23a_IRC582015_RP_Design(1).pdf

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About This Presentation

IRC 58-2015 PPT


Slide Content

DESIGNOF DESIGN
OF

RIGID PAVEMENTS USING
IRC METHOD Dr. Venkaiah Chowdar
y
IRC:58
-
2015
y
IRC:58
2015
Guidelines for the Design of Plain Jointed
Ri idP f Hi h Ri
g
id
P
avements
f
or
Hi
g
h
ways
(
Fourth Revision
)
()

Develo
p
ments in IRC:58
•First Published: 1974

FirstRevision:1988
p
First
Revision:
1988
oLegal axle load limit increased from 8160 kg to 10200 kg o
TrafficclassificationbasedonCVPD[A:0
15;B:15
45;C:45
o
Traffic
classification
based
on

CVPD

[A:

0
-
15;
B:
15
-
45;
C:
45
-
150; D: 150-450; E: 450-1500; F: 1500-4500; G: >4500].

SecondRevision:2002

Second
Revision:
2002
oFatigue damage concept introduced
Fl l d i l d d l l d
o
Fl
exura
l stresses
d
ue to s
ing
le an
d
tan
d
em ax
le
loa
d
s
•Third Revision: 2011 (CFD, TDC, BUC, tied shoulders,
bddDLCifl f l) b
on
d
e
d
DLC
,
in
fl
uence o
f
permanent cur
l)
•Fourth Revision: 2015 (more rational design)

IRC
(
58-2015
)
Method of RP Desi
g
n
•Covers design of JPCP with and without tied concrete
shou
lde
r
s
(
)g
shoudes

App
licable to roads with avera
g
e traffic > 450 CVPD
pp g
•For low volume roads: IRC:SP:62-2014 •Guidelines include: (i) procedure for design of widened
outer lane, (ii) tied concrete shoulder, (iii) CC slab bonded
to stabilized sub-base, (iv) design of longitudinal joints,
expansion, and contraction joints

Salient Features of IRC:58-2015
•Design considering flexural stress caused due to combined effect
of different categories of axle loads and temperature gradient
•CFD caused by single, tandem, tridem axles taking into account
TDC dBUC TDC
an
d

BUC

Considerationof permanentcurlincalculationof flexuralstresses Consideration
of

permanent
curl

in

calculation
of

flexural
stresses
•Desi
g
ns without concrete shoulders and with tied concrete
g
shoulders D i f CC l b b d d bili d b
b

D
es
igns
f
or
CC
s
la
b
s
b
on
d
e
d
to cement sta
bili
ze
d
su
b
-
b
ases

Designsforwidenedouterlanes

Designs
for

widened
outerlanes

Concrete Pavement T
yp
es
yp
•When PQC is laid over bituminous surface during sunshine,
necessary to whitewash the bituminous surface to minimize heat
absorption absorption
•When subgrade CBR ≥ 8%, granular separation and drainage layers
can be re
p
laced with
g
eos
y
nthetics servin
g
the desired function
pgy g

Ri
g
id Pavement
(
MORTH
,
2001
)
g(,)

Ri
g
id Pavement
(
MORTH
,
2013
)
g(,)

Factors Governin
g
Desi
g
n
•Design period •
Designcommercialtrafficvolume
gg

Design
commercial
traffic
volume
•Composition of commercial traffic (single, tandem, tridem, and
li
l)
mu
lt
i-ax
les
)
•Axle load spectrum •Tyre pressure •
Lateralplacementof wheelloads

Lateral
placement
of

wheel
loads
•Directional distribution •Strength of foundation

Climaticfactors Climatic
factors

Axle Load Characteristics
Axletype Legalaxle load
Axle load group interval
forfatiguedamageanalysis for
fatigue
damage
analysis
Single 10.2 t (100 kN) 10 kN
Td
190 (186
kN
)
20
kN
T
an
d
em
19
.0
t
(186
kN
)
20
kN
Tridem 24.0 t (235 kN) 30 kN
•Data on axle load spectrum from axle load survey
conducted for a continuous 48 hour
p
eriod
p
•Commercial vehicles to be weighed (min.):
o
10%fortrafficexceeding6000CVPD
o
10%
for

traffic
exceeding
6000
CVPD
o15% for traffic between 3000 to 6000 CVPD o
20%fortrafficlessthan3000CVPD
o
20%
for

traffic
less
than

3000
CVPD

Axle Load Characteristics
•Vehicles to be surveyed shall be selected randomly to
avoid
bias
avoidbias
•If spacing of consecutive axles (wheel base) is more
than 2.4 m, each axle shall be considered as a single axle TifCV0710MP

T
yre pressure
in most o
f
CV
s:
0
.7
to
1
.0
MP
a

Variationof tyrepressurewillhavenegligibleinfluence Variation
of
tyre
pressure
will
have
negligible
influence

on CC pavements with thickness ≥200 mm
•Design tyre pressure is 0.8 MPa

Wheel Base Characteristics
•Wheel base spacing information is used to estimate top-
dow
n f
atigue
c
r
ac
k
in
g
caused
by
a
xl
e
l
oads
du
r
in
g
n
ight

dow atiguecac i gcausedbya e oadsdui g ight period
•Data on axle load spacing shall be collected during
traffic survey
•If spacing between any pair of axles is less than the
i ft jit h l dtb
spac
ing o
f
t
ransverse
jo
in
t
s, suc
h
ax
les nee
d
t
o
b
e
considered in design traffic for computing top-down
fti ki d f
a
ti
gue crac
ki
ng
d
amage

Wheelbasesof trucksrangefrom36to>50m Wheel
bases
of
trucks
range
from
3
.6
to
>
5
.0
m

Wheel Base Characteristics
•Commonly used spacing of transverse joints is 4.5 m •
A
xles with spacing > 4.5 m are not expected to
contribute to top-down fatigue cracking
•If spacing of transverse joints is different from 4.5 m,
d i ffi f i i f
dki
d
es
ign tra
ffi
c
f
or est
imat
ion o
f
top-
d
own crac
ki
ng
damage may be selected appropriately
•% of CVs with spacing between front and first rear axle
lessthantheproposedspacingof transversejointsin less
than
the
proposed
spacing
of
transverse
joints
in

CC slab shall be determined from axle load survey

Desi
g
n Period
•Life span ≥30 years
g
•May be suitable modified considering:
T ffi l
o
T
ra
ffi
c vo
lume
o
Uncertaintyof trafficgrowthrate
o
Uncertainty
of
traffic
growth
rate
oCa
p
acit
y
of the road
py
oAugmentation of capacity by widening

Traffic Consideration
•Design Lane:
o
Lanecarryinghighestno of heavyCVs
o
Lane
carrying
highest
no
.
of

heavy
CVs
oEach lane of a 2-way 2-lane highway and outer lane of multi-
lhih lane
hi
g
h
ways
•Design Traffic:
oADT based on 7-day, 24-h traffic volume o
Actualgrowthrateshallbeconsidered
o
Actual
growth

rate
shall
be

considered
oAnnual growth rate of CVs shall be min. 5% oDay & night traffic trends shall be captured
(
day loading
leads to bottom-up cracking, night loading leads to top-
d n r kin
)
d
ow
n
c
r
ac
kin
g
)

Traffic Consideration
•Design Traffic:
o
Edgeflexuralstresscausedbyaxleloads
forbottom
up
o
Edge
flexural
stress
caused
by
axle

loads
for
bottom
-
up

cracking
is max. when tyre imprint of outer wheel touches
the long
itudinal ed
g
e
gg
oStress in the edge region reduces substantially when the tyre
positionisawayfromthelongitudinaledge position
is
away
from

the
longitudinal
edge
oEdge flexural stress is small when wheel loads are close to the
transversejoints transverse
joints
oData obtained from Indian Highways on lateral distribution
of wheelpathsof CVsindicatesthatthetyreimprintsof of

wheel
paths
of

CVs
indicates
that
the

tyre
imprints

of

very few vehicles are tangential to longitudinal edge/joint on
2-lane 2-
w
a
y
roads and multi-lane hi
g
hwa
y
s
y
gy

