experimental physics notes for neet and jee aspirants

Worth for jee and neet aspirations

1. NEET 2024 ; |
ea a:

2. wns

NOOR

List of Experiments

. Vernier Calipers - its use to measure the internal and external diameter and depth of vessel.

. Screw Gauge - its use to determine thickness/diameter of thin sheet/wire.

. Simple pendulum - dissipation of energy by plotting a graph between the square of amplitude
and time.

. Metre scale - the mass of a given object by the principle of moments.

. Young’s modulus of elasticity of the material of a metallic wire.

. Surface tension of water by capillary rise and effect of detergents.

. Coefficient of viscosity of a given viscous liquid by measuring terminal velocity of a given
spherical body.

8. Speed of sound in air at room temperature using a resonance tube.
9. Specific heat capacity of a given (i) solid and (ii) liquid by method of mixtures.
10. The resistivity of a given wire using a meter bridge.

. The resistance of the given wire using Ohm’s Law.

12. Resistance and figure of merit of a galvanometer by half deflection method.
13. The focal length of: (i) Convex mirror, (ii) Concave mirror, and (iii) Convex lens, using the

parallax method.

14. The plot of the angle of deviation v/s angle of incidence for a triangular prism.

3. List of Experimen

15. Refractive index of glass slab using a travelling microscope.
16. Characteristics curves of a p-n junction diode in forward and reverse bias.
17. Characteristics curves of a zener diode and finding reverse breakdown voltage.

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Taught & mentored 10,000+ students

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5. 1. Vernier Calliper
INTERNAL Meanure dimension

bs >

ft

Yı

EXTERNAL
JAWS

oF N 12,4 6,8 2 Vu 6e 5 2,4 6,8 42,4 6,5 52 4 6 8 6
9 2 3 4 . 9

mans length.

IMPERIAL SCALE

0.001in

a u at“
f mm du fo

Veuve? METRIC SCALE DEPTH MEASURING
BLADE

Scob

6. 1. Vernier Calliper
No d dvd v.S capuding with MS dv

Y Length J Ims div

Leant court gone = Ins BE vs

y
Smolha+
dist thot Can

be Meahuped

7. i 7 dive] ms > lo div d vs
then 4.c.?

Normal s cols
ldivgms= Imm
= ı ms =! vs
Sl ll mara = 10div
0)
=| Imm — VU man] mm —
= Ta Id
= 0) mm

= Hem NS

8. 25
cu Main
rt EN 5 …] ver
o

MSR = 22
VSR - 3
Reading - MSR + VSREL.C

= 2 ram + ZxO.mm
= 2.3mm

9. eading
= MSR + VWSRALC

of Vanin
Colliper

10. Vernier Calliper : Zero Error

bgp = Reading = = Reading

(A) Positive zero error (B) Negative zero error

11. Vernier Calliper : Calculations

INTERNAL
JAWS

LOCKING
SCREW

IMPERIAL SCALE

| vo-1imsp-ivsp |

=

EXTERNAL
JAWS

METRIC SCALE

DEPTH MEASURING.
DE

Vernier scale + main scale — Zero error = actual reading

12. A vernier calliper has 1mm marks on the main scale. It has 20 equal division on
the vernier scale which match with 16 main scale divisions. For this vernier
calliper, the least count is -

20divon VS = 16 avg ms
20divd vs = l6mm

(a) 0.02 mm

(b) 0.05 mm

: : =16 4
(c)0.1mm =: | div d VS et = pe

(d) 0.2 mm hee |'mso= Wo] - p-3]= 30m

= 0.2 mm

13. A vernier calliper has 1 mm marks on the main scale. It has 20 equal division on
the vernier scale which match with 16 main scale divisions. For this vernier
calliper, the least count is -

(a) 0.02 mm
(b) 0.05 mm

(c) 0.1 mm

(d) 0.2 mm

14. No 20

Our
In a vernier caliper, when the jaws are touching each other the zero marks in both the
scale coincides, 10 vernier scale divisions matches with 9 main scale divisions (in mm). A

rod of length Lis measured with this vernier caliper. It shows 55 in main scale reading and
in the vernier scale 8th mark matches with a main scale division. What is the value of L?
———oOw— a

lo VSO = 4 msD l= MSR + VSRRLC

lo VS = 4mm
= O:
(b)55.7 mm - | yso = A mm ~ 55mm + ex La
10 = 55.%mm

(a) 55.8 mm

(c) 55.6 mm
LC = |Imso - 'vso)
(d) 55.9 mm

m | [Men — el
'0

= No =O-lenm

15. In a vernier caliper, when the jaws are touching each other the zero marks in both the
scale coincides, 10 vernier scale divisions matches with 9 main scale divisions (in mm). A
rod of length L is measured with this vernier caliper. It shows 55 in main scale reading and

in the vernier scale 8th mark matches with a main scale division. What is the value of L?

