Electrochemistry 06 _ Class Notes __ Parishram 2025.pdf

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1. —2025—
FOR CLASS 127”

Chemistry

Elctochemnt |,

Lecture - 06

By- Bharti Ma'am

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TOPICS shed

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(2) Tlectrochemica Seay
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3. CHAPTER NAM

3

A
Electrochemistry

nt
2

pe
ve

Er STE 4, D
ME lag ES = A

u,

4. Quick Revision

45 AG’ = =nPE°
cet N= po. + e fred

2) d-nfr, | F7 #50 €

5. CUA

Eo Ec La

cu cut

Q= [brduct)
(Reatand)

[sowie] = À

E q = Pressure

Ex, E PH

6. e The Clectrode Potential for,
0 a+ — ce LV. The value for
O are cue” ee)
Feat a= 0-5 CRD
ia

en

Ans oer

E

7. : a
> Cit eis — lay Emos Amine | y

ou, Ars ade mean
T Are — uw Bros © um, Ne! ¡ata ME

Ca*+ 96 — cu) —® sus LE = 40 Cw

AG, = 04° +00 pr Bey ole in:
NER = ne + nee’) e 060 E

AA

&

ARE = quen ous + (MPA? ) Gs E :

-QRE = -Fow- por
~ ape =-Ploister)

8. E

|

E

9. oe
Y ee
NNF
= 31
ka Am
Jo
er EN

ki bu

4 Im po 4 4

E

10. YD Y
y

af eux
go by,

Ex ponental function]

11. E)

Relation Bo Natur dog and Emmen toa

doy x= dnx ;
e E = Ea lo $
cut M
Ans 2408 bay

v
ay When temps 292k

12. es ad 5
fog 1= zum fog 13 = tl

Joga = 0:30

dor = OUF

404 T= 069% 0:

13. a Jog =?

(A) 0-48
(B) 0-60 d
(fore qa
5 IS) = don 3 dee vr
= our T O30

Aogirnn) = hep aed = ou

Product Rue

14. Jog IT =? es
pie Aegis?
(A) 067 >

DA LE = dede 2

[c) o-6lt
= 04+- 030
(a) ols x où

des

ty

5 =i)
y

E

15. c
ED ten = AE

Cell

Represent the cell in which the following reactign takes place

Mg(s) + 2Ag*(0.0001 M> M&(0.130 M) + 2Ag(s)

E = pity ®

cu. *

= = COR
Calculate tts Eca if ES (cel) = 3.17 V. Mg. (8) | mé* Com) | Fico oot!) [Ay (4)

=E° —0054| Je Q
Lu eux de

€
= Y = 0054) 19 x lo 5
EE el en y x gun
om +A

*

= 312-0089) fog 18 + ETS

ae ¿ln = eyes

O Ley]
1 Cp Cag”
Qe [m2
Caer)”
1Q= 013 (1x0

‘ (ot)

16. gi CRP of SHE = tev 110%

Calculate the potential of hydrogen electrode in contact with a solution whose

À do Mm '
eduction Potential :- Ris (gain of e) Im ip
Reduction Potential ¢ 4 4 2 loge ft Leal
an + — kn L ggg aoe LEA toy Le en
E = H a cH” = RS
A EU '
M. Ku Ome al 2% - aa ¡Pisto
Qa Pa = ats E VA (ut) my

y= HT at som EPS Los} ad y
| =-0:0591% 10 spor

17. @

doq4 = tine = 2 14 2
dog q= UE 3 xhoy 3

18. je

Given that E co, = 1.05 V

EE ui AJO

Dann N
gn
E =pbo05- ol
CU 2
=|05-0:05%1 Aout doy je
u
kg" + yo |

2 AE

Et

= |e y
calculate he emf of the cell ih which the following rection takes place: Eu BY
Nils) #{2Ag° 20.002 M) ->(i2210.160 M) + ZAg(s)

4 AR

O= (5 Lui]

Ly Cast”
g= ol = ols
aa

6
= ue)

19. Write the Nernst equation and emf of the following cells at 298 K:
(i) Mg(s) | Mg?* (0.001M) || Cu?* (0.0001M) | Cu(s)

—

20. Write the Nernst equation and emf of the following cells at 298 K:
(ii) Fe(s) | Fe?* (0.001 M) || H*(1M) | H,(g) (1 bar) | Pt(s)

2
w

21. Write the Nernst equation and emf of the following cells at 298 K:
(iii) Sn(s) | Sn?* (0.050 M) || H* (0.020 M) | H,(g) (1 bar) | Pt(s)

2.
y

22. AED

0 = me A Joy ke

Esa? LE Ak,

24. Calculate the equilibrium constant of the reaction: (EY
SUIZA AU

Cu(s) + 2Ag*(aq) > Cu?*(aq) + 2Ag(s) 4,2?
ES (ce) = 0.46 V Ey? ur ©,

25. —— fs à ao arde