RajeshGundlapalle
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45 slides
Jun 21, 2020
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About This Presentation
PRECISION RECTIFIERS
Size: 860.33 KB
Language: en
Added: Jun 21, 2020
Slides: 45 pages
Slide Content
SIGNAL PROCESSING CIRCUITS USING OP AMP
PrecisionRectifiers
Half Wave Rectifier(HWR)
•Saturation precision HWR
•Non Saturation Precision HWR
Full wave rectifier (FWR)
Limiting Circuits
Peak Clipper
Dead Zone Circuit
Precision Clipper
Sample and Hold Circuit
RAJESHG
Sr. Asst. Prof/ECE
Half-waverectifier
Consider adioderectifier:
Vo
Vi
D
R
i
VD
Vo
slope=1
V
Half-waverectifier
Consider adioderectifier:
Vo
Vi
D
R
i
VD
IfVi »VD,the diodedropcanbeignored.
However,ifVi issmall,e.g., Vi =0.2sinωt V,then the circuit doesnotrectify, and
Vo(t)=0V.
Vo
slope=1
V
Half-waverectifier
Consider adioderectifier:
Vo
Vi
D
R
i
VD
IfVi »VD,the diodedropcanbeignored.
However,ifVi issmall,e.g., Vi =0.2sinωt V,then the circuit doesnotrectify, and
Vo(t)=0V.
Precision rectifier circuits overcome thisdrawback.
Vo
slope=1
V
Half-waveprecision rectifier
Vo
DVi
R
Half-waveprecision rectifier
i−Vo Vo
DVi Vi VD
R iR
R
Consider twocases:
(i)Disconducting:The feedback loopisclosed,and the circuit lookslike(except
forthe diodedrop) the bufferwehaveseenearlier.
iD
Vo1
Half-waveprecision rectifier
i−Vo Vo
DVi Vi VD
R iR
R
Consider twocases:
(i)Disconducting:The feedback loopisclosed,and the circuit lookslike(except
forthe diodedrop) the bufferwehaveseenearlier.
Sincethe input currenti− ≈0,iR =iD.
Vo1Vo+0.7V
Further,V+ −V− = = ≈0V→Vo =Vi.
A AV V
iD
Vo1
Half-waveprecision rectifier
i−Vo Vo
DVi Vi VD
R iR
R
Consider twocases:
(i)Disconducting:The feedback loopisclosed,and the circuit lookslike(except
forthe diodedrop) the bufferwehaveseenearlier.
Sincethe input currenti− ≈0,iR =iD.
Vo1Vo+0.7V
Further,V+ −V− = = ≈0V→Vo =Vi.
A AV V
ThissituationarisesonlyifiD >0(since the diodecanonlyconductinthe
forward direction),i.e.,Vo >0→Vi =Vo >0V.
iD
Vo1
Half-waveprecision rectifier
Vo
i−Vo Vo
DVi Vi VD
R iR
R
Vi
Consider twocases:
(i)Disconducting:The feedback loopisclosed,and the circuit lookslike(except
forthe diodedrop) the bufferwehaveseenearlier.
Sincethe input currenti− ≈0,iR =iD.
Vo1Vo+0.7V
Further,V+ −V− = = ≈0V→Vo =Vi.
A AV V
ThissituationarisesonlyifiD >0(since the diodecanonlyconductinthe
forward direction),i.e.,Vo >0→Vi =Vo >0V.
slope=1
iD
Vo1
Half-waveprecision rectifier
Vo
DVi
R
Half-waveprecision rectifier
Vo Vo
DVi Vi
R
R
(ii)Disnot conducting→Vo =0V.
Vo1
Half-waveprecision rectifier
Vo Vo
DVi Vi
R
R
(ii)Disnot conducting→Vo =0V.
What about Vo1?
Sincethe OpAmpisnowinthe open-loop configuration,averysmallVi is
enough todriveittosaturation.
Vo1
Half-waveprecision rectifier
Vo Vo
DVi Vi
R
R
(ii)Disnot conducting→Vo =0V.
What about Vo1?
Sincethe OpAmpisnowinthe open-loop configuration,averysmallVi is
enough todriveittosaturation.
Note thatCase(ii)occurs whenVi <0V. SinceV+ −V− =Vi−0=Vi is
negative, Vo1 isdrivento−Vsat.
Vo1
Half-waveprecision rectifier
Vo Vo
DVi Vi
R
R
Vi
(ii)Disnot conducting→Vo =0V.
