01 INTRODUCTION OF ELECTROCHEMISTRY.pptx

elektrolisis ppt berbahasa inggris

1. ELECTROCHEMISTRY Ppt by : RIZAL NOER MEIZAL

2. HOW THE CALCULATOR TO WORK ? What is the meaning of spontan reaction ? -The reaction will be work if has different electrone afinity between the reactans in battery- Do not need energy/electrical from outside. Spontan reaction  Electron flow  Energy Now, what is the electrochemistry ?

3. INTRODUCTION The part of chemistry which studies an electrical energy in chemical reaction (electron) / interaction about electrical energy with chemical reaction. GALVANI CELL/VOLTA CELL ELECTROLYSIS CELL ELECTRO DEPOSITION ELECTRO ANALYSIS ELECTRO SYNTETIC ELECTRO DEGRADATION

4. PRINCIPE Do you remember about redox reaction ?? What is it?? A chemical reaction which describe about ½ reduction reaction and ½ oxydation reaction . What are the meaning of reduction reaction and oxydation reaction ??

5. Reduction : Changed of atomic or atomic group receive or bond an electrone . Releasing O 2 . Decrease oxnum ( biloks ) Oxydator Oxydation : Changed of atomic or atomic group release an electrone . Bonding O 2 . Increase oxnum ( biloks ) Reductor

6. How to balance the redox reaction?? Any two methode to balance the redox reaction : Oxidation Number Changed (ONC)/ PBO (Indonesian) H alf reaction methode

7. ONC Methode Oxnum : A tomic valences Principe : Eternity of capasity and mass Increase an oxnum is same with decrease an uxnom Look the redox reaction below! HNO 3(aq) + Cu 2 O (s) → Cu(NO 3 ) 2(aq) + NO (g) + H 2 O (l) Procedure : Write all oxnum of every atom. Where are atom which reduction and oxydation ? Did you studied the oxnum rules??

8. Oxnum Rules Free unsure, oxnum = 0 C ompound hasn’t ion, oxnum = 0 Alkaly group, oxnum = + 1 Soil alkaly group, oxnum = +2 Halide group, oxnum = -1 Hydrogen, oxnum = +1 (Hydride compound, oxnum = -1) Oxygen, oxnum = -2 (F 2 O, oxnum = +2, peroxide and Na 2 O 2 , oxnum = - 1, superoxide, oxnum = -1/2) Poliatomic ion, oxnum = as the ion

9. So, where is the atom which reduction and oxydation ? +5 +1 +2 HNO 3(aq) + Cu 2 O (s) → Cu(NO 3 ) 2(aq) + NO (g) + H 2 O (l) Oxnum of HNO 3 = 0 Oxnum of O = -2 x 3 = -6 Oxnum of H = +1 So, oxnum of N is +5, right? Oxnum of Cu 2 O = 0 Oxnum of O = -2 So, oxnum of Cu is +1, right? Oxnum of Cu(NO 3 ) 2 = 0 Oxnum of Cu = Oxnum of Cu + 2 x oxnum of (NO 3 ) = 0 Oxnum of Cu + 2 x -1 = 0 So, o xnum of Cu is 0 – (-2) = +2, right?

10. So, where is the atom which reduction and oxydation ? +5 +1 +2 +2 HNO 3(aq) + Cu 2 O (s) → Cu(NO 3 ) 2(aq) + NO (g) + H 2 O (l) Oxnum of NO = 0 Oxnum of O = -2 So, oxnum of N is +2, right? Oxnum of H 2 O = 0 Oxnum of O = -2 So, oxnum of H is +1, right?

11. ONC Methode Principe : Eternity of capasity and mass Increase an oxnum is same with decrease an uxnom Look the redox reaction below! HNO 3(aq) + Cu 2 O (aq) → Cu(NO 3 ) 2(aq) + NO (g) + H 2 O (l) Procedure : Write all oxnum of every atom. Where are atom which reduction and oxydation ? Every atom which reduction or oxydation must to balance. (Only reduction or oxydation !!)

12. +5 +1 +2 +2 HNO 3(aq) + Cu 2 O (s) → Cu(NO 3 ) 2(aq) + NO (g) + H 2 O (l)

13. ONC Methode Principe : Eternity of capasity Increase an oxnum same with decrease an uxnom Look the redox reaction below! HNO 3(aq) + Cu 2 O (aq) → Cu(NO 3 ) 2(aq) + NO (g) + H 2 O (l) Procedure : Write all oxnum of every atom. Where are atom which reduction and oxydation ? Every atom which reduction or oxydation must to balance. (Only reduction or oxydation !!) Cross multiplication of oxnum .

14. ONC Methode Principe : Eternity of capasity Increase an oxnum same with decrease an uxnom Look the redox reaction below! HNO 3(aq) + Cu 2 O (aq) → Cu(NO 3 ) 2(aq) + NO (g) + H 2 O (l) Procedure : Write all of oxnum of every atom. Where are atom which reduction and oxydation ? Every atom which reduction or oxydation must to balance. (Only reduction or oxydation !!) Cross multiplication of oxnum . Balance the all of atom.

15. HOMEWORK!!!

16. ½ Reaction Methode Principe : Transfer of electron Procedure : Different where is the reduction reaction or oxydation reaction. In neutral or acid condition, add H + into the segment which lacked H, and H 2 O into the segment which lacked O. In base condition, add H 2 O into the segment which lacked H, and OH - into the segment which lacked O. Balance the ion of reaction with add e - to two ½ reaction equation. Count the two reaction equation.

17. Acid condition MnO 4 - + Fe 2+ → Mn 2+ + Fe 3 + Step 1 MnO 4 - → Mn 2+ (Reduction) Fe 2+ → Fe 3+ ( Oxydation ) Step 2 MnO 4 – → Mn 2+ + 4H 2 O Step 3 MnO 4 – + 8H + → Mn 2+ + 4H 2 O Step 4 MnO 4 – + 8H + + 5e – → Mn 2+ + 4H 2 O (Half of reduction reaction)

18. Acid condition MnO 4 - + Fe 2+ → Mn 2+ + Fe 3 + Step 1 MnO 4 - → Mn 2+ (Reduction) Fe 2+ → Fe 3+ ( Oxydation ) Step 2 Fe 2+ → Fe 3+ + e – (Half of oxydation r eaction)

19. Last Step HOW WITH BASE CONDITION?

20. HOMEWORK!!!

21. ANY QUESTION??