03-Non-Dir. Overcurrent.ppt

300 views 54 slides Sep 05, 2022
Slide 1
Slide 1 of 54
Slide 1
1
Slide 2
2
Slide 3
3
Slide 4
4
Slide 5
5
Slide 6
6
Slide 7
7
Slide 8
8
Slide 9
9
Slide 10
10
Slide 11
11
Slide 12
12
Slide 13
13
Slide 14
14
Slide 15
15
Slide 16
16
Slide 17
17
Slide 18
18
Slide 19
19
Slide 20
20
Slide 21
21
Slide 22
22
Slide 23
23
Slide 24
24
Slide 25
25
Slide 26
26
Slide 27
27
Slide 28
28
Slide 29
29
Slide 30
30
Slide 31
31
Slide 32
32
Slide 33
33
Slide 34
34
Slide 35
35
Slide 36
36
Slide 37
37
Slide 38
38
Slide 39
39
Slide 40
40
Slide 41
41
Slide 42
42
Slide 43
43
Slide 44
44
Slide 45
45
Slide 46
46
Slide 47
47
Slide 48
48
Slide 49
49
Slide 50
50
Slide 51
51
Slide 52
52
Slide 53
53
Slide 54
54

About This Presentation

OC


Slide Content

Application of Non-Directional Overcurrent
and Earthfault Protection

Non-Directional Overcurrent and Earth
Fault Protection

Overcurrent Protection
Purpose of Protection
Detect abnormal conditions
Isolate faulty part of the system
Speed
Fast operation to minimise damage and danger
Discrimination
Isolate only the faulty section
Dependability / reliability
Security / stability
Cost of protection / against cost of potential hazards

Overcurrent Protection
Co-ordination
Co-ordinate protection so that relay nearest to
fault operates first
Minimise system disruption due to the fault
F1 F2
F3F3
F2F1

Fuses

Overcurrent Protection
Fuses
Simple
Can provide very fast fault clearance
<10ms for large current
Limit fault energy
Pre Arc Time
Arcing Time
Prospective Fault Current
Total
Operating
Time
t

Overcurrent Protection
Fuses -disadvantages
Problematic co-ordination
I
FAapprox 2 x I
FB
Limited sensitivity to earth faults
Single phasing
Fixed characteristic
Need replacing following fault clearance
Fuse A Fuse B

Tripping Methods

Overcurrent Protection
Direct Acting AC Trip
AC series trip
common for electromechanical O/C relays
51
I
F
Trip Coil

Overcurrent Protection
Direct Acting AC Trip
Capacitor discharge trip
used with static relays where no secure DC
supply is available
I
F'
Sensitive
Trip
Coil
I
F
51
+
-

Overcurrent Protection
DC Shunt Trip
Requires secure DC auxiliary
No trip if DC fails
I
F'
I
F
DC
BATTERY
SHUNT
TRIP COIL
51

Overcurrent Protection

Overcurrent Protection
Principles
Operating Speed
Instantaneous
Time delayed
Discrimination
Current setting
Time setting
Current and time
Cost
Generally cheapest form of protection relay

I
F1
I
F1
I
F2
Overcurrent Protection
Instantaneous Relays
Current settings chosen so that relay closest to
fault operates
Problem
Relies on there being a difference in fault level
between the two relay locations
Cannot discriminate if I
F1= I
F2
50
B
50
A
I
F1
I
F2

Overcurrent Protection
Definite (Independent) Time Relays
T
OP
TIME
I
S Applied Current
(Relay Current Setting)

Overcurrent Protection
Definite (Independent) Time Relays
Operating time is independent of current
Relay closest to fault has shortest operating time
Problem
Longest operating time is at the source where
fault level is highest
51
0.9 sec 0.5 sec
51

Overcurrent Protection
IDMT
Inverse Definite Minimum Time characteristic
TIME
Applied Current
(Relay Current Setting)
I
S

Overcurrent Protection
Disc Type O/C Relays
Current setting via plug bridge
Time multiplier setting via disc
movement
Single characteristic
Consider 2 ph & EF or 3 ph
plus additional EF relay

Overcurrent Protection
Static Relay
Electronic, multi characteristic
Fine settings, wide range
Integral instantaneous elements

Overcurrent Protection
Numerical Relay
Multiple characteristics and stages
Current settings in primary or secondary
values
Additional protection elements
Current
Time
I>1
I>2
I>3
I>4

Co-ordination

Overcurrent Protection
Co-ordination Principle
Relay closest to fault
must operate first
Other relays must have
adequate additional
operating time to
prevent them operating
Current setting chosen
to allow FLC
Consider worst case
conditions, operating
modes and current
flows
T
I
S1
I
S2
Maximum
Fault
Level
I
R
2R
1
I
F1

Overcurrent Protection
Co-ordination Example
C AB
0.01
0.1
1
10
Operating time (s)
Current (A) FL
BFL
C FL
D
E
D
C
B
DE

Overcurrent Protection
IEC Characteristics
SI t = 0.14
(I
0.02
-1)
VI t = 13.5
(I
2
-1)
EI t = 80
(I
2
-1)
LTI t = 120
(I-1)
Current (Multiples of Is)
0.1
1
10
100
1000
1 10010
Operating Time (s)
VI
EI
SI
LTI

Overcurrent Protection
Operating Time Setting -Terms Used
Relay operating times can be
calculated using relay
characteristic charts
Published characteristcs are
drawn against a multiple of
current setting or Plug Setting
Multiplier
Therefore characteristics can be
used for any application
regardless of actual relay current
setting
e.g at 10x setting (or PSM of 10)
SI curve op time is 3s
Current (Multiples of Is)
0.1
1
10
100
1000
1 10010
Operating Time (s)

Overcurrent Protection
Current Setting
Set just above full load current
allow 10% tolerance
Allow relay to reset if fault is cleared by
downstream device
consider pickup/drop off ratio (reset ratio)
relay must fully reset with full load current
flowing
PU/DO for static/numerical = 95%
PU/DO for EM relay = 90%
e.g for numerical relay, Is = 1.1 x I
FL/0.95

Overcurrent Protection
Current Setting
Current grading
ensure that if upstream relay has started
downstream relay has also started
Set upstream device current setting greater than
downstream relay
e.g. Is
R1 = 1.1 x Is
R2
R
1
R
2
I
F1

Overcurrent Protection
Grading Margin
Operating time difference between two devices to
ensure that downstream device will clear fault before
upstream device trips
Must include
breaker opening time
allowance for errors
relay overshoot time
safety margin
GRADING
MARGIN

Overcurrent Protection
Grading Margin -between relays
Traditional
breaker op time - 0.1
relay overshoot- 0.05
allow. For errors- 0.15
safety margin - 0.1
Total 0.4s
Calculate using formula
R
2R
1

Overcurrent Protection
Grading Margin -between relays
Formula
t’ = (2Er + Ect) t/100 + tcb + to + ts
Er = relay timing error
Ect = CT measurement error
t = op time of downstream relay
tcb = CB interupting time
to = relay overshoot time
ts = safety margin
Op time of Downstream Relay t = 0.5s
0.375s margin for EM relay, oil CB
0.24s margin for static relay, vacuum CB

Overcurrent Protection
Grading Margin -relay with fuse
Grading Margin = 0.4Tf + 0.15s over whole characteristic
Assume fuse minimum operating time = 0.01s
Use EI or VI curve to grade with fuse
Current setting of relay should be 3-4 x rating of fuse to
ensure co-ordination

Overcurrent Protection
Grading Margin -relay with upstream fuse
1.175T
r+ 0.1+ 0.1 = 0.6T
f
or
T
f= 2T
r + 0.33s
Allowance for CT
and relay error
CB Safety margin Allowance for fuse
error (fast)
T
f
T
r
I
FMAX

Overcurrent Protection
Time Multiplier Setting
Used to adjust the operating
time of an inverse
characteristic
Not a time setting but a
multiplier
Calculate TMS to give
desired operating time in
accordance with the grading
margin
Current (Multiples of Is)
0.1
1
10
100
1 10010
Operating Time (s)

Overcurrent Protection
Time Multiplier Setting -Calculation
Calculate relay operating time required, T
req
consider grading margin
fault level
Calculate op time of inverse characteristic
with TMS = 1, T
1
TMS = T
req
/T
1

Overcurrent Protection
Co-ordination -Procedure
Calculate required operating current
Calculate required grading margin
Calculate required operating time
Select characteristic
Calculate required TMS
Draw characteristic, check grading over whole
curve
Grading curves should be drawn to a common
voltage base to aid comparison

Overcurrent Protection
Co-ordination Example
Grade relay B with relay A
Co-ordinate at max fault level seen by both relays =
1400A
Assume grading margin of 0.4s
Is = 5 Amp; TMS = 0.05, SI
I
FMAX
= 1400 Amp
B A
200/5 100/5
Is = 5 Amp

Overcurrent Protection
Co-ordination Example
Relay B is set to 200A primary, 5A secondary
Relay A set to 100A If (1400A) = PSM of 14
relay A OP time = t = 0.14 x TMS = 0.14 x 0.05 = 0.13
(I
0.02
-1) (14
0.02
-1)
Relay B Op time = 0.13 + grading margin = 0.13 + 0.4 = 0.53s
Relay A uses SI curve so relay B should also use SI curve
Is = 5 Amp; TMS = 0.05, SI
I
FMAX
= 1400 Amp
B A
200/5 100/5
Is = 5 Amp