What about Vo1?
Sincethe OpAmpisnowinthe open-loop configuration,averysmallVi is
enough todriveittosaturation.
Note thatCase(ii)occurs whenVi <0V. SinceV+ −V− =Vi−0=Vi is
negative, Vo1 isdrivento−Vsat.
Vo
Vo=0
Vo1
Half-waveprecision rectifier
2
0
−2
−4
−6
−8
o
Vi
superdiode
−10Vi
−12
0 1
t(ms)
2
*The circuit iscalleda“superdiode”(i.e., adiodewithzeroVon).
Doff
V
o=0
Vo
Don
V
o=V
i
D
Vo1 V
R
V
o
V
i
Half-waveprecision rectifier
2
0
−2
−4
−6
−8
o
Vi
superdiode
−10Vi
−12
0 1
t(ms)
2
*The circuit iscalleda“superdiode”(i.e., adiodewithzeroVon).
Doff
V
o=0
Vo
Don
V
o=V
i
D
Vo1 V
R
V
o
V
i
V
o1
−Vsat
Half-waveprecision rectifier
2
0
−2
−4
−6
−8
o
Vi
superdiode
−10Vi
−12
0 1
t(ms)
2
*The circuit iscalleda“superdiode”(i.e., adiodewithzeroVon).
*Note thatthe OpAmpneeds tocomeout ofsaturationwhenVi changes from
negative topositive values. Thisisarelatively slowprocess, and itlimitsthe
speed ofthiscircuit.
Doff
V
o=0
Vo
Don
V
o=V
i
D
Vo1 V
R
V
o
V
i
V
o1
−Vsat
Half-waveprecision rectifier
2
0
−2
−4
−6
−8
o
Vi
superdiode
−10Vi
−12
0 1
t(ms)
2
*The circuit iscalleda“superdiode”(i.e., adiodewithzeroVon).
*Note thatthe OpAmpneeds tocomeout ofsaturationwhenVi changes from
negative topositive values. Thisisarelatively slowprocess, and itlimitsthe
speed ofthiscircuit.
Doff
V
o=0
Vo
Don
V
o=V
i
D
Vo1 V
R
V
o
V
i
V
o1
−Vsat
Half-waveprecision rectifier
Improved/Non saturated half-waveprecisionrectifier
i
R2
i
R1
ViR1 Vo
i
R
R
R2
i
D2
Vo1
D2
i
D1
D1
i
R2
i
R1
ViR1 Vo
i
R
R
(i)D1 conducts:V− =V+ =0V,Vo1 =−VD1 ≈−0.7V.
R2
i
D2
Vo1
D2
i
D1
D1
Improved/Non saturated half-waveprecisionrectifier
i
R2
i
R1
ViR1 Vo
i
R
R
(i)D1 conducts:V− =V+ =0V,Vo1 =−VD1 ≈−0.7V.
D2 cannotconduct(show that,ifitdid,KCLisnot satisfied at Vo).
→iR2 =0,Vo =V− =0V.
R2
i
D2
Vo1
D2
i
D1
D1
Improved/Non saturated half-waveprecisionrectifier
Improvedhalf-waveprecisionrectifier
R2
i
R2
i
R1
Vi ViR1 R1Vo Vo
i
R RR
(i)D1 conducts:V− =V+ =0V,Vo1 =−VD1 ≈−0.7V.
D2 cannotconduct(show that,ifitdid,KCLisnot satisfied at Vo).
→iR2 =0,Vo =V− =0V.
Vi>0
Vo1
D2
D1
R2
i
D2
Vo1
D2
i
D1
D1
Improvedhalf-waveprecisionrectifier
R2
i
R2
i
R1
Vi ViR1 R1Vo Vo
i
R RR
(i)D1 conducts:V− =V+ =0V,Vo1 =−VD1 ≈−0.7V.
D2 cannotconduct(show that,ifitdid,KCLisnot satisfied at Vo).
→iR2 =0,Vo =V− =0V.
iR1 =iD1 whichcanonlybepositive ⇒ Vi >0V.
Vi>0
Vo1
D2
D1
R2
i
D2
Vo1
D2
i
D1
D1
R2
i
R2
i
R1
Vi ViR1 R1Vo Vo
i
R RR
(i)D1 conducts:V− =V+ =0V,Vo1 =−VD1 ≈−0.7V.