(a) 55.8 mm
(b) 55.7 mm

(c) 55.6 mm

(d) 55.9 mm

16. he smallest division on the main scale of a vernier callipers is 1mm, and 10 vernier 10 vernier

divisions coincide with 9 main scale divisions.
‘When jaws touch each other the vernier just crosses zero on mains scale and 2nd division
coincides with MS. +ve Mor

While measuring the diameter of a sphere, the zero mark of the vernier scale lies between

(29and 21 mm and the 7th division of the vernier scale coincide with a main scale division.

en diameter of the sphere is -
IOVSOH=AMSO Zaomer = MSR+ VSRYTE
10 VSD = 9mm > 0 +2x01=02

(a) 20.5 mm

(b) 21.5 mm > IVSD= Some Roading = 20mm + 7X 0:
‘o = 20.7mm

21.50
(c) mm he= Jimso- rvso|
(d) 20.50 mm d= 20-7 - 0:2

a
= | - mm
Timm ip | = 20. 5mm

= Y <o-
Ih = O \mm

17. he smallest division on the main scale of a vernier callipers is 1 mm, and 10 vernier
divisions coincide with 9 main scale divisions.
When jaws touch each other the vernier just crosses zero on mains scale and 2nd division
coincides with MS.
While measuring the diameter of a sphere, the zero mark of the vernier scale lies between
20 and 21 mm and the 7th division of the vernier scale coincide with a main scale division.
Then diameter of the sphere is -

(a) 20.5 mm
(b) 21.5 mm

(c) 21.50 mm

(d) 20.50 mm

18. Anvil Main scale

Circular scale

Ratchet

U- frame

Screw Gauge

19. Screw Gauge: Calculations

pitch 4 sommguage = dist moved by C-S.

No. df r»otohiam .

Le of scnaw quace = pilch
4 d “9 CSO Ctotal)

Reading = MSR + Low CSR

- = (Pas Zane)
0 Roading + (Negunas)

21. 25 msR = 2)

mn ESA = 42
26 ea; AC =0.0lmm
40
Reodacg = 2lmm +0-01X42mm
Cine

= 2l. 42 mm

22. Screw Gauge: Pitch, Least Count, Zero Error

Pitch of the screw gauge = (distance moved by a screw) / (no. of rotations)

Least count (LC) = (pitch) / (total no.of divisions on the circular scale)

(a) (b) (c) N

No zero error Positive zero error Negative zero error

23. A student measured the diameter of a small steel ball using a screw gauge of least count

So
0.00] cm. The main scale reading is 5 mm and zero of circular scale divisi incides with 25
divisions above the reference level. If the screw gauge has a zero error of -0.004 cm, the

_—_ 7 Zei AA

correct diameter of the ball is-

(a) 0.521 cm Zao ~ Es

(b) 0.525 cm Roadung= MSR + LCrCSR

anes = Smm + 0-00|em x25
C) 0. cm

= O.5tm+ 0. 025cm
=0.525 m

Ans =0.525 + 0. 00%
= 0.5 2 4m

(d) 0.529 cm

24. A student measured the diameter of a small steel ball using a screw gauge of least count
0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25
divisions above the reference level. If the screw gauge has a zero error of -0.004 cm, the
correct diameter of the ball is-

