nelson-demo-solving-radical-equation-oct-25 (2).ppt

aclarete25 3 views 61 slides Sep 16, 2025
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About This Presentation

Performance in Mathematics 9 reflects students' understanding of algebra, geometry, and basic statistics. It indicates their ability to solve problems, apply mathematical concepts, and think logically. Strong performance demonstrates mastery of key skills, while poor performance may highlight ga...


Slide Content

ELICIT

ENGAGE

Activity 1: GUESS THE JUMBLED LETTERS!
Directions:
a. A student will arrange the jumbled letters by saying
the word.

b. The time given will be 15 seconds for every word.


c. The first student who will answer the jumbled letters
within the given time will get the point.

E P O R W
POWER
1.
123456789101112131415

R L A A D C I
RADICAL
2.
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G N I V L O S
SOLVING
3.
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T O O R S
ROOTS
4.
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E S Q N U O A I T
EQUATIONS
5.
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E R A U Q S
O T O R
SQUARE ROOT
6.
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E V A L B R I A
VARIABLE
7.
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E X S T R U A O E N
EXTRANEOUS
8.
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R L A I E N
LINEAR
9.
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U T L I N O S O
SOLUTION
10.
123456789101112131415

JOB WELL
DONE!!!!!

Prepared by:
Mr. Nelson R. Tumala Jr.
Mathematics Teacher

OBJECTIVES:
At the end of the period,
a. I can solve equations containing
one radical
b.I can apply the principle of
powers in solving radical
c.I can discuss the importance of
teamwork in doing the activity

EXPLORE

Activity 2: WHO AM I?
Directions:
a.The class will be divided into FIVE groups.
Groups A - E
b. The teacher will give nine squares for every group
that contains expressions, linear equations, and
principle of powers.
c. The given can be solved mentally.


d. Every group must form a 3 by 3 square wherein the
sides of the squares must be equal to each other.

32
x + 5 = 10
x=5
10x + 8 = -12
x=-2
x = -10
6
2
5
x

+
2
=
-
8
X
2

+

1
0
x

-
1
0


5
x


6
=

9
x
=
-
1
0


X
=

1

3x + 10 = 2x + 12
x = -5
x = 2
(x + 5)
2
x
2
+ 10x + 10
1
0

0
0
0
2
5
-
5
x

=

2
0
6
4
1
0
5
3

3

3
x
2
+ 10x + 25
(9)
2
8x + 12 = 20
81
(10x)
2
X
=

3
8
x

+

2
0

=

7
x

+

1
0

1
0
x

=
1
0
2
6
1
0
0

0
0
0
2
7
x
2
- 10x + 25
(x - 5)
2

32
3x + 10 = 2x + 12
(9)
2
x = -5
x + 5 = 10
8x + 12 = 20
x=5 81 x = 2
10x + 8 = -12 (x + 5)
2
x=-2
x = -10 (10x)
2
x
2
+ 10x + 10
6
2
5
x

+
2
=
-
8
X
2

+

1
0
x

-
1
0


1
0

0
0
0
2
5
-
5
x

=

2
0
5
x


6
=

9
X
=

3
8
x

+
2
0
=
7
x
+
1
0

1
0
x

=
1
0
x
=
-
1
0


X
=

1


2
6
1
0
0

0
0
0
2
7
6
4
1
0
5
3

3

3
x
2
+ 10x + 25
x
2
- 10x + 25
(x - 5)
2

Activity 3:
REMEMBER ME THIS WAY!
Directions:
The teacher will post the given
equation/expression on the board
then the students will classify the
following given as radical
expression or radical equation.

5x
105x
52x
102x
25
2
x
25
2
x
10010
2
x
32
3
x
3
4
x
5 5
32x
33
812  xx
3
12x

Radical expressions Radical equations
25
2
x
52x
5x
33
812  xx
5 5
32x
3
12x
105x
10010
2
x
102x
3
4
x
25
2
x
32
3
x

TUNE: I LOVE MATH
MATHEMATICS(2X)
I LOVE MATH(2X)
IT IS SO EXCITING
VERY INTERESTING
I LOVE MATH(2X)

TUNE: I LOVE MATH
RADICAL EQUATION(2X)
AN EQUATION(2X)
CONTAINING RADICAL
EXPRESSIONS
WITH EQUAL SIGN(2X).

Activity 4:
AGREE OR DISAGREE!
Directions:
a. Read each statement under the column
STATEMENT then write A if you agree
with the statement; otherwise, write D.
Write your answer on the “Response-
Before-the-Discussion” column.

Response-
Before-
the-
Discussion
STATEMENT
Response-
After-the-
Discussion
The value of is 9x
2
.
In the equation the value of x
is 32.
The value of x in the equation
is 8.
The value of x in the equation
is -5.
The value of x in the equation
is 25.
Anticipation-Reaction Guide
2
)3(x
82x
312 x
7335  xx
642 x

EXPLAIN

Activity 5:
JUST GIVE ME A REASON!
Directions:
The students will give their reason
by citing the concept/process/law
used to simplify the given radical
equations.

5x
22
)5()( x
25x
1. Solve for the value of x:
Why?

5x
22
)5()( x
25x
1. Solve for the value of x:
:Checking
5x
525
55
?
?