D2 cannotconduct(show that,ifitdid,KCLisnot satisfied at Vo).
→iR2 =0,Vo =V− =0V.
iR1 =iD1 whichcanonlybepositive ⇒ Vi >0V.
(ii)D1 isoff;thiswillhappen whenVi <0V.
Vi>0
Vo1
D2
D1
R2
i
D2
Vo1
D2
i
D1
D1
Improved/Non saturated half-waveprecisionrectifier
R2 R2
i
R2
i
R1
Vi Vi ViR1 R1 R1Vo Vo Vo
i
R R RR
(i)D1 conducts:V− =V+ =0V,Vo1 =−VD1 ≈−0.7V.
D2 cannotconduct(show that,ifitdid,KCLisnot satisfied at Vo).
→iR2 =0,Vo =V− =0V.
iR1 =iD1 whichcanonlybepositive ⇒ Vi >0V.
(ii)D1 isoff;thiswillhappen whenVi <0V.
Inthiscase, D2 conductsand closesthe feedback loopthroughR2.
Vi<0Vi>0
Vo1
D2
D1
Vo1
D2
D1
R2
i
D2
Vo1
D2
i
D1
D1
Improved/Non saturated half-waveprecisionrectifier
R2 R2
i
R2
i
R1
Vi Vi ViR1 R1 R1Vo Vo Vo
i
R R RR
(i)D1 conducts:V− =V+ =0V,Vo1 =−VD1 ≈−0.7V.
D2 cannotconduct(show that,ifitdid,KCLisnot satisfied at Vo).
→iR2 =0,Vo =V− =0V.
iR1 =iD1 whichcanonlybepositive ⇒ Vi >0V.
(ii)D1 isoff;thiswillhappen whenVi <0V.
Inthiscase, D2 conductsand closesthe feedback loopthroughR2.
„
0−Vi
«
R2
Vo =V− +iR2R2 =0+ R2 =−
R
Vi.
R1 1
Vi<0Vi>0
Vo1
D2
D1
Vo1
D2
D1
R2
i
D2
Vo1
D2
i
D1
D1
Improved/Non saturated half-waveprecisionrectifier
R2
1k
−
R1
i
1k
ViR1
Vo
o
R
Vo
R
2
V
V =0
V
i
Vo1
D2
D
1
Improved/Non saturated half-waveprecisionrectifier
2
R2
1k
1
−
R1
i
1k
ViR1
Vo
0
o
R
−1
0 1
t (ms)
2
Vo
R
2
V
V =0
V
i
Vo1
D2
D
1
V
i V
o
Improved/Non saturated half-waveprecisionrectifier
2
R2
1k
1
−
R1
i
1k
ViR1
Vo
0
o
R
−1
0 1
t (ms)
2
Vo
R
2
V
V =0
V
i
Vo1
D2
D
1
V
o1
V
i V
o
Improved/Non saturated half-waveprecisionrectifier
2
R2
1k
1
−
R1
i
1k
ViR1
Vo
0
o
R
−1
0 1
t (ms)
2
*Note thatthe OpAmpdoesnot enter saturationsinceafeedback path is
available forVi >0Vand Vi <0V.
Vo
R
2
V
V =0
V
i
Vo1
D2
D
1
V
o1
V
i V
o
Improved/Non saturated half-waveprecisionrectifier
2
R2
1k
1
−
R1
i
1k
ViR1
Vo
0
o
R
−1
0 1
t (ms)
2
*Note thatthe OpAmpdoesnot enter saturationsinceafeedback path is
available forVi >0Vand Vi <0V.
SEQUELfile:precisionhalfwave.sqproj
Vo
R
2
V
V =0
V
i
Vo1
D2
D
1
V
o1
V
i V
o
Improved/Non saturated half-waveprecisionrectifier
R2
D1
ViR1
i
Vo
2
V
i
R
The diodesarenowreversed.
Vo
Vo=0
V
R
−
R1
Vo1
D2
Improved/Non saturated half-waveprecisionrectifier
R2
D1
ViR1
i
Vo
2
V
i
R
The diodesarenowreversed.
Byconsidering twocases: (i)D1 on,(ii)D1 off,the Vo versusVi relationshipshownin
the figureisobtained(show this).
Vo
Vo=0
V
R
−
R1
Vo1
D2
Improved/Non saturated half-waveprecisionrectifier
R2
D1
ViR1
i
Vo
2
V
i
R
The diodesarenowreversed.
