Thermodynamics class 11 physics

MhdAfz 4,060 views 20 slides Jan 17, 2022
Slide 1
Slide 1 of 20
Slide 1
1
Slide 2
2
Slide 3
3
Slide 4
4
Slide 5
5
Slide 6
6
Slide 7
7
Slide 8
8
Slide 9
9
Slide 10
10
Slide 11
11
Slide 12
12
Slide 13
13
Slide 14
14
Slide 15
15
Slide 16
16
Slide 17
17
Slide 18
18
Slide 19
19
Slide 20
20

About This Presentation

For more such informative content, go to https://scifitechify.blogspot.com/.
This PPT is about thermodynamics. It explains isothermal, isobaric, adiabatic, and isochoric processes. In-depth explanation of formulae and derivation is provided.


Slide Content

THERMODYNAMIC PROCESSES By Mohammed Afzal 11A

Introduction: Conducting Insulating

Types of System: (Diathermic) 1)

Types of System: 2 )

Types of System: 3 )

Depends on amount of matter. Eg;- Mass,Vol,Moles,Heat Capacity,Energy,Enthalpy,Entropy,Gibb’s Free Energy,Internal energy Does not depend on matter. Eg:- Density,Refractive index, specific heat capacity,pressure,temp,viscosity,concentration Molarity,Molality,mole fraction,normality,molar entropy,molar enthalpy,internal energy. Extensive: Intensive :

Depends on initial and final state of a system. Does not depend on path of flow. Eg:-Pressure(P),Temp(T),Volume(V),moles(n), Enthalpy(H),Entropy(S),Internal Energy(U),Gibbs Free Energy(G) Depends on path of flow. Eg:-Heat(Q),Work(W) State Functions: Path Functions:

Cyclic Process: P V ΔP=0 ΔT=0 ΔE=0 ΔV=0 ΔS=0 ΔQ≠0 ΔW≠0

Gram SHC : c = Q/mΔT Molar SHC : C = Q/nΔT C isothermal -> ∞ C adiabatic = 0 (For gases) c = 4.2 J/g °C (Water) c v = Q/mΔT (At constant vol) C v = Q/nΔT (At constant vol) c P = Q/mΔT (At constant pressure) C P = Q/nΔT (At constant pressure) C v =Mc v C P= Mc P C P - C V = R C V = (f/2)R C P = (f/2 + 1)R γ=C P /C V Specific Heat Capacity:

f(degree of freedom) C v = (f/2)R C P = C V + R γ=C P /C V 3(Monoatomic) 3R/2 5R/2 5/3 = 1.66 5(Diatomic) 5R/2 7R/2 7/5 = 1.4 6(Polyatomic) 7R/2 4R 4/3 = 1.33 γ= 1 + 2/f

PV Graph for all processes: P V Isobaric Isochoric Isothermal Adiabatic Isobaric:ΔP=0 Isochoric:ΔV=0 Isothermal:ΔT=0 Adiabatic:ΔQ=0

Occurs in infinitely small steps -> Infinite time to finish. Slow Each step in equilibrium. Not practical. W = - ∫ P ext dV Occurs at once -> finite time. Fast Equilibrium initially and finally only. Practical situation. W = - 𝝨pΔV Reversible Process: Irreversible Process:

Heat given to the system -> +ve Heat given by the system -> -ve Work done on a system -> +ve Work done by a system -> -ve Conventions:

W=PV relation: P ext = F/A ⟹ F = P ext x A W = F Δx = P ext A Δ x ⟹ W = - P ext ΔV Why -ve? By convention

P V d V P ∫ dW = ∫ P dV W = - ∫ P ext dV = Area under P-V Graph Expansion: W = -ve Compression: W = +ve

Cyclic Process: P V W net = Area of shape(ie square in this case) enclosed -ve for clockwise (as in this case) +ve for anti-clockwise

Isobaric(Δp=0): W= -Pext ΔV Isochoric(ΔV=0): W = 0 Vacuum(Free Expansion): P ext = 0 ⟹ W = 0 Isobaric and Isochoric processes:

W = - ∫ Pext dV = - ∫ nRT dV/V = - nRT ln (V2/V1) = - 2.303 nRT log 10 (V2/V1) = - 2.303 nRT log 10 (P2/P1) = - 2.303 P 1 V 1 log 10 (V2/V1) = - 2.303 P 2 V 2 log 10 (V2/V1) = - 2.303 P 1 V 1 log 10 (P2/P1) = - 2.303 P 2 V 2 log 10 (V2/V1) Isothermal process

Adiabatic Process