Traffic Consideration
•Design Traffic:
o
Somemulti
lanedividedhighwayshave85to90mwide
o
Some
multi
-
lane
divided
highways
have
8
.5
to

9
.0
m

wide

carriageways with single longitudinal joint
o
Lnmrkin in h dnt inid ith
o
L
a
n
e
m
a
rkin
gs
in
suc
h
cases
d
o
n
o
t
co
in
c
id
e w
ith

longitudinal joints resulting in large proportion of wheel
pathsmoveclosertolongitudinaljoint paths
move

closer
to

longitudinal
joint
oRecommended to consider 25% of total 2-way CVs shall be
consideredasdesigntraffic
for2
-
lane2
-
wayroadsfor
considered
as
design
traffic
for

2
lane
2
way
roads

for

analysis of bottom-up cracking
o
Forfour
-
laneandmulti
-
lanedividedhighways
25%of traffic
o
For
four
-
lane

and

multi
-
lane
divided
highways
,
25%
of

traffic

in the predominant direction shall be considered as
desi
g
n trafficfor anal
y
sis of bottom-u
p
crackin
g
g
y
pg

Traffic Consideration
•Design Traffic:
o
Designtraffic
fortop
-
downcracking
analysiswillbea
o
Design
traffic
for

top
down

cracking
analysis
will
be

a

portion of the design traffic considered for bottom-up
cracking analysis
oCVs with spacing between front axle and first rear axle
less than the spacing of transverse joints shall be
considered for top-down cracking analysis
oActual proportion shall be determined from traffic (or)
lld
ax
l
e
l
oa
d
surveys
oDefault value of 50% of design traffic used for bottom-up
cracking
anal sisma beconsidered
cracking
anal
y
sis
ma
y
be

considered
oFor new roads, data from roads of similar classification and
importanceshallbeusedtopredictdesigntraffic importance
shall
be

used
to

predict
design

traffic

Traffic Consideration
•Design Traffic:
o
Sincefrontaxles(steeringaxles)fittedwithsinglewheelson
o
Since
front

axles
(steering
axles)
fitted
with
single
wheels
on

either side cause negligible bottom-up fatigue damage,
rear axles only are considered in the axle load spectrum
(
)
{
}
r
r A
C
n
1 1 365− + ×
=
Where,
C = cumulative no. of CVs durin
g
desi
g
n
p
eriod
r
ggp
A = initial no. of CVs per day in the year when road is
opened to traffic
r = annual growth rate of CVs
n = desi
g
n
p
eriod in
y
ears
gp y

Tem
p
erature Consideration
•Temperature Differential ( ∆T):
p
oTemperature differential between top and bottom surfaces of
concrete slab make it to curl
inducing stresses
oTemperature differential = f(solar radiation received by
pavement surface, wind velocity, thermal diffusivity of
concrete, latitude, longitude, and elevation of the place)
oTemperature differential values shall be estimated from
geographicalparametersandmaterialcharacteristics geographical
parameters
and

material
characteristics
o
Intheabsenceof data pickvaluesfromthetable
o
In
the
absence
of

data
,
pick
values
from

the

table

Tem
p
erature Consideration
•Temperature Differential ( ∆T):
Vii f ihd hi
li d i
p
o
V
ar
iat
ion o
f
temperature w
it
h
d
ept
h

is non-
li
near
d
ur
i
ng
day time and nearly linear during night time
oMax. temperature differential during night is nearly half of
the day time max. temperature differential
oTemperature differentials are positive when slab is convex
upwards during day time and negative when slab is concave
upwards during night time
o
Axl
e
l
oad
st
r
esses
s
h
a
ll
be

co
m
puted
f
o
r f
at
igue
a
n
a
lys
is

o
e oadst essess a beco puted o atguea ayss
when slab is in a curled state due to temperature
differential during day as well as night times

(CRRI 1974) (CRRI
,
1974) ; Telangana

Tem
p
erature Consideration
•Zero Stress Temperature Gradient:
o
CCslabslaidduringdaywillhavehigh+

Tduetointense
p
o
CC
slabs
laid
during

day
will
have
high

+

T
due

to

intense

solar radiation, high air temperature, and chemical reaction
oSlabs will not curl because of +

T
and remain flat
during hardening stage because of its plastic stage
oSlab remains stress free
and corres
p
ondin
g
tem
p
erature
pgp
gradient is termed as zero stress temperature gradient
oExposure of fresh concrete to sun and high air temperature
during hardening stage causes development of
p
ermanent
curl (warping!!!)in CC slabs which is nearly equal to curl
db n ti tmprtr diffrntil(

T) f 5
°
C
cause
d
b
y
n
ega
ti
ve
t
e
mp
e
r
a
t
u
r
e
diff
e
r
e
nti
a
l (
-

T)
o
f

5

°
C
oEquivalent -∆T shall be added algebraically to actual
temperaturedifferentialprevailingatanytime temperature
differential
prevailing
at
any

time

Tem
p
erature Consideration
Difference between curling and warping:
p
•Curlingis the deformation of the slab due to a
difference in tem
p
erature between the surface and
p
bottom of the slab ( temperature gradient)
•Warpingis the deformation of the slab surface profile
due to difference in moisture between the surface and
bottom of the slab ( moisture gradient)
•If a slab surface is allowed to dry and bottom is moist,
the edges of slab will warp upward ( permanent curl!!!)

Tem
p
erature Consideration
•Zero Stress Temperature Gradient:
If

Td i d i 20
°
C

Tf i
p
o
If
max. +

T
d
ur
ing
d
ay
is
20
°
C
,

T
f
or stress computat
ion
can be taken as 15 °C
oHowever, 5 °C reduction in

T is not made
so that design
for bottom-up cracking remains conservative
oIf max. -∆T during night is 10 °C, total effective - ∆T shall be
taken as 15 °C (=10 °C + 5 °C)
oSafer to consider effective negative temperature gradient for
c
h
ec
kin
g
t
h
e

s
lab
f
o
r
top
-
dow
n
c
r
ac
kin
g
caused
by

cec gtesabotop
dow c ac gcausedby
combined effects of traffic loads and night time - ∆T

Tem
p
erature Consideration
•Zero Stress Temperature Gradient:
Cb hl lifi dp
o
C
um
b
ersome to carry out
h
our
ly cumu
lat
ive
f
at
igue
d
amage
analysis
oAssume max. +

T to be constant for six hour period during
day time (10 a.m. to 4 p.m.) and max. -∆T to be constant for
ih iddi ihi (
06
)
s
ix
h
our per
io
d

d
ur
ing n
ig
h
t t
ime
(
0
a.m. to
6
a.m.
)

[morning and evening traffic peak hours???
]
oSlab shall be assumed to be free of warping stresses for
remaining 12 hours for fatigue damage analysis as the fatigue
ddbbidtiflddtt d
amage cause
d
b
y com
bi
ne
d
ac
ti
on o
f

loa
d
an
d

t
empera
t
ure
differential will be insignificant during this period

Embankment Soi
l
•CBR of embankment (500 mm below formation level) shall be
determined for estimating effective CBR of subgradeand
modulus of subgrade reaction (k)for CC pavement design
•Ex
p
ansi
v
e soil strata ma
y

b
e re
p
lace
d
w
ith non-ex
p
ansi
v
e soil
, if
pv ybpdw
pv ,
economically feasible.

