TAIBAH UNIVERSITY Faculty of Science Department of Math. جامعة طيبة كلية العلوم قسم الرياضيات Probability and Statistics for Engineers STAT 301 Teacher : Osama Hosam Second Semester 1432/1433
Mathematical Expectation Lesson 6
Mean of a Random Variable
Mean of a Random Variable Definition 4.1: Let X be a random variable with a probability distribution f(x) . The mean (or expected value) of X is denoted by (or E(X) ) and is defined by:
Mean of a Random Variable (Example1) A shipment of 8 similar microcomputers to a retail outlet contains 3 that are defective. If a school makes a random purchase of 2 of these computers, find the expected number of defective computers purchased
The prob. distribution of X is (see Lesson 15) x 1 2 Total f(x)= P(X=x) Hypergeometric Distribution 1.00 Mean of a Random Variable (Example1)
The expected value of the number of defective computers purchased is the mean (or the expected value) of X , which is: (computers) Mean of a Random Variable (Example1)
Mean of a Random Variable (Ex 4.3) Let X be a continuous random variable that represents the life (in hours) of a certain electronic device. The pdf of X is given by: Find the expected life of this type of devices.
Solution: (hours) Therefore, we expect this type of electronic devices to last, on average, 200 hours.
Mean of a Random Variable Let X be a random variable with a prob. distribution f(x ) , and let g(X ) be a function of the random variable X . The mean (or expected value) of the random variable g(X ) is denoted by (or ) and is defined by: Theorem 4.1:
Mean of a Random Variable (Example 3) Let X be a discrete random variable with the following probability distribution x 1 2 f(x) Find:
Mean of a Random Variable (Example 3) Solution
Mean of a Random Variable (Example4) Let X be a continuous random variable that represents the life (in hours) of a certain electronic device. The pdf of X is given by: Find
Mean of a Random Variable (Example 4) Solution
Mean of a Random Variable (Ex. 4.5) Let X be a random variable with density function Find
Mean of a Random Variable (Ex4.5) Solution
Exercises
Variance
Variance of a Random Variable In Figure 4.1 we have the histograms of two discrete probability distributions with the same mean = 2 that differ considerably in the variability or dispersion of their observations about the mean. Figure 4.1 Distributions with equal means and unequal dispersions.
Variance of a Random Variables The most important measure of variability of a random variable X is called the variance of X and is denoted by Var (X) or
Variance of a Random Variables Let X be a random variable with a probability distribution f(x) and mean . The variance of X is defined by: Definition 4.3:
Variance of a Random Variable Definition : The positive square root of the variance of X , ,is called the standard deviation of X Note:
Variance of a Random Variable (Ex 4.8) Let the random variable X represent the number of automobiles that are used for official business purposes on any given workday. The probability distribution for company A [ Figure 4.1(a )] is x 1 2 3 f(x) 0.3 0.4 0.3
Variance of a Random Variables(Ex 4.8) For company B [ Figure 4.1(b )] is x 1 2 3 4 f(x) 0.2 0.1 0.3 0.3 0.1 Show that the variance of the probability dist. for company B is greater than that of company A.
Variance of a Random Variables(Ex 4.8) Solution: For company A we find that:
Variance of a Random Variables(Ex 4.8) For company B we find that:
Variance of a Random Variables(Ex 4.8) Clearly, the variance of the number of automobiles that are used for official business purposes is greater for company B than for company A.
Variance of a Random Variables The variance of a random variable X is Theorem 4.2:
Variance of a Random Variable For the discrete case we can write: Proof:
Let X be a discrete random variable with the following probability distribution x 1 2 3 f(x) 0.15 0.38 0.10 0.01 Find Var (X) . Variance of a Random Variables(Ex 4.9)
Variance of a Random Variables(Ex 4.8) Solution: =0.87 (0.61) 2 = 0.4979
The weekly demand for Pepsi, in thousands of liters , from a local chain of efficiency stores, is a continuous random variable X having the probability density Find the mean and variance of X . Variance of a Random Variable (Ex 4.10)
Variance of a Random Variables(Ex 4.10) Solution:
Mean of a Random Variable Let X be a random variable with a prob. distribution f(x ), and let g(X ) be a function of the random variable X . The variance of the random variable g(X ) is : Theorem 4.3:
Calculate the variance of g(X) = 2X +3 where X be a discrete random variable with the following probability distribution x 1 2 3 f(x) 0.25 0.125 0.5 0.125 Variance of a Random Variables(Ex 4.11)
Solution Variance of a Random Variables(Ex 4.11) 2x+3 3 5 7 9 f(x) 0.25 0.125 0.5 0.125 First let us find the mean of the random variable 2X +3
Variance of a Random Variables(Ex 4.11) 4x 2 -12x+9 9 1 1 9 f(x) 0.25 0.125 0.5 0.125
Variance of a Random Variable If we use Theorem 4.2 we will get the same answer:
Variance of a Random Variables(Ex 4.11) 4x 2 +12x+9 9 25 49 81 f(x) 0.25 0.125 0.5 0.125
Exercise
Means and Variances of Linear Combinations of Random Variables
If X 1 , X 2 , …, X n are n random variables and a 1 , a 2 , …, a n are constants, then the random variable : is called a linear combination of the random variables X 1 ,X 2 ,…, X n . Linear Combination of random variables
If X is a random variable with mean =E(X ), and if a and b are constants, then: E( aXb ) = a E(X) b aXb = a X ± b Theorem 4.5: Linear Combination of random variables
Setting a = 0 in Theorem 4.5 , we see that E(b) = b . Corollary 4.1: Corollary 4.2: Setting b = 0 in Theorem 4.5 , we see that E( aX ) = aE (X) . Linear Combination of random variables
Let X be a random variable with the following probability density function: Find E(4X+3). Linear Combination of r.v . Example 4.16
Solution: 5/4 Linear Combination of r.v . Example 4.16 E(4X+3) = 4 E(X)+3 = 4(5/4) + 3 =8
Linear Combination of r.v . Example 4.16 Another solution: ; g(X) = 4X+3 E(4 X +3) =
If X 1 , X 2 , …, X n are n random variables and a 1 , a 2 , …, a n are constants, then: E(a 1 X 1 +a 2 X 2 + … + a n X n ) = a 1 E(X 1 )+ a 2 E(X 2 )+ …+ a n E ( X n ) Theorem : Linear Combination of random variables
Corollary : Linear Combination of random variables If X , and Y are random variables, then: E(X ± Y) = E(X) ± E(Y)
Linear Combination of random variables Theorem 4.9 : If X is a random variable with variance and if a and b are constants, then:
Setting a = 1 in Theorem 4.9 , we see that Corollary 4.6: Corollary 4.7: Setting b = 0 in Theorem 4.9 , we see that Linear Combination of random variables
If X 1 , X 2 , …, X n are n independent random variables and a 1 , a 2 , …, a n are constants, then: Theorem : Linear Combination of random variables
If X, and Y are independent random variables, then:· Corollary : Linear Combination of random variables
Linear Combination of r.v . (EX 4.20) If X, and Y are independent random variables, with . Find the variance of the random variable
Solution: Linear Combination of r.v . (EX 4.20)
If X, and Y are independent random variables, with . Linear Combination of r.v . (Example) Find: