Response of control systems in time domain

Response of control systems in time domain

1. UNIT -4 (04 Hrs) Response of control system 1 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

2. Standard Test Signals In analyzing and designing control systems, we must have a basis of comparison of performance of various control systems. This basis may be set up by specifying particular test input signals and by comparing the responses of various systems to these input signals. The commonly used test input signals are: step functions, ramp functions, impulse functions, sinusoidal functions, and white noise 2 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

3. Which of these typical input signals to use for analyzing system characteristics may be determined by the form of the input that the system will be subjected to most frequently under normal operation. If the inputs to a control system are gradually changing functions of time, then a ramp function of time may be a good test signal. Similarly, if a system is subjected to sudden disturbances, a step function of time may be a good test signal. 3 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

4. Transient Response and Steady-State Response The time response of a control system consists of two parts: the transient response and the steady-state response. By transient response, we mean that which goes from the initial state to the final state. By steady-state response, we mean the manner in which the system output behaves as ‘t’ approaches infinity. c(t) = ctr (t) + css (t) 4 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

5. FIRST ORDER SYSTEMS The input-output relationship is given by: C(s)/R(s) =1/(Ts + 1) In the following, we shall analyze the system responses to such inputs as the unit-step, unit-ramp, and unit-impulse functions. The initial conditions are assumed to be zero. First order systems 5 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

6. Unit-Step Response of First-Order Systems Since the Laplace transform of the unit-step function is 1/s, substituting R(s)=1/s , we obtain: C(s) =1/(Ts + 1)s Expanding into partial fractions: Taking the inverse Laplace transform: Equation states that initially the output c(t) is zero and finally it becomes unity. One important characteristic of such an exponential response curve c(t) is that at t=T the value of c(t) is 0.632, or the response c(t) has reached 63.2% of its total change. This may be easily seen by substituting t=T in c(t).That is, c(T) = 1 - e-1 = 0.632 6 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

7. Note that the smaller the time constant T, the faster the system response. Another important characteristic of the exponential response curve is that the slope of the tangent line at t=0 is 1/T, since The output would reach the final value at t=T if it maintained its initial speed of response. In two time constants, the response reaches 86.5%of the final value. At t=3T, 4 T, and 5T, the response reaches 95%, 98.2%, and 99.3%, respectively, of the final value. 7 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

8. Unit-Ramp Response of First-Order Systems. Since the Laplace transform of the unit-ramp function is 1/s2, we obtain the output of the system as: Taking inverse laplace transform: Error signal is given as: 8 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

9. As t approaches infinity, e–t/T approaches zero, and thus the error signal e(t) approaches T. The smaller the time constant T, the smaller the steady-state error in following the ramp input. 9 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

10. Unit-Impulse Response of First-Order Systems. For the unit-impulse input, R(s)=1, the output of the system can be given by: Tking inverse laplace transform: 10 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

11. Comparing the system responses to these three inputs clearly indicates that the response to the derivative of an input signal can be obtained by differentiating the response of the system to the original signal. It can also be seen that the response to the integral of the original signal can be obtained by integrating the response of the system to the original signal and by determining the integration constant from the zero-output initial condition. This is a property of linear time-invariant systems. Linear time-varying systems and nonlinear systems do not possess this property. 11 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

12. Second Order Systems Consider the servo system consisting of a proportional controller and load elements (inertia and viscous-friction elements).Suppose that we wish to control the output position c in accordance with the input position r. The equation for the load elements is where T is the torque produced by the proportional controller whose gain is K. By taking Laplace transforms of both sides of this last equation, assuming the zero initial conditions, we obtain: 12 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

13. Such a system where the closed-loop transfer function possesses two poles is called a second-order system. Block diagram of given second order system 13 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering Modified TF, considering gain K in the forward path

14. Step Response of Second-Order System The closed-loop transfer function of the system is: which can be rewritten as The closed-loop poles are complex conjugates if B2-4JK<0 and they are real if B2-4JK > 0. In the transient-response analysis, it is convenient to write 14 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

15. Where is called the attenuation; , the undamped natural frequency; and , the damping ratio of the system. The modified TF becomes: This form is called the standard form of the second-order system. The dynamic behavior of the second-order system can then be described in terms of two parameters and If 0< <1, the closed-loop poles are complex conjugates and lie in the left-half s plane. The system is then called underdamped , and the transient response is oscillatory. If =0, the transient response does not die out. If =1, the system is called critically damped. Overdamped systems correspond to >1. 15 Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering

16. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 16 (1 ) Underdamped case (0< <1): In this case, C(s)/R(s) can be re-written as: Where ω d = The frequency ω d is called the damped natural frequency. For a unit-step input, C(s) can be written

17. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 17 It can be seen that the frequency of transient oscillation is the damped natural frequency ω d and thus varies with the damping ratio .

18. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 18 The error signal for this system is the difference between the input and output and is This error signal exhibits a damped sinusoidal oscillation. At steady state, or at t=∞,no error exists between the input and output. If the damping ratio is equal to zero, the response becomes undamped and oscillations continue indefinitely. The response c(t) for the zero damping case may be obtained by substituting =0 in the expression of c(t). Undamped natural frequency of the system

19. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 19 (2) Critically damped case ( = 1): If the two poles of C(s)/R(s) are equal, the system is said to be a critically damped one. For approaching unity in the expression of c(t) and by using the following limit: (3) Overdamped case ( >1 ): In this case, the two poles of C(s)/R(s) are negative real and unequal. For a unit-step input, R(s)=1/s and C(s) can be written

20. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 20 Taking inverse Laplace transform Thus, the response c(t) includes two decaying exponential terms. Suppose –s2 is located very much closer to the j ω axis than –s1 (which means |s2| << |s1| ), then for an approximate solution we may neglect –s1. This is permissible because the effect of –s1 on the response is much smaller than that of –s2.

