acting on it? A. free fall B. momentum C. projectile motion D. uniform circular motion
3. A stone is thrown straight up. What is itās acceleration on the way up? A. -10.80 m/s 2 B. -9.80 m/s 2 C. 9.80 m/s 2 D. +10.80 m/s 2
4. What happens to the velocity of a ball as it is dropped off a cliff? A. It is constant B. It decreases at a uniform rate C. It increases at a uniform rate D. It increases at non-uniform rate
5. What is the value of āgā or acceleration due to gravity? A. 6.80 m/s 2 B. 7.80 m/s 2 C. 9.80 m/s 2 D. 10.80 m/s 2
6. What causes some bodies to fall faster than others even though they have the same mass? A. air resistance B. gravity of the earth C. heat D. velocity of the body
For numbers 7-10, refer to the following problem: A ball is thrown upward with an initial velocity.
A ball is thrown upward with an initial velocity. 7. Which of the following becomes zero when the ball reaches its maximum height? A. acceleration B. displacement C. time D. velocity
A ball is thrown upward with an initial velocity. 8. Which of the following becomes zero when the ball returns to its origin? A. acceleration B. displacement C. time D. velocity
A ball is thrown upward with an initial velocity. 9. How would you compare the time it took the ball to go up with the time it took the ball to go down? A. equal B. greater than C. insufficient data D. less than
A ball is thrown upward with an initial velocity. 10. The ball returns to its origin after 3.0 s. How long will take for the ball to reach the maximum height from the ground? A. 1.5 s B. 2.0 s C. 3.0 s D. 6.0 s
11. A bus started from rest and moved with uniform acceleration. It acquired a velocity of 60m/s after 100 seconds. Find the acceleration of the bus. a. 0.6 m/s 2 b. 1.0 m/s 2 c. 2.6 m/s 2 d. 3.0 m/s 2
12. A man is driving down a street at 55 km/h. Suddenly, a child runs into the street. If it takes the man 0.75 s to react and apply the brakes, how many meters the man will travel before he begins to slow down? A. 0.0058 m B. 5.8 m C. 15.8 m D. 57.8 m
13. A stone was dropped from rest from the top of a building and took 10 seconds to hit the ground. What is the final velocity of the stone? A. -98 m/s B. -100 m/s C. 98 m/s D. 100 m/s
14. A tricycle is parked in a terminal. Suddenly, it accelerated at 2m/s 2 for 5s. How far did the tricycle move? A. 10 m B. 15 m C. 20 m D. 25 m
15. You are walking in Paris alongside the Eiffel Tower and suddenly a coin smacks you on the head and knocks you to the ground. If it takes 30.0 seconds the coin tagged you in the head. Neglecting air resistance, how high is the Eiffel Tower? A. 4,000 m B. 4,410 m C. 5,000 m D. 5,410 m