Overcurrent Protection
Co-ordination Example
Relay B Op time = 0.13 + grading margin = 0.13 + 0.4 = 0.53s
Relay A uses SI curve so relay B should also use SI curve
Relay B set to 200A If (1400A) = PSM of 7
relay B OP time TMS = 1 = 0.14 x TMS= 0.14= 3.52s
(I
0.02
-1) (7
0.02
-1)
Required TMS = Required Op time = 0.53 = 0.15
Op time TMS=1 3.52
Set relay B to 200A, TMS = 0.15, SI
Is = 5 Amp; TMS = 0.05, SI
I
FMAX
= 1400 Amp
B A
200/5 100/5
Is = 5 Amp

Overcurrent Protection
LV Protection Co-ordination
ZA2118B
Relay 1
Relay 2
Relay 3
Relay 4
Fuse
1
2
3
4
F
350MVA
4 4
3 3
2
F
11kV
MCGG CB
ACB CTZ61 (Open)CTZ61
ACB
MCCB
27MVA
20MVALoad
Fuse
2 x 1.5MVA
11kV/433V
5.1%
K
1

Overcurrent Protection
LV Protection Co-ordination
ZA2119
1000S
100S
10S
1.0S
0.1S
0.01S
0. 1kA 10kA 1000kA
TX damage
Very
inverse

Overcurrent Protection
LV Protection Co-ordination
ZA2120C
Relay 1
Relay 2
Relay 3
Relay 4
Fuse
1
2
3
4
F
350MVA
4 4
3 3
2
1
F
11kV
KCGG 142 CB
ACB (Open)KCEG 142
ACB
MCCB
27MVA
20MVALoad
Fuse
2 x 1.5MVA
11kV/433V
5.1%
K

Overcurrent Protection
LV Protection Co-ordination
ZA2121
1000S
100S
10S
1.0S
0.1S
0.01S
0. 1kA 10kA 1000kA
TX damage
Long time
inverse

ZA2135
R
3
R
2
R
1
Block t >
I> Start
IF2
IF1
M(Transient backfeed ?)
Graded
protection
Blocked
protection
Overcurrent Protection
Blocked OC Schemes

Use of High Sets

Fast clearance of faults
ensure good operation factor, I
f>> I
s(5 x ?)
Current setting must be co-ordinated to prevent
overtripping
Used to provide fast tripping on HV side of transformers
Used on feeders with Auto Reclose, prevents transient
faults becoming permanent
AR ensures healthy feeders are re-energised
Consider operation due to DC offset -transient
overreach
Overcurrent Protection
Instantaneous Protection

Set HV inst 130% I
fLV
Stable for inrush
No operation for LV fault
Fast operation for HV
fault
Reduces op times
required of upstream
relays
HV2 LVHV1
HV2
LVTIME
CURRENT
HV1
I
F(LV)I
F(HV)
1.3I
F(LV)
Overcurrent Protection
Instantaneous OC on Transformer Feeders

Earthfault Protection

Earth fault current may be limited
Sensitivity and speed requirements may not be met by
overcurrent relays
Use dedicated EF protection relays
Connect to measure residual (zero sequence) current
Can be set to values less than full load current
Co-ordinate as for OC elements
May not be possible to provide co-ordination with
fuses
Overcurrent Protection
Earth Fault Protection

Combined with OC relays
E/F
OC OC OC E/F
OC OC
Economise using 2x OC
relays
Overcurrent Protection
Earth Fault Relay Connection -3 Wire System

EF relay setting must be
greater than normal
neutral current
Independent of neutral
current but must use 3 OC
relays for phase to neutral
faults
E/F
OC OC OC
E/F
OC OC OC
Overcurrent Protection
Earth Fault Relay Connection -4 Wire System

Solid earth
30% I
full load
adequate
Resistance earth
setting w.r.t earth fault
level
special considerations
for impedance earthing
-directional?
Overcurrent Protection
Earth Fault Relays Current Setting

Settings down to
0.2% possible
Isolated/high
impedance earth networks
For low settings cannot use residual connection, use
dedicated CT
Advisable to use core balance CT
CT ratio related to earth fault current not line current
Relays tuned to system frequency to reject 3rd
harmonic
B
C
E/F
A
Overcurrent Protection
Sensitive Earth Fault Relays

Need to take care with core
balance CT and armoured
cables
Sheath acts as earth return
path
Must account for earth current
path in connections -insulate
cable gland
NO OPERATION OPERATION
CABLE
BOX
CABLE GLAND
CABLE GLAND/SHEATH
EARTH CONNECTION
E/F
Overcurrent Protection
Core Balance CT Connections
Tags