(a) 0.521 cm
(b) 0.525 cm

(c) 0.053 cm

(d) 0.529 cm

25. A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the
thickness of a thin sheet of aluminium. Before starting the measurement, it is found that when the
two jaws of the screw gauge are brought in contact, the 45" division coincides with the main scale

line and that the zero of the main scale is barely visible. What is the thickness of the sheet if the
main scale reading is 0.5 mm and the 25!" division coincides with the main scale line?
Lez pitch Zao=-(0+0.01x5)

cso Too =~ 0-05 mm = f

(a) 0.80 mm

(b) 0.70 mm

= GEMM Reding - mse
(c) 0.50 mm 50 PRE

LC =0.01mm =0 54 0.01x25\ _ ve
=0:5+0-35 Mor

= O75 rom

An, = 0.75 40-05 = 0-80 mm

sk 5:
(d) 0.75 mm

26. A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the
thickness of a thin sheet of aluminium. Before starting the measurement, it is found that when the
two jaws of the screw gauge are brought in contact, the 45" division coincides with the main scale
line and that the zero of the main scale is barely visible. What is the thickness of the sheet if the
main scale reading is 0.5 mm and the 25!" division coincides with the main scale line?

(a) 0.80 mm
(b) 0.70 mm

(c) 0.50 mm

(d) 0.75 mm

27. 3. Simple Pendulum

e AIM - To find dissipation of energy by plotting a graph between the square of amplitude and time.

(a) Set-up of dissipation of energy of (b) Effective length of the pendulum
an oscillating simple pendulum.

28. A

3. Simple Pendulum
Ne, o = e” 7200

30. Simple Pendulum

Principle: When a simple pendulum executes simple harmonic motion, the restoring force F is given by
F(t)=—kx(t)

Where x(t) is the displacement at time t and k = mg/L. The displacement is given by
x(t) =A, cos(ot - 0)

1, ,2
E=SkAj

A(t) = Ae?

E(t) = Ska? (t) =E,e*

31. A simple harmonic oscillator undergoes damped oscillations, and a graph is plotted between the
square of its amplitude (A?) and time (+). If the amplitude reduces to half in 10 s then the energy

would have dropped by how many times at 10 s ? At what time will amplitude will be 1/4th of initial?
ae N |

No

32. 4. Meter Scale : Principle of Momentum

Balanced Wedge

Y

Known standard
mass

33. A uniform metre scale has two weights of 12 gm and m gm suspended at the 10
cm and 80 cm marks respectively. Find the unknown mass, so that the metre
scale stays balanced?

tT - 7 4o ¿30

—
5 10 20 30 40 50 60 70 80 9
Loan x lg = Zocmxmg

ma ae ve”
3
an = 1690

34. A uniform metre scale has two weights of 12 gm and m gm suspended at the 10
cm and 80 cm marks respectively. Find the unknown mass, so that the metre
scale stays balanced?

5 10 20 30 40 50 60 70 80

ANS 4 gm

35. 5. Searle’s Setup
=

Moone. Y
wine
Coalnol wire > pet the

et d Control Wh Hest Wire
dsd. a
Or pansion

a
INN

Test Weight

37. A

P.
, =
e
2

38. 5. Young’s Modulus of Elasticit

e AIM - To find Young’s modulus of elasticity of the material of a metallic wire.

e According to Hooke’s Law - (Simple Method)
If AL = lis the extension in a wire of length L and radius r due to force F (=Mg),
the Young’s Modulus of the material of the given wire, Y -

39. In a Searle's experiment, the diameter of the wire as measured by a screw gauge with least
count 0.001 cm is 0.050 cm. The length, measured by a scale of least count 0.1 cm, is 110.0 cm.
Whena weight of 50 N is suspended from the wire, the extension is measured to be 0.125 cm
by a micrometer of least count 0.001 cm. Find the maximum error in the measurement of
Young's moduli f the material of the wire from these data.

(a) 1.26 %
(b) 4.89 %

% AY, (4b 24%, Ax) 1007
(c) 9.67 % «= L + > F =q

(d) 15.56 % =(O:' , 2»0.001 ,0-001
ho 0.05

0.125

RESINA

40. In a Searle's experiment, the diameter of the wire as measured by a screw gauge with least
count 0.001 cm is 0.050 cm. The length, measured by a scale of least count 0.1 cm, is 110.0 cm.
When a weight of 50 N is suspended from the wire, the extension is measured to be 0.125 cm
by a micrometer of least count 0.001 cm. Find the maximum error in the measurement of
Young's modulus of the material of the wire from these data.

(a) 1.26 %

(b) 4.89 %

(c) 9.67 %

(d) 15.56 %

41. Surface Tension of Water : Capillary Rise Method

e AIM - Surface tension of water by capillary rise and effect of detergents.

42. angle is obhux

Ps 0=%0 Hg in glosa
9 <40* ey: Water in NA J
e: Water nyo. Silvey, 9%

43. 6. Surface Tension of Water : Capillary Rise Method

e AIM - Surface tension of water by capillary rise and effect of detergents.
| h = 250050
$9 Rh ini

hw
>

Tubes —_

h

SN

Measurement of surface tension by capillary rise

44. A capillary tube of a uniform bore is dipped vertically in water which rises by 7 cm
in the tube. Find the radius of the capillary if the surface tension is 70 dynes/cm
g= 9.8 m/s. =70 10 ON

= 4
0 or A= 250050 voten
* ge A» = 7x08 N

A-2580 m
59h
-? .
=2x7H0 no
Jo°xlox 7200”
=0.2mm

45. A capillary tube of a uniform bore is dipped vertically in water which rises by 7 cm
in the tube. Find the radius of the capillary if the surface tension is 70 dynes/cm

g= 9.8 m/s.

ANS - 0.2 mm

46. 7. Coefficient of Viscosity

e AIM - Coefficient of viscosity of a given viscous liquid by measuring terminal velocity of a given
spherical body. nodıva dansı'y ball

z nun : VA:
Wr 22 3 (a Diary Ñ 4/3nr pg
2

6 tea) A 1

Viscaryty.

4/3nr 09

47. Alc=o

49. Plot the graph of speed vs time for a ball falling in a viscous fluid

y

Slope füngent = à

50. If a ball dropped has terminal speed of v in a viscous fluid, then a ball with double its size has
a terminal velocity of ?

(a) v V=2grq(o-$)
an

(b) v/2

var”

(d) 4v y Bey
x4 FRY

(c)2v

51. If a ball dropped has terminal speed of v in a viscous fluid, then a ball with double its size has
a terminal velocity of ?

(a) v
(b) v/2

(c) 2v

(d) 4v

52. 8. Speed of sound : Resonance Tube

e AIM - Speed of sound in air at room temperature using a resonance tube.

tuning fork ==

open

54. ») (tea)

cubinaching
L-L = Le.
= 22
y
dy =p 2 Y
bot 2
a
2lLe-b)

55. Avtinode

Im

_—

56. If a tuning fork of frequency () 340 Hz and tolerance + 1% is used in resonance
column method [v=2f,(I,-I,)], the first and the second resonance are measured
1,=24.0 cm and |,=74.0 cm. Find max. Permissible error in speed of sound.

fe Y ALY Ab +8 y
All, -t1) f

o yea f (kl) = 1 +04 7
Va] 2

= hay,

57. If a tuning fork of frequency () 340 Hz and tolerance + 1% is used in resonance
column method [v=2f,(I,-I,)], the first and the second resonance are measured
1,=24.0 cm and |,=74.0 cm. Find max. Permissible error in speed of sound.

dC= o.lem gui ane alo addect

a= 4. li Axr= 0-1+0-1
- 7-24 = 0-2 cm
wm = SO(m UÑA 1007,

“ ae
= 04°,

58. If a tuning fork of frequency (A) 340 Hz and tolerance + 1% is used in resonance
column method [v=2f,(I,-I,)], the first and the second resonance are measured
1,=24.0 cm and |,=74.0 cm. Find max. Permissible error in speed of sound.

ANS - 1.4%

59. In a resonance tube experiment to determine the speed of sound in air, a pipe of
diameter 5 cm is used. The air column in the pipe resonates with a tuning fork of

frequency 500 Hz, when the minimum length of the air column is 15.5 cm. Find

the speed of sound in air at room temperature. y

Tat Honmonic
(a) 330 m/s ly- Lace +e

(b) 335 m/s . = 15.5 +0 317150

(c) 340 mis = 17 cm

EE,
(d) 345 m/s = 45001 17:10 AS

!
=3%0mIA.

60. In a resonance tube experiment to determine the speed of sound in air, a pipe of
diameter 5 cm is used. The air column in the pipe resonates with a tuning fork of
frequency 500 Hz, when the minimum length of the air column is 15.5 cm. Find
the speed of sound in air at room temperature.