Soilswellcanbecontrolledbysurchargeloads(placingswelling

Soil
swell
can

be

controlled
by
surcharge

loads
(placing
swelling

soils in lower part of the embankment)
bd
•Geosynthetics may
b
e use
d
to arrest tension cracks
•Ex
p
ansive soils shall be com
p
acted 1-3% above OMC
pp
•Expansive soils may be modified using lime (or) cement

Characteristics of Sub
g
rade
•Subgrade is considered as a Winkler (dense liquid) foundation •
Strengthof s bgradeise pressedintermsof
modulusof
g

Strength
of

s
u
bgrade

is
e
x
pressed

in

terms
of

modulus
of

subgrade reaction (k)determined using a 75 cm dia. plate.
•One test per kilometre per lane.
•Additional tests shall be
p
erformed with chan
g
e in sub
g
rade soil
,
pgg,
sub-base, nature of formation (cut or fill).
[
]
078
0
21
1
+
=
φ
k
k
where, φis the plate diameter (in m), k
φ
and k
75
are modulus of
bd i(iMP/)ihldi
φ
d75
[
]
078
.
0
21
.
1
75
+
=
φ
φ
k
k
su
b
gra
d
e react
ion
(i
n
MP
a
/
m
)
w
it
h
p
late
di
ameter
φ
an
d

75
cm,
respectively

Characteristics of Sub
g
rade
•Strength of subgrade is affected by its moisture content •
Diffic lt(
timeconsumingandexpensive
)todetermine
k
g

Diffic
u
lt
(
time
consuming
and
expensive
)
to

determine
k
-
value at different densities and moisture contents
•k-
v
alue estimated from soaked CBR value:
Soaked k-value, Soaked k-value, CBR, % MPa/m CBR, % MPa/m
2211055
3281562 4352069 54250140 7 48 100 220

Characteristics of Sub
g
rade
•If CBR of 500 mm thick compacted subgrade is significantly
greater than the embankment, effective CBR shall be estimated
g

Characteristics of Sub
g
rade
•Min. recommended design CBR of subgrade is 8% •
In
sit CBRof s bgradecanalsobedeterminedfromD namic
g

In
-
sit
u
CBR

of

s
u
bgrade
can
also

be
determined
from

D
y
namic

Cone Penetrometer (DCP) using 60 °cone [ASTM D 6951]:
(
)
(
)
N
l
12
1
465
2
CBR
l
Where
, N
DCP
is the rate of cone
p
enetration
(
mm
/
blow
)

(
)
(
)
DCP 10 10
N
l
og
12
.
1
465
.
2
CBR
l
og

=
,
DCP
p(/)
•k-value can also be determined from Falling Weight
Deflectometer(FWD)tests Deflectometer
(FWD)

tests
•k-value of subgrade back-calculated from FWD test data is the
dik
l
d
ynam
ic
k
-
v
a
lue
•Static k-value is 50% of dynamic k-value

Characteristics of Sub
g
rade
•Filter and drainage layers shall be provided above the subgrade
for drainage of water to prevent:
g
i.Excessive softeningof subgrade and sub-base, and ii.Erosionof subgrade and sub-base under adverse moisture
conditions and heavy dynamic loads
•Geosynthetics may be used at the interface of subgrade and
granular sub-base layer for effective filtration (geotextiles, and
dd d
geocomposites
)
an
d

d
rainage (geotextiles, geonets, an
d

geocomposites)
•Geosynthetics will not allow migration of subgrade soil fines into
the granular sub-base layer

Characteristics of Sub-base
dfbld lb
•Provi
d
es a uni
f
orm, sta
bl
e, an
d
permanent support to CC s
la
b

Shallhave
sufficientstrength
topreventitsdisintegrationand
Shall
have
sufficient
strength
to

prevent
its
disintegration
and

erosion under heavy traffic and adverse environmental conditions
(excessive moisture, freezing and thawing)
•Recommended to use a Dry Lean Concrete (DLC) as sub-base
overGSBwith
7
-
dayavg compressivestrengthof 7MPa
(10
over
GSB

with
7
-
day
avg
.
compressive
strength
of

7

MPa
(10

MPa in IRC:58:2012)
•For PQC bonded to DLC, avg. 7-day strength of DLC > 10MPa

Characteristics of Sub-base
ff hllb hdhbhh
•Sur
f
ace o
f
DLC s
h
a
ll
b
e roug
h
ene
d
wit
h
wire
b
rus
h
wit
h
in 3 to 6
hours of laying
•Min. recommended thickness of DLC for major roads is 150 mm
C d( ) bili d b
blbd

C
emente
d
(
or
)
sta
bili
ze
d
su
b
-
b
ase may a
lso
b
e use
d


Cementtreatedsub
-
basewhenusedshallhaveamin28
-
day
Cement
treated
sub
base
when

used
shall
have
a

min

28
day

characteristic compressive strength of 7 MPa and loss of weight
shall not exceed 14% after 12 cycles of freeze-thaw simulation

Characteristics of Sub-base
•Appropriate blanket course shall be used in addition to sub-
baseon problematic subgrade soils (clayey and expansive soils)
•k-values of granular and cement treated sub-base: •
ForCCslabslaidoverabituminoussub
-
base,k
-
valueshall
For
CC
slabs

laid
over

a
bituminous
sub
base,
k
value
shall

be adopted from IRC:SP:76

Characteristics of Sub-base
•k-values of DLC sub-base laid over granular sub-base consisting
of filter and drainage layers:
•An upper limit of 300 MPa/m is recommended considering the
loss of subgrade support expected by heavy traffic
•Contribution of granular sub-base placed below DLC layer can
be i
g
nored for estimatin
g
effective kof the foundation
gg

Se
p
aration La
y
er b
/
w DLC and CC Slab
•Interface between (b/w) DLC and CC slab shall be smooth to
reduce inter layer friction and to permit relative movements
py/
•Debonding layer of min. 125 µm polythene sheet used in India •
Waxbasedcompoundinplaceof plasticsheetmaybeused(used

Wax
based
compound

in
place
of

plastic
sheet
may
be

used
(used

in one of the National Highways projects in India)

Chokestone(NMAS95mm;smallsizeof uniformlygraded

Choke
stone

(NMAS

9
.5
mm;

small
size
of

uniformly

graded

stone layer of 13 to 25 mm thickness) used in USA

Srf dr inm b d

S
u
rf
ace
dr
ess
in
g
m
ay
b
e use
d
•Debonding layer is not necessary if CC slab is placed over BC
lill id iflb layer as
it a
ll
ows expans
ion an
d
contract
ion o
f
s
la
b
•Non-woven geotextile of 5-6 mm thickness ca be used

Concrete Stren
g
th
•Flexural strength of CC is required for design of CC slabs

CanbeobtainedfromlaboratorytestsonCCbeam
g
Can
be

obtained
from

laboratory
tests
on

CC

beam
•Otherwise, use:
h
f
ifl l h( dl f )iMP d
f
ck cr
f f7.0=
wh
ere,
f
cr
is
fl
exura
l strengt
h
(
mo
d
u
lus o
f
rupture
)

in
MP
a, an
d
f
ck
is characteristic compressive cube strength of CC in MPa Fl l h f P Q li C (PQC)
hll

Fl
exura
l strengt
h
o
f

P
avement
Q
ua
li
ty
C
oncrete
(PQC)
s
h
a
ll
not
be less than 4.5 MPa
dbdddb
•90
d
ays strength shall
b
e permitte
d
(instea
d
of 28
d
ays)
b
ecause
no. of load repetitions is less during initial 90 days and also has
negligibleeffectoncumulativefatiguedamageof CC negligible
effect
on

cumulative
fatigue
damage
of

CC
•90 days strength of CC can be obtained by increasing 28 days
strength
byafactorof 110
strength
by
a

factor
of

1
.
10

Concrete Stren
g
th
•Target mean flexural strength while designing the mix shall be
such that there is 95% probability that the characteristic strength
g
w
ould be achieved when the mix is produced in the field
•Tar
g
et mean flexural stren
g
th at 28
d
a
y
s
(
in MPa
)
:
ggdy()
σ
a cr cr
Z f f
+ =
'
Where,
f
ischaracteristicflexuralstrengthat28days MPa
f
cr
is
characteristic
flexural
strength
at

