SHORT TRICK TO FIND DAY OF ANY GIVEN DATE - LOGICAL REASONING QUESTIONS FOR COMPETITIVE EXAMS

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1. SSC EXAM REASONING 1
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Shortcut to find day of any Given date:-
Code for MonthMonth
0Jan, Oct
1May
2Aug
3Feb, March, Nov.
4June
5Sep, dec
6April, July.
If year is less than 2000, then consider only last 2 digit of that year & if year is equal to or more than 2000,
then subtract 1900 from that given year.
It mean for 1914 Take (14) as value of the year
& for 2014 Take (2014 – 1900 = 114) as value of year.
As we know, leap year comes after every 4 years. So to know leap year value, just divide year by 4.
So now Trick is =
7
Date Month Year Leap Year  
& then find Remainder..
if Remainder is 1 (it is 1
st
day of week – monday)
if Remainder is 2 (day is Tuesday)
if Remainder is 3 (day is Wednesday)
if Remainder is 4 (day is Thursday)
If Remainder is 5 (day is Friday)
if Remainder is 6 (day is Saturday)
& if Remainder is 0 (then day is Sunday)
Note:- This trick is only to find the day of the year between 1900 & 2100
e.g. I. What was day on 15
th
Aug 1947 ?
Date 15
Month 2 (code for Aug)
Year 47 (last 2 digit of 1947)
leap year11 (47 ÷ 4 = 11 as Quoitent)
Add all these 4 values = 75
& then divide by 7 & we will get Remainder 5 so day on 15
th
August 1947 is friday
e.g. II. What was day on 27
th
Jan 2015 ?
Date 27
Month 0 (code for Jan)
Year 115 (2015 – 1900 = 115)
leap year28 (115 ÷ 4 = 28 as Quoitent)
Add all these 4 values = 170
& when 170 is divided by 7, Remainder is ‘2’ so day was Tuesday.