Understanding the Case
Classical Approach
0 X L
Assume there is no air resistance? What do you expect?
Prepared by Dr. Pradeep Samantaroy
Understanding the Case
Quantum Approach
0 X L
V = 0
V = ∞ V = ∞
Zone I Zone II Zone III
V(x)=0 for L >x >0
V(x)=∞ for x ≥ L, x ≤0
Prepared by Dr. Pradeep Samantaroy
Let’s solve the case…!
ExV
dx
xd
m
)(
)(
2
2
22
The Schrodinger’s equation for the electron in one dimensional box
can be represented as
Applying boundary conditions to Zone I
E
dx
xd
m
*
)(
2
2
22
0
2
Hence, the probability of finding electron in the Zone I is zero.
The same logic can be applied to zone III.
Prepared by Dr. Pradeep Samantaroy
E
dx
xd
m
2
22
)(
2
2
2
2
)(
k
dx
xd
E
m
dx
xd
22
2
2)(
This is similar to the general differential equation: kxBkxA cossin
So we can start applying boundary conditions:
x=0 ψ=0 kBkA 0cos0sin0 0B
x=L ψ=0 0A kLAsin0 nkL
where n is any integer
Solution to the Zone II
And the general solution to the differential equation is: L
xn
A
II
sin
Now the wave function becomes
Prepared by Dr. Pradeep Samantaroy
How do you find the value of A?
Normalizing wave function 1)sin(
0
2
L
dxkxA 1
4
2sin
2
0
2
L
k
kxx
A 1
4
2sin
2
2
L
n
L
L
n
L
A
Since n is any integer
1
2
2
L
A L
A
2
Hence normalized wave function is: L
xn
L
II
sin
2
Prepared by Dr. Pradeep Samantaroy
2
22
mE
k m
k
E
2
22
2
22
42m
hk
E 2
2
2
22
42
m
h
L
n
E 2
22
8mL
hn
E Calculation of Energy Levels
Can n be zero??
Prepared by Dr. Pradeep Samantaroy
E
1 = h
2
/ 8mL
2
E
2 = 4h
2
/ 8mL
2
E
3 = 9h
2
/ 8mL
2
E
4 = 16h
2
/ 8mL
2
Ψ |Ψ
2
| E
The Important Graphs
Prepared by Dr. Pradeep Samantaroy
Let’s solve numericals
An electron is confined in a one-dimensional box of length 2 A°.
Calculate the ground state energy in electron volts.
Is quantization of energy level observable?
Prepared by Dr. Pradeep Samantaroy
Let’s solve numericals
Calculate the average value of the energy of a particle of mass m
confined to move in a one-dimensional box of width a and
infinite height with potential energy zero inside the box. The
normalized wave function of the particle is
Ψ
n(x) = (2/a)
1/2
sin (nπx/a) where n = 1,2,3…
Prepared by Dr. Pradeep Samantaroy