28
days
,
MPa
Z
a
is a factor corresponding to desired confidence
ll(196f5%l ll) leve
l (1
.96
f
or
5%
to
lerance
leve
l)
σ
is standard deviation of field test samples, MPa

Concrete Stren
g
th
•Modulus of elasticity (E) and Poisson’s ratio ( µ) of CC vary with
concrete materials and affects CC strength
g
•E increases and µdecreases with increase in CC strength •E and µmay be determined experimentall
y
•25% variation in these values will have ne
g
li
g
ible influenceof
gg
the flexural strength of CC

Forstressanalysisof CCslabwith28
-
dayflexuralstrengthof 45
For
stress
analysis
of

CC

slab
with

28
-
day
flexural
strength

of

4
.5

MPa (4.95 MPa for 90 days), E is 30,000 MPa and µis 0.15
C ffi i f h l i f (
)
dd

C
oe
ffi
c
ient o
f
t
h
erma
l expans
ion o
f
concrete
(
α
)
d
epen
d
s on
type of aggregateused in CC and for design purpose, αshall be
takenas10
×
10
-6
per
°
C
taken
as

10
×
10
per

C

Fati
g
ue Behaviour of CC
•Repeated application of flexural stresses due to wheel loads
causes progressive fatigue damage in CC slab in the form of
g
gradual development of micro-cracks especially when stress ratio (SR) is high.
•SR is defined as the ratio between applied flexural stress due to
wheel load and flexural strength (modulus of rupture) of CC
2577
4
45.0 for
268.3


<
∞=SR
N
55.0 45.0 when
4325 .0
2577 .
4





⎢ ⎣⎡

=SR
SR
N
55.0 for
0828 .0
9718 .0
log
10
>

=SR
SR
N

Fati
g
ue Behaviour of CC
•With increase in SR, no. of load repetitions to cause cracking
decreases
g
•N value is used for checking the adequacy of pavement slab
bd
ihhi
b
ase
d
on M
i
ner’s
h
ypot
h
es
i
s

Fatigueresistancenotconsumedbyrepetitionsof aparticular

Fatigue
resistance
not
consumed
by
repetitions
of
a
particular

wheel load is available for repetitions of other wheel loads
•Above fatigue criteria developed by Portland Cement
A
ssociation (PCA, 1980) are very conservative and can be used
for analysis of bottom-up and top-down cracking

Fati
g
ue Behaviour of CC
•New fatigue model for CC pavement was developed by American
Concrete Pavement Association
g
•This model is same as PCA model for a reliability of 90%
{
}
217.0
24.10
log




R
SR
{
}
10
10
0112 .0
log
log



⎢ ⎣⎡

=
R
SR
N
r
r
N
r
is fatigue life at load level r
SR
r
is stress ratio at load level r = (stress caused at load level r/ modulus of rupture) R is reliabilit
y
taken as 0.90 for 90% reliabilit
y
where 10% of CC
yy
slab is expected to undergo fatigue cracking at the end of design
period

Fati
g
ue Behaviour of CC
Reliabilityvaluesfordifferentcategoriesof roads:
g
Reliability
values
for

different

categories
of

roads:

V
illage roads: 60%
•District roads: 70%
•State highways: 80%

Nationalhighways:
90%
National
highways:
90%
•Expressways: 90%

Critical Stress Condition
•Severest combination of various factors that induce max.
stress in the CC slab is the critical stress condition
•Flexural stress due to combined action of wheel loads and
tem
p
erature differentia
l
b
et
w
een to
p
an
d
b
ottom faces of CC
p
bw p db
slab is considered for design of pavement thickness

Effectof moistureisoppositetothatof temperature
andis

Effect
of

moisture
is
opposite
to

that

of

temperature
and

is

not considered critical
bbd
•Flexural stress at
b
ottom face of the CC sla
b
is maximum
d
uring
day time when axle loads act at the middle of the CC slab when
temperaturegradientispositiveandleadstobottom
upcracking
temperature
gradient
is

positive
and

leads
to

bottom
-
up

cracking

(BUC)

Critical Stress Condition
Day time →positive temperature gradient →axle load acting at the
centre of slab →maximum flexural stress at bottom face of cement
concreteslab

bottom
upcracking
concrete
slab


bottom
-
up

cracking

Critical Stress Condition
Placement of axles for maximum edge flexural stress at bottom
of slab without tied concrete shoulders
Stresscausedbysingleaxle>tandemaxle>tridemaxle Stress
caused
by

single
axle

>
tandem
axle
>

tridem
axle
Max. stress occurs at same locations for tied concrete shoulders

Critical Stress Condition
Ni h i

idi

lld i l
Ni
g
h
t t
ime

negat
ive temperature gra
di
ent

ax
le
loa
d
act
ing c
lose
to transverse joints →maximum flexural stress at top face of the
cementconcreteslab

top
-
downcracking(TDC)
cement
concrete
slab


top
down

cracking
(TDC)

Critical Stress Condition
Different axle load positions causing tensile stress at top face of
the CC slab with tied concrete shoulder
Built-in permanent curl induced during CC slab curing further aggravatestheproblem aggravates
the
problem

Calculation of Flexural Stress
•For an axle load of 200 kN and ∆T = 0 °C with tied CC
shoulder, flexural stress decrease with increase in k-values for all
thicknesses

Calculation of Flexural Stress
•For an axle load of 200 kN and ∆T = 17 °C with tied CC
shoulder, warping stresses are higher for thicker slabs and results
in higher flexural stresses in slabs for higher k-
v
alues while
flexural stresses are lower for higher k-values for thinner slabs
No effect of k-value on flexural stress (
h = 270 mm
)
() Increasing k-value does not help in thickness design due to higher curling stresses caused by a stiffer support

Calculation of Flexural Stress
•For BUC, combination of load and nonlinear positive
temperature differentialis considered
•For TDC, combination of load and linear temperature
differentia
l
is consi
d
ere
d
dd
•In BUC case, single axle load causes largest edge stress followed
bytandemandtridemaxles by
tandem
and

tridem
axles
•Tridem axles are not considered for BUC analysisbecause of
dd bd
the lower flexural stresses in
d
uce
d
in CC sla
b
s
d
ue to these axles
•In TDC case, onl
y
one axle of sin
g
le/tandem/tridem axle units is
yg
considered for analysis in combination with front axle

Frontaxleloadisassumedtobe50%of weightof oneaxle Front
axle
load

is
assumed
to

be

50%
of

weight
of

one

axle

of the rear axle unit (single/tandem/tridem) for analysis

Calculation of Flexural Stress
Following cases are considered for the analysis:

Bottom
-
upcracking
Bottom
up
cracking
oPavement with tied concrete shoulders for single rear axle oPavement without concrete shoulders for single rear axle
oPavement with tied concrete shoulders for tandem rear axle
oPavement without concrete shoulders for tandem rear axle

