Energy System Heat Transferred by transmission.pptx
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Jun 01, 2024
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About This Presentation
The formula and how to solve and calculate the heat transfer calculation in the basic residential building. The building is a small project with archiCAD.
Size: 2.43 MB
Language: en
Added: Jun 01, 2024
Slides: 19 pages
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Energy Systems Assignment 2 Basic Residential Heat Transferred By Transmission
Energy System 1 24/04/2024
Energy System 1 24/04/2024 1. Hallway 15,5m2 2. Living + dining room 37,5m2 3. Bedroom 12m2 4. Bedroom 12m2 5. Bedroom 12m2 6. Kitchen 7,5m2 7. Toilet 4m2 8. Bathroom 9m2 9. Storage room 10,5m2 Total Area 120m2
Q πππππ = β π π=π πΌπ βπ¨π β(π internal βπ external) Q πππππ : Heat transferred by transmission, U : The heat transfer coefficient by transmission, [ π€/ π2βπΎ ] A : Area, [π2] π πππ‘πππππ: Internal temperature, [β] π ππ₯π‘πππππ: External temperature, [β] π πππ‘πππππβ π ππ₯π‘πππππ, temperature difference, [K] For example, {20β-(-11β)} = {(20+273.15) K - (-11+273.15) K} = 31K Q πππππππππππ = π³βπβπͺπβ(π internal βπ external ) Q π£πππ‘ππππ‘πππ : Heat transferred by ventilation , [W] L : the air flow rate through the conditioned space, π3 / π From homework 1, L in depressive areas is 0.045 π3/π ,and L in compressive areas is 0.117 π3/π π : Density of the air , π = 1.2 ππ/π3 C π : The heat capacity of the air , πΆπ = 1006 π½/ππβπΎ Since J = Wβs, the unit is same as πβπ /ππβπΎ In these above two equations, π internal βπ external has the biggest impact on the equations. Measurements used in the following calculations: Brick wall : 0.20 m Wall Isolator : 0.07 m Roof concrete : 0.20 m Roof Isolator : 0.07 m Floor : 0.10 m Floor Isolator : 0.07 m Secondary gazing low-emission glass window Thermal conductivity of concrete: 0.11 π/πβπΎ Thermal conductivity of solid brick: 0.80 π/πβπΎ Typical insulation material: 0.04π/πβπΎ For windows and doors, ππ= 1.8 π€/π2βπΎ
Room1 (Bedroom 1) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((3+0.27+4+0.27)-(1.7+2.5)(2.5)) x {20β-(-11β)} = 0.462 π€/π2ββ x (3.34 x 2.5) x 31β = 298.97175 [W] β 298.97 [W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (3+0.27)(4+0.27) x {20β-(-11β)} = 0.444 π€/π2ββ x 13.9629 x 31β = 192.1853556 [W] β 192.19 [W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (3+0.27)(4+0.27) x {20β-15β)} = 0.5 π€/π2ββ x 13.9629 x 5β = 34.90 [W] Windows / Doors: Q π‘ππππ , window = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (1.7 x 2.5)β {20β-(-11β)} = 171.27 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.117 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 4378.51 [W] Q π‘ππππ ,π π’π,ππππ1 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ , window + ππ£πππ‘ππππ‘πππ = 298.97 [W] + 192.19 [W] + 34.90 [W] + 171.27 [W] + 4378.51 [W] = 3514.988 [W]
Room 2 (Bathroom) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((3+0.27+3)-(0,75+1,70)(2.5)) x {20β-(-11β)} = 0.462 π€/π2ββ x 23.875 x 31β = 341.93775 [W] β 341.93 [W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (3+0.27)(3) x {20β-(-11β)} = 0.444 π€/π2ββ x 9.81 x 31β = 135.02484 [W] β 135.02 [W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (3+0.27)(3) x {20β-15β)} = 0.5 π€/π2ββ x 9.81 x 5β = 24.52 [W] Windows / Doors: Q π‘ππππ , window = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (0.75 x 1.7)β {20β-(-11β)} = 51.38 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.045 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 1684.04 [W] Q π‘ππππ ,π π’π,ππππ 2 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ , window + ππ£πππ‘ππππ‘πππ = 341.93 [W] + 135.02 [W] + 24.52 [W] + 51.38 [W] + 1684.04 [W] = 2236.89 [W]
