CHAIN DRIVE Guided By Prof. H. D. Mhatre Presented By, 13) Girish Bonde 15) Pratik Chaudhari 16) Rahul chaure
KINDLY SUBSCRIBE THE YOUTUBE CHANNEL ALSO..... MECHANICAL ELECTRICAL ADVANCE DESIGN SKILLS ARE AVAILABLE ON YOUTUBE. LINK : https://studio.youtube.com/channel/UCJp3a0R2k_lWlOnoXy5sukA
content Introduction Types of Belt Drive Advantages Disadvantages Application Manufacturer’s catalog
introduction Transfer power (torque) from one location to another. From driver: motor , peddles , engine , windmill , turbine to driven : conveyor belt , back wheels/bike , generator rock crusher , dryer . Used to span large distances Gear drives have a higher torque capability but not flexible or cheap.
Chain Drive In Motorcycle Chain Drive In JCB
types of chains
Roller Chain Construction (Most common Type)
application Used in bicycles and motorcycles. Conveyors. Textile industry. Chain pumps. Rolling mills.
Manufacturer’s Catalog Selection Procedure And Formulae Example:- It is required to design a chain drive to connect a 12 kW, 1400 rpm electric motor to a centrifugal pump running at 700 rpm. These conditions involve moderate shocks. ( i ) Select a proper roller chain and give a list of its dimensions. (ii) Determine the pitch circle diameters of driving and driven sprockets. (iii) Determine the number of chain links . (iv) Specify the correct centre distance between the axes of sprockets.
Solution Given :- kW = 12, n1 = 1400 rpm, n2 = 700 rpm Step I kW rating of chain In order to reduce the polygonal effect, the number of teeth on the driving sprocket is selected as 17( K2 = 1). It is further assumed that the chain is simple roller chain with only one strand ( K1 = 1). The service factor from Table 14.3 is 1.3. FromEq . (14.8), kW rating of chain = (kW to be transmitted) Ks K1*K2
= 12 *1. 3 1*1 = 15.6 kw Step II selection of chain Referring to table 14.2, the power rating of the chain 12B at 1400 rpm is 18.15 kw. Therefore the Chain number 12B is selected. The dimensnios of this chain (table 14.1) are as follows: P = 19.05 mm d1 = 12.07 mm b1 = 11.68 mm
Step III : Pitch circle diameter of driving and driven pulleys From Eq. 14.2, D = P = 19.05 = 103.67mm Sin (180/z) Sin (180/17) For the driven sprocket, Z2 = Z1(N1/N2) = 17 (1400/700) = 34
D2 = P = 19.05 = 206.46mm Sin (180/z) Sin (180/17) Step IV Number of chain links The centre distance between the sprocket wheelsshould be between (30 p) to (50p). Taking a mean value of (40 p), the approximate centre distance is calculated. a = 40 p = 40(19.05) = 762 mm From Eq. (14.6),
Step V Correct centre distance To provide small sag, for allowing the chain links to take the best position on the sprocket teeth, the centre distance is reduced by (0.002 a). Therefore, the correct centre distance is given by, a = 0.998 Y 765.03 = 763.5 mm