Top
-
downcracking
Top
-
down
cracking
oPavements with and without dowel bars having front
(steering)axlewithsingletyresandthefirstaxleof therear (steering)
axle
with
single
tyres
and

the
first

axle
of

the
rear

axle unit (single/tandem/tridem) placed on the same panel

Calculation of Flexural Stress
•For heavy traffic conditions, dowel bars are provided across
transverse joints for load transfer
•Tied concrete shoulders are necessary for high volume roads •Tied concrete shoulders and dowel bars are not warranted for
traffic volumes less than 450 CVPD
•Terminal load transfer efficiency (LTE) for dowelled
transverse joints is taken as 50% for stress computation
•Terminal LTE for tied joints between the slab and concrete
shoulder is taken as 40% for stress com
p
utation
p
•MEPDG recommends LTE of 60% and 50% respectively for
dowelledandtiedjoints dowelled
and

tied
joints

Calculation of Flexural Stress
•Considering a slab size as 3.5 m x 4.5 m, charts are available to
compute flexural stresses for combinations of (i) slab thickness,
(ii) modulus of subgrade reaction, (iii) axle load, (iv) axle type (single, tandem), (v) temperature differential, (vi) with and
ith tti d t h ld
with
ou
t
ti
e
d
concre
t
e s
h
ou
ld
er
•Linear interpolation is permitted between the charts
•Regression equations are available for computation of flexural
stresses for BUC and TDC cases
•Single regression equation for TDC case, and separate regression
equationsforBUCcasefordifferentpavementtypesand equations
for

BUC

case
for

different
pavement
types
and

foundation strengths
P d lfil il bl l ihIRC582015

P
rogramme
d
exce
l fil
e ava
il
a
bl
e a
long w
it
h
IRC
:58
:2015

Re
g
ression E
q
uations for Flexural Stress
BUC Case (single axle with tied concrete shoulder):
gq

Re
g
ression E
q
uations for Flexural Stress
BUC Case (single axle without tied concrete shoulder):
gq

Re
g
ression E
q
uations for Flexural Stress
BUC Case (tandem axle with tied concrete shoulder):
gq

Re
g
ression E
q
uations for Flexural Stress
BUC Case (tandem axle without tied concrete shoulder):
gq

Re
g
ression E
q
uations for Flexural Stress
TDC Case:
gq

Re
g
ression E
q
uations for Flexural Stress
gq

Cumulative Fati
g
ue Dama
g
e
(
CFD
)
:
•Pavement should be checked for cumulative bottom-up and top-
down fatigue damage.
gg()
•For BUC analysis, flexural stress at the edge due to the combined
action of single or tandem rear axle load and positive temperature
differential cycles is considered and determined from either
stress charts or regression equations .
•For TDC analysis, flexural stre ss due to axle loads and negative
differential can be determined from equation.
•CC slab undergoes fatigue damage through crack growth induced
by repeated cycles of loading.
•Cumulative fatigue damage caused to the slab during its service
life should be equal to or less than one.

Cumulative Fati
g
ue Dama
g
e
(
CFD
)
:
gg()

Desi
g
n Criterion:
•If CFD (BUC) + CFD (TDC) ≤1, pavement will be safe from
cracking
g
•Pavement is deemed to have failed if sum of cumulative damages
is greater than 1
•In India, 6 h traffic for fatigue analysis for day and night hours
may not be valid for all regions
•Designers are recommended to carry out hourly or 2 hourly
fatigue damage analysis for all 24 h to examine pavement safety
MlldidCC dilkihih

M
any we
ll
d
es
igne
d
CC
pavements
di
sp
lay crac
k
s w
it
hi
n a s
h
ort
period of 5 years due to loss of support caused by permanent
deformationanderosionof GSBandsubgradeinpresenceof deformation
and
erosion

of

GSB

and

subgrade
in

presence
of

water and heavy loads, locked dowel bars, shrinkage cracks etc
rather than fati
g
ue cracks caused b
y
structural deficienc
y
gy y

Erosion Consideration:
•Important mode of failure in rigid pavements.

Erosioniscausedbytandemandmulti
-
axlevehiclesandsingle
Erosion
is
caused
by
tandem

and
multi
axle
vehicles
and
single

axles are responsible for fatigue cracking of slabs.

Tandem,tridem,andmulti
-
axlevehiclesformalargepercentage
Tandem,
tridem,

and
multi
axle
vehicles
form

a

large
percentage

of total CVs on Highways in India.

ErosiondataisnotavailableinIndiaanditisverymuchessential Erosion
data
is
not

available
in

India
and

it
is
very
much

essential

to collect this data for revision of future guidelines.

Erosionoccurswhenuntreatedsub
-
baseandsubgradematerials
Erosion
occurs
when

untreated
sub
base
and
subgrade

materials

are used.

Erosiondependsonqualityof subgrade sub
-
base climatic
Erosion

depends
on

quality
of

subgrade
,
sub
base
,
climatic

conditions, and gross weight of the vehicles.

GPRorFWDcanindicateextentof voidsbelowDLClayer GPR
or

FWD

can

indicate
extent
of

voids
below
DLC

layer

Draina
g
e La
y
er:
•New pavements are impermeable but with passage of time,
joints, median and cracks allow water to infiltrate into pavement
gy
•Entrapped water (due to infiltration of moisture or thawing in
snow bound areas) in the unbound layers causes erosion of the
foundation material because pore water pressure caused by tandem and tridem axle loads is substantially high Pdflidhddidl

P
avement
d
e
fl
ect
ion
d
ue to
h
eavy tan
d
em an
d
tr
id
em ax
les can
be up to 1.0 mm and results in formation of voids spaces below
CCslabduetopermanentdeformationof foundationmaterial CC
slab

due
to

permanent
deformation

of

foundation
material
•Essential to provide a drainage layer together with a filter/
se
p
aration la
y
er beneath the sub-base throu
g
hout the road width
py
g
•Filter/separation layer prevents fines from pumping up from
sub
g
rade to the draina
g
e la
y
er
ggy

Draina
g
e La
y
er:
•Amount of water infiltrating into the pavement should be
assessed and a drainage layer having required permeability need
gy
to be designed
•Min. permeability of ≥300 m/day is recommended •Drainage layer is very crucial for highways in areas having annual
rainfall ≥1000 mm
•Drainage layer can be treated with 2 to 2.5% bitumen/cement or
2.5 to 3% bitumen emulsion to obtain a stable platform to permit
movementof constructiontrafficwithoutanydisplacementor movement
of

construction
traffic
without
any

displacement
or

shoving of open graded aggregates

If granularlayersarenotrequiredbecauseof highsubgrade If
granular
layers
are
not

required

because
of

high

subgrade

strength, geosynthetics can be used for separation and drainage
w
ith reduced thickness of
g
ranular la
y
er over sub
g
rade
gy g

Draina
g
e La
y
er:
•Laboratory tests on GSB gradations shown in MORTH (2013)
resulted in permeability less than 12 m/day (considered poor for
gy
drainage layer)
•Drainage layer shall have good permeability and stability •However, more permeable materials will have low stability

Properbalanceof permeabilityandstabilityisdesirable Proper

balance
of

permeability
and
stability
is
desirable
•Stabilization is necessary for stability of open graded aggregates
Cidifdili d

C
onservat
ive
d
es
ign
f
or
d
ra
inage
layer
is necessary to guar
d

against pavement failure observed in India within 5 years of
constructionduetodeformationinGSBandsubgradedueto construction
due
to

deformation

in

GSB

and
subgrade

due
to

heavy loads and moisture

VariousgradationsareinuseinUSAfordrainagelayer Various
gradations
are

in
use

in

USA
for

drainage
layer

Draina
g
e La
y
er:
•In US, CC slab is directly laid over cement treated drainage layer
known as permeable base where stability of drainage layer is
gy
crucial for good performance of pavemen
t
•Open graded cement treated permeable base is also required to
allow the construction traffic
•In India, DLC layer bears the construction traffic and also
provides a strong support to CC slab
•Grading 4, 6, 7 (see Table in next slide) containing higher fines
can be used without stabilization and can provide a good balance
between permeability and stability
•For other gradations (1, 2, 3, 5, 8), stabilization is necessary to
impart stability