Room 3 (Bedroom 2) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((4+0.27+3)-(1.8+1.7)(2.5)) x {20β-(-11β)} = 0.462 π€/π2ββ x (3.77 x 2.5) x 31β = 134.98485 [W] β 134.98 [W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (4+0.27)(3) x {20β-(-11β)} = 0.444 π€/π2ββ x 12.81 x 31β = 176.31684 [W] β 176.31 [W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (4+0.27)(3) x {20β-15β)} = 0.5 π€/π2ββ x 12.81 x 5β = 32.02 [W] Windows / Doors: Q π‘ππππ , window = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (1.8 x 1.7) x {20β-(-11β)} = 123.31 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.117 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 4378.51 [W] Q π‘ππππ ,π π’π,ππππ3 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ , window + ππ£πππ‘ππππ‘πππ = 134.98 [W] + 176.31 [W] + 32.02 [W] + 123.31 [W] + 4378.51 [W] = 4845.13 [W]
Room 4 (Bedroom 3) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((3+0.27+4+0.27)-(1.5+1.7)(2.5)) x {20β-(-11β)} = 0.462 π€/π2ββ x (4.34 x 2.5) x 31β = 155.3937 [W] β 155.39 [/W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (3+0.27)(4+0.27) x {20β-(-11β)} = 0.444 π€/π2ββ x 13.9629 x 31β = 192.1853556 [W] β 192.19 [W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (3+0.27)(4+0.27) x {20β-15β)} = 0.5 π€/π2ββ x 13.9629 x 5β = 34.90 [W] Windows / Doors: Q π‘ππππ , window = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (1.5 x 1.7)β {20β-(-11β)} = 102.76 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.117 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 4378.51 [W] Q π‘ππππ ,π π’π,ππππ 4 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ , window + ππ£πππ‘ππππ‘πππ = 155.39 [W] + 192.19 [W] + 34.90 [W] + 102.76 [W] + 4378.51 [W] = 4863.75 [W]
Room 5 (Guess Bathroom) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((1.25+0.27+3.2)-(0,80+1,70)(2.5)) x {20β-(-11β)} = 0.462 π€/π2ββ x 13.875 x 31β = 198.71775 [W] β 198.71 [W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (1.25+0.27)(3.2) x {20β-(-11β)} = 0.444 π€/π2ββ x 4.864 x 31β = 66.9480 [W] β 66.94[W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (1.25+0.27)(3.2) x {20β-15β)} = 0.5 π€/π2ββ x 4.864 x 5β = 12.16 [W] Windows / Doors: Q π‘ππππ , window = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (0.80 x 1.7)β {20β-(-11β)} = 54.80 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.045 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 1684.04 [W] Q π‘ππππ ,π π’π,ππππ 5 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ , window + ππ£πππ‘ππππ‘πππ = 198.71 [W] + 66.94 [W] + 12.16 [W] + 54.80 [W] + 1684.04 [W] = 2016.65 [W]
Room 6 (Hallway) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((15.5+0.27)-(1.0+2.4)(2.5)) x {20β-(-11β)} = 0.462 π€/π2ββ x (12.37 x 2.5) x 31β = 1107.269625 [W] β 1107.26 [/W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (15.5+0.27) x {20β-(-11β)} = 0.444 π€/π2ββ x 15.77 x 31β = 217.05828 [W] β 217.05 [W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x 15.77 x {20β-15β)} = 0.5 π€/π2ββ x 15.77 x 5β = 39.42 [W] Windows / Doors: Q π‘ππππ , door = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (1.0 x 2.4)β {20β-(-11β)} = 96.72 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.117 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 4378.51 [W] Q π‘ππππ ,π π’π,ππππ6 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ ,ππππ + ππ£πππ‘ππππ‘πππ = 1107.26 [W] + 217.05 [W] + 39.42 [W] + 96.72 [W] + 4378.51 [W] = 5838.96 [W]