Byconsidering twocases: (i)D1 on,(ii)D1 off,the Vo versusVi relationshipshownin
the figureisobtained(show this).
Vo
Vo=0
V
R
−
R1
Vo1
D2
Improved/Non saturated half-waveprecisionrectifier
Two Output half-waveprecisionrectifier
The diodesD2is connected in series with the opampo/p terminal and R
2exactly is connected
as in improved precision HWR.
Two Output half-waveprecisionrectifier
The diodesD2is connected in series with the opampo/p terminal and R
2exactly is connected
as in improved precision HWR.
The diodesR
4 is added in series D
1where D
1exactly is connected as in improved precision
HWR.
Two Output half-waveprecisionrectifier
When V
i> 0V , Op-amp output terminal goes ‘-ve’, resulting
D
1in Forward Bias and D
2in reverse bias [ No Current flows in R
2]
op amp together with R
1and R
4function as inverting amplifier.
So, at node ‘B’
V
B= -[+V
i] (R
4/R
1)
Two Output half-waveprecisionrectifier
When V
i< 0V , Op-amp output terminal goes ‘+ve’, resulting
D
2in Forward Bias and D
1in reverse bias [ No Current flows in R
4]
op amp together with R
1and R
2function as inverting amplifier.
So, at node ‘A’
V
A= -[-V
i] (R
2/R
1)
AM demodulationusingapeakdetector
0.15
Super
diode
AM
signal
Vo2
0
−0.15
0 1
t(ms)
2
*charging throughsuperdiode,discharging throughresistor
*The time constant(RC)needs tobecarefullyselected.
Vo1 filter
Vi
Vo1
Full-waveprecision rectifier
V
B
V
i
o
V
i
V
o1 V
A
V
i
V
i
V
i
x(−1)
V
B V
VoHalf−wave
rectifier
(inverting)
x(−2)
V
o1 V
A
Full-waveprecision rectifier
V
B
V
i
o
V
i
V
o1 V
A
V
i
V
i
V
i
oV
i
inverting half−waverectifier inverting summer
(SEQUELfile:precision_full_wave.sqproj)
D
1
R
1
R
R
R/2
R
1
D
2
V
V
o1
x(−1)
V
B V
VoHalf−wave
rectifier
(inverting)
x(−2)
V
o1 V
A
Full-waveprecision rectifier
V
B
2
V
i
1
o
0
V
i
V
o1 V
A
V
i
−1
i
V
i
V
i
−2
0 1
t(ms)
2
oV
i
inverting half−waverectifier inverting summer
(SEQUELfile:precision_full_wave.sqproj)
D
1
R
1
R
R
R/2
R
1
D
2
V
V
o1
x(−1)
V
B V
VoHalf−wave
rectifier
(inverting)
x(−2)
V
o1 V
A
V
Vo
Full-waveprecision rectifier
2
1
0
−1
i
−2
0 1
t(ms)
2
V
Vo
oV
i
inverting half−waverectifier inverting summer
D
1
R
1
A
R
3
R
4
R
5
R
2
= 2R
1
D
2
V
B
When V
i> 0V [‘+ve’ Cycle] ,
at ‘A’ , V
A= + V
i
And at ‘B’ , V
B= -2V
i
therefore , V
B =-[R
4
/R
3] (V
A + V
B )
= [R
4
/R
3] V
i
When V
i< 0V [‘-ve’ Cycle] ,
at ‘A’ , V
A= -V
i
And at ‘B’ , V
B= 0
therefore , V
B =-[R
4
/R
5] (V
A + V
B )
= [R
4
/R
5] V
i
Full-waveprecision rectifier
2
1
0
−1
i
−2
0 1
t(ms)
2
V
Vo
oV
i
inverting half−waverectifier inverting summer
D
1
R
1
A
R
3
R
4
R
5
R
2
= 2R
1
D
2
V
B
When V
i> 0V [‘+ve’ Cycle] ,
at ‘A’ , V
A= + V
i
And at ‘B’ , V
B= -2V
i
therefore , V
B =-[R
4
/R
3] (V
A + V
B )
= [R
4
/R
3] V
i
When V
i< 0V [‘-ve’ Cycle] ,
at ‘A’ , V
A= -V
i
And at ‘B’ , V
B= 0
therefore , V
B =-[R
4
/R
5] (V
A + V
B )
= [R
4
/R
5] V
i
A precision FWR circuit is also known as an “absolute value circuit”.