Draina
g
e La
y
er:
gy
Sieve
size, mm
AASHTO57
cement/
bitumen
California
bitumen
treated
Wisconsin
cement
treated
New Jersey
bitumen
treated
Virginia
cement
treated
AASHTO93
grading
45and6
bitumen

treated
treated
treated
treated
treated
4
,
5
,
and

6

(unstabilized)
12345678
37.5 100 - - - - - - -
25.4 95-100 100 100 100 100 - - -
19 5
-
96
-
100
90
-
100
95
-
100
-
100
100
100
19
.5
96
100
90
100
95
100
100
100
100
12.5 25-60 35-65 - 85-100 25-60 81.5 79.5 75
9.5 - 20-45 20-55 60-90 - 72.5 69.5 63
4.75 0-10 0-10 0-10 15-25 0-10 49 43.5 32
2.36 0-5 0-5 0-5 2-10 0-5 29.5 22 5.8
1.18 - - - - - 16 5 0
0.3 - - - - - 0 0 0
0 075
0
2
0
2
0
5
2
5
0
0
0
0
.075
0
-
2
0
-
2
0
-
5
2
-
5
-
0
0
0
Permeability,
m/day
6600 5000 3000 300 3000 350 850 950

Draina
g
e La
y
er:
•Aggregates used in highly permeable drainage layers are
predominantly coarser than 4.75 mm
gy
•Filter/separation layer placed above subgrade must prevent
intermixing of subgrade soil and drainage layer (refer to IRC:37)
•Effect of bitumen treatment on permeability (cement treatment
will have similar effect):
Aggregate
size, mm
Permeability, m/day
Untreated
T
reated with 2% bitumen
38 to 25.4 mm 46000 40000
20 to 9.5 mm 33000 31600
4.75 to 2.36 mm 2600 2000

Draina
g
e La
y
er:
•It may not always be possible to determine permeability of
drainage layer
gy
•Permeability of a drainage layer depends on effective aggregate
size (D
10
) and uniformity coefficient (C
u
)
•C
u
= D
60
/D
10
; D
60
is sieve size through which 60% passes; C
u
is
an indicator of the spread of particle sizes between 10 and 60%
•Greater the value of D
10
, greater is the permeability

D
10
>2mmisadoptedforhighlypermeableaggregates
D
10
>

2

mm

is

adopted
for

highly
permeable
aggregates
•C
u
= 1 for single size aggregates
C
40f d d d

C
u
=
40
f
or
d
ense gra
d
e
d
aggregates
•Lower the value of C
u
, greater is the permeability (lower
bili !)
sta
bili
ty
!)

Draina
g
e La
y
er:
•C
u
should be between 2 and 8 for a good drainage layer

If C
<
4,drainagelayerhashighpermeabilitybutlayerwouldbe gy
If
C
u
4,
drainage
layer
has
high

permeability
but
layer
would
be

unstable which must be stabilized with either cement or bitumen
for heavy traffic pavements
•L.A. abrasion value of aggregates used for drainage layer must be
less than 40% to limit degradation during compaction.
•Thickness of drainage layer will depend on permeability and
quantity of water infiltrating into the pavement
•Duration of rainfall is critical instead of rainfall intensity for
infiltration of water into the pavement
•Infiltration rate (I
c
) through joints or cracks is 0.223 m
3
/day/m
and can be used for design of the drainage layer

Draina
g
e La
y
er:
•Permeability shall be selected such that total outflow capacity of
the drainage layer is greater than the inflow of rainwater into the
gy
pavemen
t

Infiltrationrateperunitarea(q
):

Infiltration
rate
per

unit
area
(q
i):

Draina
g
e La
y
er:
•Water entering into the pavement from earthen median can
damage the pavement if care is not taken to prevent entry of
gy
w
ater along with fines into the drainage layer

Usageof filterornonwovengeotextilelayercanminimize

Usage
of

filter
or

nonwoven

geotextile
layer
can
minimize

choking of drainage layer with soils entering into the drainage
la
y
er near the median
y
•Exposed drainage layer along embankment slope shall not be
r d ith rth p i ll hil r tif in r i n f id
cove
r
e
d
w
ith
ea
rth
es
p
ec
ia
ll
y w
hil
e
r
ec
tif
y
in
g e
r
os
io
n
o
f
s
id
e
slopes after rain
•Blockage of a drainage layer may cause a much serious problem
than with no drainage layer

Draina
g
e La
y
er:
A four-lane divided CC pavement will be constructed for a high traffic
volume road in an area having an annual rainfall of 1500 mm/year.
gy
The width of each carriageway will be 7.0 m with 2.5 m (1.5 m CC +
1.0 m unpaved) width shoulders will be provided. Transverse joint
p i illb 45 Th hi h h l it di l di t f 3%
s
p
ac
ing w
ill
b
e
4
.5
m.
Th
e
hi
g
h
way
h
as a
long
it
u
di
na
l gra
di
en
t
o
f

3%

and a camber of 2.5%. Side slopes of embankment are 2:1 (horizontal
:vertical).Thepavementhasa300mmthickCCslabplacedover150 : vertical).
The

pavement
has

a
300
mm

thick
CC

slab
placed
over

150

mm thick DLC layer. Estimate the requirement of permeability of the
drainage layer material to be used if the layer thickness is 150 mm.
•Combined thickness of slab & DLC layer = 300+150 = 450 mm

DrainagelayerwillbeprovidedbelowDLClayeratadepthof Drainage
layer
will
be

provided
below
DLC

layer
at
a

depth
of

450 mm from the pavement surface

Drainagelayerwillbeextendedtofullwidthof embankment Drainage
layer
will
be

extended
to

full
width
of

embankment

Draina
g
e La
y
er:
•Width of drainage layer = 7 m (pavement) + 2.5 m (shoulder) +
2 x 0.45 m = 10.4 m.
gy
•Direction of flow of water along AD (diagonal)
•AB = 10.4 m; AC = 10.4x(0.03/0.025) = 12.48 m; AD = 16.24 m
•Drop of elevation along AC = 12.48 x 0.03 = 0.374 m
•Dro
p
of elevation alon
g
CD = 10.4 x 0.025 = 0.26 m
pg

Draina
g
e La
y
er:
Drop of elevation along AD = 0.374 + 0.260 = 0.634 m
Gradient alon
g
AD = I = dro
p
alon
g
AD
/
len
g
th of AD =
gy
gpg/g
0.634/16.24 = 0.039
I
c
= crack infiltration rate = 0.223 m
3
/day/m
N
c
= no. of longitudinal joints/cracks = 3 (one joint between lanes +
one joint between lane and shoulder + one joint between paved
shoulder and edge)
W
p
= width of pavement subjected. to infiltration = 7 + 2.5 = 9.5 m W
c
= length of transverse cracks or
joints = 7 + 1.5 = 8.5 m
C
s
= spacing of transverse joints = 4.5 m
K
p
= rate of infiltration through un-cracked pavement surface = 0
q
i
= rate of infiltration of water into pavement = 0.115 m
3
/day/m
2

Draina
g
e La
y
er:
Amount of water infiltrated per metre length flowing along the path
AD of the drainage layer = 16.24 x 0.115 = 1.868 m
3
/day/m
gy
Rate of flow through drainage layer, Q = KIA I = 0.039; KA = Q/I = 1.868/0.039 = 47.89 A1015015
2
(i150dil)
A
=
1
x
0
.15
=
0
.15
m
2
(
assum
ing
150
mm
d
ra
inage
layer
)
K
=
requiredcoefficientof permeability
=
47.89/0.15
=
319m/day
K

required
coefficient
of

permeability

47.89/0.15

319
m/day
If thickness of drainage layer is 300 mm, K4789/030160/d K
=
47
.89/0
.30
=
160
m
/d
a
y

