Mass defect, binding energy, E = mc
2
, eV, Atomic Mass
unit
Binding Energy
How is energy released when a nucleus forms?
so 0.4 kg of mass is "lost" when 4 nucleons bind into a helium atom
Which of these is called "mass defect"?
Find the composition of the copper-63 nucleus and determine the
combined mass of its components.
The mass of a proton is 1.00728 u and a neutron is 1.00867 u.
Mass of copper is 62.91367 u ( 29 protons)
Calculate the mass defect.
Mass defect, binding energy, E = mc
2
, eV, Atomic Mass
unit
29 protons(1.00728 u/proton) + 34 neutrons
(1.00867 u/neutron)
63.50590 u
Δm= 63.50590 u -62.91367 u = 0.59223 u
Binding Energy: The work that must be done to split
an atom into its constituent parts
Fusing smaller
nuclei releases
energy
Splitting larger
nuclei releases
energy
What can you tell me about the masses on either side?
What can you tell me about the binding energies on either side?
1) The mass of the uranium and neutron is larger than the mass of the krypton, barium and 3 neutrons.
2)The binding energy of the uranium nucleus is smaller than the binding energy of the krypton and barium -
this excess binding energy from krypton and barium compared to uranium is what is released
Mass of particles in alpha particle = 2 protons + 2 neutrons
= 2(1.0076) + 2(1.0090) = 4.0332 u
Mass Loss (Mass Defect) = 4.0332 - 4.0028 = 0.0304 u
since 1u = 931 MeV
Binding Energy = 0.0304 x 931 = 28.3 MeV
Calculate the binding energy(in MeV) of an
alpha particle from the following info:
mass of a proton = 1.0076 u
mass of a neutron = 1.0090 u
mass of an alpha particle = 4.0028 u
1 u = 931 MeV
mass loss(mass defect) = 238.0508 - (234.0436 + 4.0026) = 0.0046 u
since 1 u = 931 MeV,
energy released(MeV) = 0.0046 x 931 = 4.3 MeV
Calculate the total energy released(in MeV)
when uranium 238 decays by alpha emission to
Thorium 234.
uranium 238 = 238.0508 u
thorium 234 = 234.0436 u
alpha partice = 4.0026 u
1 u = 931 MeV
Mass defect, binding energy, E = mc
2
, eV, Atomic Mass
unit