2. Solve for the value of x:
633 x
363 x
93x
22
)9()3( x
9x
819x
9
81
9
9

x
Why?

2. Solve for the value of x:
633 x
363 x
93x
22
)9()3( x
9x
:Checking
633 x
6393 
639
63)3(3 
66
819x
9
81
9
9

x
?
?
?
?

3. Solve for the value of x:
132 x
22
)1()32( x
132 x
312 x
22x
2
2
2
2

x
1x
Why?

3. Solve for the value of x:
132 x
:Checking
11
22
)1()32( x
132 x
312 x
22x
2
2
2
2

x
1x
132 x
13)1(2 
132
11
?
?
?
?

4. Solve for the value of x:
7x
35  xx
22
)3()5(  xx
32510
2
 xxx
02811
2
xx
0)4)(7( xx
4x
Why?

4. Solve for the value of x:
:Checking
7x
35  xx
22
)3()5(  xx
22
32510
2
 xxx
02811
2
xx
0)4)(7( xx
4x
35  xx
If x = 7
3)7(5)7( 
42
?
?
?

4. Solve for the value of x:
:Checking
7x
35  xx
22
)3()5(  xx
11
32510
2
 xxx
02811
2
xx
0)4)(7( xx
4x
35  xx
If x = 4
3)4(5)4( 
11
Extraneous root
?
?
?

ELABORATE

COLLABORATIVE
WORK

Category 4 3 2 1
Working with
others
Score: ____
Almost always
listen to, share
with, and supports
the efforts of
others. Tries to
keep people
working well
together.
Usually listens to,
share with, and
support the efforts
of others. Does
not cause "waves”
in the group.
Often listen to,
shares with, and
supports the
efforts of others,
but sometimes is
not a good team
member.
Rarely listens to,
shares with, and
supports the
efforts of others.
Of ten is not a
good team player.
Dealing with the
given task
Score: ____
Group tries to
solve its given
task by itself
without seeking
outside help.
Group seldom
solves its given
task as a team and
asks classmates or
teacher for help.
Group settles the
given task and
gives up easily.
Little attempt to
solve the given
task; gives up
easily.
Quality of work
Score: ____
Provides work of
the highest
quality
Provides high
quality work
Provides work
that occasionally
needs to be
checked by other
group members to
ensure quality.
Provides work
that usually needs
to be checked to
ensure quality.
Collaborative Work RUBRIC

Category 4 3 2 1
Attitude
Score: ____
Always has a
positive attitude
about the task.
Often has a
positive attitude
about the task.
Seldom has a
positive attitude
about the task.
Never has a
positive attitude
about the task.
Presentation
Score: ____
Presentation is
excellent,
captures interest
of audience and
at all times the
presenter speaks
clearly and
loudly, good eye
contact, & use of
appropriate body
language.
Presentation is
very good;
captures interest
of audience and
most of the time
the presenter
speaks clearly and
loudly, some eye
contact, & some
use of appropriate
body language.
Presentation is
good and at times
interesting to
audience and the
presenter is hard
to hear , little eye
contact, & poor
body language
Presentation is
not as good and
does not captures
interest of
audience and the
presenter cannot
be heard, with out
eye contact, and
poor body
language.
Quality of work
Score: ____
Collaborative Work RUBRIC

Can you do this?
GROUP 1
Solve for the value of x:
965 x

Can you do this?
GROUP 2
Solve for the value of x:
5116 x

Can you do this?
GROUP 3
Solve for the value of x:
107xx

Can you do this?
GROUP 4
Solve for the value of x:
xx6

Can you do this?
GROUP 5
Solve for the value of x:
79x

Response-
Before-
the-
Discussion
STATEMENT
Response-
After-the-
Discussion
The value of is 9x
2
.
2
)3(x
DISAGREE

Response-
Before-
the-
Discussion
STATEMENT
Response-
After-the-
Discussion
In the equation the value of x
is 32.
82x
AGREE

Response-
Before-
the-
Discussion
STATEMENT
Response-
After-the-
Discussion
The value of x in the equation
is 8. 312 x
AGREE

Response-
Before-
the-
Discussion
STATEMENT
Response-
After-the-
Discussion
The value of x in the equation
is -5. 7335  xx
DISAGREE

Response-
Before-
the-
Discussion
STATEMENT
Response-
After-the-
Discussion
The value of x in the equation
is 25. 642 x
AGREE

Let’s Remember
1. Isolate one radical at a time on one
side of the equation.

To solve radical equations reducible to
quadratic form, follow these steps:


2. Square both sides.

3. Solve the obtained radical equation.

4. Verify the obtained answers in step 3
whether it a solution or not.

VALUES INTEGRATION:
Why is teamwork
important in doing
collaborative
activities?

EVALUATE

Directions: Solve for the value
of x.
104.1 x
5113.2 x
158.3 xx
xx2.4
410.5 x

The answers are:
25.1x
12.2x
5&3.3x
4&1.4x
6.5x

EXTEND

Name: ______________________________
TOPIC : SOLVING EQUATIONS INVOLVING ONE RADICAL
K W H L
What I know? What do I want
to know?
How do I find
out?
What have I
learned?

THANK
YOU!
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