Tied Concrete Shoulder and
•Used to
p
rotect the ed
g
e of hi
g
h volume hi
g
hwa
y
p
avements
Widened Outer Lane:
pgggyp
•Outer lanes of CC pavements are widened by 0.5 to 0.6 mfor
2-lane 2-way roads to reduce flexural stresses in the wheel path
•Widened outer lane functions as a monolithic CC shoulder
reduces edge flexural stress by 20 to 30%
Rlidi f hik

R
esu
l
ts
i
n re
d
uct
i
on o
f
pavement t
hi
c
k
ness
•Total quantity of CC remains nearly the same as that without
shoulder shoulder
•Rough texture to the widened portions improves safety of
v
ehicles es
p
eciall
y
durin
g
ni
g
ht hours
py gg
•Thickness of CC slab with widened outer lane and tied CC
shoulder are nearly the same

Bonded Ri
g
id Pavement:
•CC pavement laid over a sustained slope on ghat sections may
slip if a debonding layer of polythene membrane is provided
g
between CC slab and DLC layer
•Eliminating polythene separation membrane between CC slab
dDLC b
bl li
li hi i
fb h
an
d
DLC
su
b
-
b
ase
layer resu
lts
in mono
li
t
hi
c act
i
ono
f

b
ot
h

the layers which in turn reduces the pavement thickness

DLClayershallbemaderoughwithwirebrushwithin3to6h

DLC

layer
shall
be

made
rough

with
wire

brush

within
3
to

6

h

of placement and a bonding agent of water and cement slurry
shall be a
pp
lied over the surface before la
y
in
g
of P
Q
C
pp y g Q
•For monolithic slab, transverse joints shall be made in DLC by
cutting grooves up to 1/3
rd
of its depth at same locations where
transverse
joints are to be provided in PQC layer to prevent
random reflection cracking of PQC layer due to cracks in un-
jointedDLClayer jointed
DLC

layer

Bonded Ri
g
id Pavement:
•7 day compressive strength of DLC layer in bonded rigid
pavement shall not be less than 10 MPa
g
•Method of equivalent flexural stiffness is used for design of
bonded pavement
•GSBof 200 to 250 mm shall be provided below DLC layer for
bonded CC pavement for filtration and drainage and estimate
ff i
k
lfbd
GSB bi i
e
ff
ect
ive
k
-
v
a
lue o
f
su
b
gra
d
e-
GSB
com
bi
nat
ion
•Total slab thickness (h) over GSB layer is determined for given
trafficandotherdesignparameters traffic
and

other

design
parameters
•Part of PQC thickness (h) shall be replaced by 150 mm DLC
suchthatcombinedflexuralstiffnessof pavementslablayer(h
)
such
that
combined

flexural
stiffness
of

pavement
slab

layer
(h
1
)

and DLC layer (h
2
) is ≥PQC slab (h) flexural stiffness over GSB

Bonded Ri
g
id Pavement:
g
•If the design slab thickness over GSB + Subgrade foundation is
“h’, and if it is proposed to provide DLC of thickness ‘h
2

bonded to CC slab of thickness ‘h
1
’, then “h
1
” can be obtained
by equating the flexural stiffness of design slab to the
bi d iff f DLCl dCC l b
com
bi
ne
d
st
iff
ness o
f

DLC

l
ayer an
d
CC
s
l
a
b

Bonded Ri
g
id Pavement:
•Recall the equation discussed in KENSLABS
g
(
)
2 2
5
0
5
0
h
h
h
E
h
+

⎜⎛
+
•Neutral axis depth:
(
)
2
2 1 2
1
1
5.
0
5.
0
E
h
h
h
E
h
d

⎜⎛
+

⎜⎝
+
=
2
1
2
1
h
E
E
h


⎜⎝⎛
+

Bonded Ri
g
id Pavement:
g
•Flexural stiffness of P
Q
C:
Q
•Flexural stiffness of DLC: •28-day compressive strength of DLC having 7-day compressive
stren
g
th of 10 MPa is 13.6 MPa
g
•E of DLC = 5000(f
ck
)
0.5
= 18439 MPa

T
hin
D
L
C
l
aye
r m
ay
c
r
ac
k
due
to

s
hrink
age,
co
n
t
r
act
io
n
&

t
r
a
ffi
c
T D C aye ayc ac duetos age,co t acto &t a c
•Effective E of DLC = 1000f
ck
= 13600 MPa [Reduced E!!!]

Poisson
’sratioof DLC
=
0.2
Poissons
ratio
of

DLC

0.2

CC Slab Desi
g
n Procedure:
1)Specify design values for various parameters (n, r, A, lanes, etc.)
2
)
Select trial desi
g
n thickness of CC slab
g
)
g
3)Compute repetition of axle loads of different magnitudes and
categories during design life
4)Find proportion of axle load repetitions operating during day and
night times
5)Estimate axle load repetitions in 6-h period during day time (max.
+∆T is assumed to remain constant during 6-h for BUC analysis)
6)Estimate axle load repetitions in 6-h period during night time
(max. -∆T is taken as half of + ∆T; to take into account
tl

Tf5
°
C
hll
bdddt

Tf TDC
permanen
t
cur
l, -

T
o
f

5
°
C
s
h
a
ll
b
e a
dd
e
d
t
o

T
f
or
TDC

analysis; vehicles with spacing b/w steering axle and first rear axle
<
transversejointspacingshallbeconsideredforTDCanalysis) transverse
joint
spacing
shall
be

considered
for

TDC

analysis)

CC Slab Desi
g
n Procedure:
7)Compute flexural stresses at edge due to single and tandem axle
loads for combined effect of axle loads and + ∆T during day time
g
(determine SR and evaluate CFD for single and tandem loads)
8)Compute flexural stress in the central area of the CC slab with
front axle near to approaching transverse joint and front rear axle
lfllijiih ld

T(d i
c
lose to
f
o
ll
ow
ing
jo
int
in t
h
e same pane
l un
d
er -

T
(d
eterm
ine
SR and evaluate CFD for different axle loads for TDC)
9)Sum of CFD for BUC and TDC shall be less than 1.0

Desi
g
n Exam
p
le-1:
A CC pavement is to be designed for a 4-lane divided NH with 2
lanes in each direction in Bihar. Design the pavement for 30 years
gp
w
ith 3.5 m lane width and 4.5 m transverse
joint spacing. It is
expected that the road will carry, in the year of completion
t ti b t3000CVPDi hdi ti A l l d
cons
t
ruc
ti
on, a
b
ou
t

3000
CVPD

in eac
h
di
rec
ti
on.
A
x
le
loa
d
survey
of CVs indicated that the proportion of front single axle, rear single
axle,reartandemaxle,andreartridemaxleare45%,15%,25%,and axle,
rear

tandem

axle,
and

rear

tridem
axle
are

45%,
15%,
25%,
and

15%, respectively. The proportion of CVs with spacing between front
axle and first rear axle less than 4.5 m is 55%. Traffic count indicates
that 60% of CVs travel during night time (6 p.m. to 6 a.m.). The avg.
no. of axles per CV is 2.35 (due to the presence of multi-axle
ehicles) Effecti eCBRof compacteds bgradeis8% DesignaCC
vehicles)
.
Effecti
v
e
CBR

of

compacted
s
u
bgrade
is

8%
.
Design

a
CC

pavement for the following: (i) with tied CC shoulder with doweled
trans
v
erse
joint
, (
ii
)
w
ithout tie
d
CC shoul
d
er an
d

w
ithout
d
o
w
ele
d

vj,()w d ddw dwd
transverse joint, (iii) with widened outer lane, (iv) bonded case.