Room 7 & 8 Living Room & Dining Room) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((5+0.27+7.5+0.27)-(4.9+3.5)(2.5)) x {20β+11β)} = 0.462 π€/π2ββ x (4.64 x 2.5) x 31β = 166.1352 [W] β 166.13 [/W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (5+0.27)(7.5+0.27) x {20β-(-11β)} = 0.444 π€/π2ββ x 40.9479 x 31β = 563.6068956 [W] β 563.61 [W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (5+0.27)(7.5+0.27) x {20β-15β)} = 0.5 π€/π2ββ x 40.9479 x 5β = 102.37 [W] Windows / Doors: Q π‘ππππ , door = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (2.5 x 2.4)(1.8 x 1.7) β {20β-(-11β)} = 739.90 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.117 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 4378.51 [W] Q π‘ππππ ,π π’π,ππππ6 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ ,ππππ + ππ£πππ‘ππππ‘πππ = 166.13 [W] + 563.61 [W] + 102.37 [W] + 739.90 [W] + 4378.51 [W] = 5950.52 [W]
Room 9 (Kitchen) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((2.5+0.27+3.2+0.27)-(2.7+3.4)(2.5)) x {20β+11β)} = 0.462 π€/π2ββ x 0.875 x 31β = 12.488784 [W] β 12.49 [W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (2.5+0.27)(3.2+0.27) x {20β-(-11β)} = 0.444 π€/π2ββ x 9.6119 x 31β = 132.2981916 [W] β 132.30 [W] \ Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (2.5+0.27)(3.2+0.27) x {20β-15β)} = 0.5 π€/π2ββ x 9.6119 x 5β = 24.03 [W] Windows / Doors: Q π‘ππππ , door = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (1.0 x 1.7) (1.0 x 2.4) β {20β-(-11β)} = 164.42 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.045 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 1684.04 [W] Q π‘ππππ ,π π’π,ππππ 2 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ ,ππππ + ππ£πππ‘ππππ‘πππ = 12.49 [W] + 132.30 [W] + 24.03 [W] + 164.42 [W] + 1684.04 [W] = 2017.28 [W]
Room 10 (Utility Room) External Wall: U = 1 / (1/24 + 0.2/0.8 + 0.07/0.04+1/8) β 0.462 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.462 π€/π2ββ x ((2.5+0.27+3.2)-(0.50+1.70)(2.5)) x {20β-(-11β)} = 0.462 π€/π2ββ x (3.77 x 2.5) x 31β = 134.98485 [W] β 134.99 [W] Ceiling: U = 1 / (1/8 + 0.2/0.8 + 0.07/0.04+1/8) β 0.444 π€/π2ββ Q π‘ππππ , ceiling = πΌπ x π¨π x (π internal βπ external) = 0.444 π€/π2ββ x (2.5+0.27) 3.2 x {20β-(-11β)} = 0.444 π€/π2ββ x 8.864 x 31β = 122.004096 [W] β 122.00 [W] Floor: U = 1 / (1/8 + 0.1/0.8 + 0.07/0.04) β 0.5 π€/π2ββ Q π‘ππππ , external π€πππ = πΌπ x π¨π x (π internal βπ external) = 0.5 π€/π2ββ x (2.5+0.27) 3.2 x {20β-15β)} = 0.5 π€/π2ββ x 8.864 x 5β = 22.16 [W] Windows / Doors: Q π‘ππππ , window = πΌπ x π¨π x (π internal βπ external) = 1.3 π€/π2βπΎ x (0.5 x 1.7)β {20β-(-11β)} = 34.25 [W] Ventilation: Q π£πππ‘ππππ‘πππ = πΏβπβπΆπβ (π internal βπ external) = 0.117 π3/π β 1.2 ππ/π3 β 1006 πβπ /ππβπΎ β {20β-(-11β)} β 4378.51 [W] Q π‘ππππ ,π π’π,ππππ1 = ππ‘ππππ ,π€πππ + ππ‘ππππ ,πππππππ + ππ‘ππππ ,πππππ + ππ‘ππππ , window + ππ£πππ‘ππππ‘πππ = 134.99 [W] + 122.00 [W] + 22.16 [W] + 34.25 [W] + 4378.51 [W] = 4691.91 [W]
Chosen Radiators Function Watts [W] Radiators Bedroom 1 3514.988 [W] Kos H type 33 : 1500x600 : 3713 [W] Bathroom 2236.89 [W] MAU 22 09 : 2560 [W] Bedroom 2 4845.13 [W] Kos H type 33 : 1500x900 : 4902 [W] Bedroom 3 4863.75 [W] Kos H type 33 : 1500x900 : 4902 [W] Guess Bathroom 2016.65 [W] IMI 18 12 : 2274 [W] Living Room & Dining Room 5950.52 [W] Kos H type 33 : 1950x900 : 6372 [W] Utility Room 4691.91 [W] Kos H type 33 : 1950x600 : 4826 [W]