21. Unit-step response curves of the second order system Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 21 From Figure , we see that an underdamped system with between 0.5 and 0.8 gets close to the final value more rapidly than a critically damped or overdamped system . Among the systems responding without oscillation, a critically damped system exhibits the fastest response.An overdamped system is always sluggish in responding to any inputs.

22. Definitions of Transient-Response Specifications Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 22 The transient response of a practical control system often exhibits damped oscillations before reaching steady state. In specifying the transient-response characteristics of a control system to a unit-step input, it is common to specify the following: 1. Delay time, td 2. Rise time, tr 3 . Peak time, tp 4. Maximum overshoot,Mp 5. Settling time, ts

23. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 23 Unit-step response curve showing td, tr , tp, Mp , and ts .

24. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 24 1. Delay time, td: The delay time is the time required for the response to reach half the final value the very first time. 2. Rise time, tr : The rise time is the time required for the response to rise from 10% to 90%, 5% to 95%, or 0% to 100% of its final value. For underdamped second order systems, the 0%to 100%rise time is normally used. For overdamped systems, the 10% to 90% rise time is commonly used. 3. Peak time, tp : The peak time is the time required for the response to reach the first peak of the overshoot. 4. Maximum (percent) overshoot, Mp: The maximum overshoot is the maximum peak value of the response curve measured from unity. If the final steady-state value of the response differs from unity, then it is common to use the maximum percent overshoot. It is defined by

25. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 25 The amount of the maximum (percent) overshoot directly indicates the relative stability of the system. 5. Settling time, ts : The settling time is the time required for the response curve to reach and stay within a range about the final value of size specified by absolute percentage of the final value (usually 2% or 5%). The settling time is related to the largest time constant of the control system.

26. Second-Order Systems and Transient-Response Specifications. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 26 In the following, we shall obtain the rise time, peak time, maximum overshoot, and settling time of the second-order system, assuming underdamped system. 1. Rise time ( tr )= we obtain the rise time tr by letting c( tr )=1.

27. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 27 2. Peak time tp : W e may obtain the peak time by differentiating c(t) with respect to time and letting this derivative equal zero. The cosine terms in this last equation cancel each other, dc/ dt , evaluated at t= tp , can be simplified to: Since the peak time corresponds to the first peak overshoot , ω d t p = π . Hence The peak time tp corresponds to one-half cycle of the frequency of damped oscillation .

28. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 28 3. Maximum overshoot( Mp): The maximum overshoot occurs at the peak time or at t= tp = π / ω d . Assuming that the final value of the output is unity, Mp is obtained from: If the final value c(q) of the output is not unity, then we need to use the following equation:

29. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 29 Settling time ( ts ) : For an underdamped second-order system, the transient response is given as:

30. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 30 The speed of decay of the transient response depends on the value of the time constant . The settling time corresponding to a ; 2% or ;5% tolerance band may be measured in terms of the time constant T= from the curves of Figure 5–7 for different values of .The results are shown in Figure 5–11. For 0< <0.9, if the 2% criterion is used, ts is approximately four times the time constant of the system. If the 5% criterion is used, then ts is approximately three times the time constant. Note that the settling time reaches a minimum value around =0.76 (for the 2% criterion) or =0.68 (for the 5% criterion) and then increases almost linearly for large values of .

31. Practice problems Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 31 Q.When the system shown in Figure (a) is subjected to a unit-step input, the system output responds as shown in Figure (b). Determine the values of K and T from the response curve.

32. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 32 The maximum overshoot of 25.4% corresponds to =0.4. From the response curve we have:

33. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 33 Q. Consider the system shown in Figure, where =0.6 and ω n =5 rad /sec. Let us obtain the rise time tr , peak time tp , maximum overshoot Mp, and settling time ts when the system is subjected to a unit-step input. From given values, we obtain:

34. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 34

35. Steady-state error in unity feedback control system Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 35 The closed-loop transfer function is: The static error constants defined in the following are figures of merit of control systems. The higher the constants, the smaller the steady-state error. In a given system, the output may be the position, velocity, pressure, temperature, or the like. The physical form of the output, however, is immaterial to the present analysis. Therefore, in what follows, we shall call the output “position,” the rate of change of the output “velocity,” and so on. This means that in a temperature control system “position” represents the output temperature, “velocity” represents the rate of change of the output temperature, and so on. In terms of error signal:

36. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 36 Static Position Error Constant Kp . The steady-state error of the system for a unit-step input is: The static position error constant Kp is defined by Thus, the steady-state error in terms of the static position error constant Kp is given by Consider the unity-feedback control system with the following open-loop transfer function G(s):

37. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 37 For a unit-step input, the steady-state error ess may be summarized as follows: Static Velocity Error Constant Kv . The steady-state error of the system with a unit-ramp input is given by: The static velocity error constant Kv is defined by:

38. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 38 Thus, the steady-state error in terms of the static velocity error constant Kv is given by Response of a type 1 unity-feedback system to a ramp input. For type 0 system : For type 1 system : For type 2 system:

39. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 39 Static Acceleration Error Constant Ka. The steady-state error of the system with a unit-parabolic input (acceleration input), which is defined by: The static acceleration error constant Ka is defined by the equation The steady-state error is then

40. Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 40 For a type 0 system,

41. Steady-State Error in Terms of Gain K Dr. Ankita Malhotra SVKM's D J Sanghvi College of Engineering 41 The error constants Kp , Kv , and Ka describe the ability of a unity-feedback system to reduce or eliminate steady-state error. Therefore, they are indicative of the steady-state performance. It is generally desirable to increase the error constants, while maintaining the transient response within an acceptable range.