Desi
g
n Exam
p
le-1:
gp
Axle Load Spectrum:

Desi
g
n Exam
p
le-1:
gp
Typical Cross-section of a CC Pavement:

Desi
g
n Exam
p
le-1:
gp
Selection of Modulus of Subgrade Reaction:
•Effective CBR of compacted subgrade = 8%
•Modulus of subgrade reaction = 50.3 MPa/m •Provide 150 mm GSB
•Provide 150 mm DLC sub-base with min. 7-da
y
com
p
ressive
yp
strength of 7 MPa

Effectivemodulusof subgradereactionof combinedfoundation

Effective
modulus

of

subgrade

reaction
of

combined

foundation

(subgrade + GSB + DLC sub-base) = 285 MPa/m
Pid125
db di l f lh h b CC

P
rov
id
e
125
µ
m
d
e
b
on
di
ng
layer o
f
po
lyt
h
ene s
h
eet
b
etween
CC

slab and DLC sub-base

Desi
g
n Exam
p
le-1:
gp
Selection of Flexural Strength of CC:
•28-day compressive strength of CC = 40 MPa
•28-day flexural strength of CC = 4.5 MPa •90-day flexural strength of CC = 1.10*4.5 = 4.95 MPa

Desi
g
n Exam
p
le-1:
gp
Selection of Design Traffic for Fatigue Analysis:
•Design period = 30 years
•Annual growth rate of CVs = 0.075 •Traffic in the predominant direction = 3000 CVPD
•2-
w
a
y
traffic = 2*3000 = 6000 CVPD
y
•Total 2-way traffic during design period is 226,444,692 CVs
()
{
}
()
{
}
075
0
1 075.01 6000 365 1 1 365
30
− + ×
=
− + ×
=
r
r A
C
n
075
.
0
r

Desi
g
n Exam
p
le-1:
gp
Selection of Design Traffic for Fatigue Analysis:
•Avg. no. of axles (steering/single/tandem/tridem) per CV is 2.35
•Total 2-way axle load repetitions during design period =
226,444,692
*
2.35
=
532,145,025axles
226,444,692 2.35

532,145,025
axles
•No. of axles in predominant direction (50%) = 266,072,513 •Design traffic (25%) = 66,518,128 •
Nighttime(12
h)designaxlerepetitions(60%)=39910877

Night
time
(12
-
h)
design
axle

repetitions
(60%)
=
39
,910
,877
•Day time (12-h) design axle load repetitions (40%) = 26,607,251 •Day time 6-h axle load repetitions (design no. of axle load
repetitions for BUC analysis) = 13,303,626

Desi
g
n Exam
p
le-1:
gp
Selection of Design Traffic for Fatigue Analysis:
•Night time 6-h axle load repetitions = 19,955,439
•Proportion of CVs with spacing between front axle and first rear
axle less than transverse joint spacing is 55%)
•Design no. of axle load repetitions (TDC analysis) = 10,975,492
Axle Proportion Category-wise Category-wise
categor
y
of the axle
category
axle repetitions
for BUC analysis
axle repetitions
for TDC analysis
Front
single
045
5986632
4938971
Front
single
0
.45
5
,986
,632
4
,938
,971
Rear single 0.15 1,995,544 1,646,324
Tandem 0.25 3
,325
,906 2
,743
,873
,,
,,
Tridem 0.15 1,995,544 1,646,324
Total 1.00 13,303,626 10,975,492

Desi
g
n Exam
p
le-1:
gp
CFD for BUC and TDC, and Selection of Slab Thickness:
•Effective k-value of foundation = 285 MPa/m
•E of CC = 30,000 MPa •µof CC = 0.15
/
3
•Unit weight of CC = 24 kN
/
m
3

Designflexuralstrengthof CC
=
4.95MPa
Design
flexural
strength
of

CC

4.95
MPa
•Max. day-time ∆T in slab for BUC for Bihar = 16.8 °C •Max. night-time ∆T in slab for TDC = (16.8/2) + 5 = 13.4 °C

Desi
g
n Exam
p
le-1:
gp
Option-1 (with tied CC shoulder, with dowel bars):
•Trial thickness of slab = 0.28 m
•Radius of relative stiffness = 0.66621 m
•Beta factor in stress equations for doweled transverse joints for
TDC analysis is 0.66
•Fatigue damage for BUC = 0.976 + 0.274 = 0.976
F i d f TDC 0274+0445+0036 0755

F
at
igue
d
amage
f
or
TDC
=
0
.274
+

0
.445
+

0
.036
=
0
.755
•CFD for BUC and TDC = 0.976 + 0.755 = 1.731 •
The
trialthicknessof 028mis
notadeq ate

The
trial
thickness
of

0
.28
m

is
not

adeq
u
ate
•Increase thickness to 290 mm •
CFDforBUandTDC=0527(OK)

CFD

for

BU

and

TDC

=

0
.527
(OK)
•If retexturing is considered in 30 years, thickness of 300 mm will
be ade
q
uate
q

Desi
g
n Exam
p
le-1:
gp
Option-2 (without tied CC shoulder, without dowel bars):
•Trial thickness of slab = 0.33 m
•Radius of relative stiffness = 0.75358 m •Beta factor in stress equations for transverse joints without dowel
bars for TDC analysis is 0.90
•Fatigue damage for BUC = 0.935 + 0 = 0.935 •Fatigue damage for TDC = 0.233 + 0.390 + 0.030 = 0.654
C Df C dTDC 0935 0654 5 9

C
F
D

f
or BU
C
an
d
TDC
=
0
.935
+
0
.654
= 1.
5
8
9

Thetrialthicknessof 0.33mis
notadequate
The
trial
thickness
of

0.33
m

is
not

adequate
•Trial thickness of 340 mm would be adequate

Desi
g
n Exam
p
le-1:
gp
Option-3 (with widened outer lanes):

Reductioninflexuralstressduetowideningof outerlaneby05 Reduction
in

flexural
stress

due
to

widening
of

outer
lane
by

0
.5

to 0.6 m is the same as that of providing tied concrete shoulder

Thicknessof thepavementissameasthatobtainedforOption
-
1
Thickness
of

the
pavement
is

same
as
that
obtained
for

Option
1

(with tied CC shoulder and with dowel bars)

Designthicknessof CCslab
=
0.29
m
Design
thickness
of

CC

slab

0.29
m

Desi
g
n Exam
p
le-1:
gp
Option-4 (CC slab bonded to DLC):
•Provide 250 mm GSB above the subgrade
•Effective modulus of subgrade reaction of foundation consisting
of subgrade(8%CBR)andGSB=72MPa/m of

subgrade
(8%

CBR)
and

GSB

=
72
MPa/m
•Assuming that doweled transverse joints and tied CC shoulders,
thickness of slab = 0.30 m

E
=30000MPa E
=13600MPa
µ
=015and
µ
=020

E
1
=
30
,000
MPa
,
E
2
=
13600
MPa
,
µ
1
=

0
.15
,
and

µ
2
=

0
.20
•Provide 150 mm DLC •Depth of neutral axis = 0.16 m

Desi
g
n Exam
p
le-1:
gp
Option-4 (CC slab bonded to DLC):
•Assume a trial slab thickness (to be bonded to 0.150 m thick
DLC layer) = 0.235 m

Stiffnessof slabtobeplacedoverDLC=4665MN
m

Stiffness
of

slab
to

be
placed
over

DLC

=
46
.65
MN
-
m
•Stiffness of DLC layer = 23.28 MN-m •Combined stiffness of CC slab and DLC = 46.65 + 23.28 =
6993MN
m
69
.93
MN
-
m
•Stiffness of the design slab of 0.30 m thickness = 69.06 MN-m •Combined stiffness is greater than the design stiffness
requirement(OK) requirement
(OK)

Thank You