(a) 330 m/s
(b) 335 m/s

(c) 340 m/s

(d) 345 m/s

61. 9. Specific Heat Capacity

e AIM - Specific heat capacity of a given (i) solid and (ii) liquid by method of mixtures.

i<—Thermometer
(0°C-100°C) in 0.5°C

<— Copper stirrer

Boiling water
Solid

(Metal piece)
Burner

Felt or glasswool

Water
Calorimeter

uter jacket

62. = Latent hoat

63. A metal block of mass 250 g at a temperature of 150°C is placed in 150 g of water
a SELF RICHT nie
at 25°C. The final equilibrium temperature is 35°C. The specific heat capacity of
water is 4.18 J/g°C. Determine the specific heat of the metal block.
AR

(a) 0.2 J/g °C Q guia — Qt

(b)0.5uigec 1509 41835 = 2509: S > (150-35)

-25) .

(0) 1.0 J/g °C See
= Qu Tygr

(d) 2 J/g °C

64. A metal block of mass 250 g at a temperature of 150°C is placed in 150 g of water
at 25°C. The final equilibrium temperature is 35°C. The specific heat capacity of
water is 4.18 J/g°C. Determine the specific heat of the metal block.

(a) 0.2 J/g °C
(b) 0.5 J/g °C
(c) 1.0 J/g °C

(d) 2 J/g °C

65. 10. Meter Bridge

Known resistance Unknown resistance
Resistance Box x

Leclanche cell (Battery eliminator)

66. Meter Bridge : Concept

= Exacta.
RD is US

67. In a metre bridge when the resistance in the left gap is 20 and an unknown

resistance in the right gap, the balance point is obtained cm from zero end.
On shunting the unknown resistance with 2 O. Find th he balance point

ut r iden] ME =243 _ 6 y

25 xs 273 5

On 60m

68. In a metre bridge when the resistance in the left gap is 20 and an unknown
resistance in the right gap, the balance point is obtained at 40 cm from zero end.
On shunting the unknown resistance with 2 Q. Find the shift of the balance point
on the bridge.

ANS - 22.5 cm

69. 11. Resistance using Ohm’s Law

e AIM - The resistance of the given wire using Ohm’s Law.

Vel

- K
HH Rheostat
Battery von rmista ce

Unknown resistance wire

70. 11. Resistance using Ohm’s Law

e AIM - The resistance of the given wire using Ohm’s Law.

V (Volt) —>

72. 12. Half Deflection Method

e AIM - Resistance and figure of merit of a galvanometer by half deflection method.

The figure of merit of a galvanometer is the quantity of current required to produce a
deflection of one division in the galvanometer. It has a unit ampere per division and it is

represented by K.
RG

= M—
cal tunislance

73. 12. Half Deflection Method

e AIM - Resistance and figure of merit of a galvanometer by half deflection method.

Resistance of galvanometer Figure of merit

74. In an experiment to determine the resistance of a galvanometer by half
deflection method, the circuit has EMF of 25 Vand’ :; full deflection is 3 div . In
one set of readings, if R = 10 Q and S = 4 Q, then the resistance of the
galvanometer is -

75. In an experiment to determine the resistance of a galvanometer by half
deflection method, the circuit has EMF of 25 V and half full deflection is 3 div . In
one set of readings, if R = 10 Q and S = 4 Q, then the resistance of the
galvanometer is -

ANS - (20/3) Q 0.5A/div

76. 13. Focal length

e AIM - The focal length of Convex lens, using er method

(HE N - oe

l'as

x>2f we f<y<2f

PPT)
¿loli

77. A luminous object and a screen are at a fixed distance D apart. A converging lens of
focal length f is placed between the object and screen. A real image of the object in
formed on the screen for two lens positions if they are separated by a distance d equal to

a=?

A VD(D+4f)
= D?- ya

40
40f = SS
© v2DO-4D x? = 0° -40F
— = D(0-4p)
DvD? +4f X= V 000-47)

B VD(D-4f)

78. A luminous object and a screen are at a fixed distance D apart. A converging lens of
focal length f is placed between the object and screen. A real image of the object in
formed on the screen for two lens positions if they are separated by a distance d equal to

A VD(D+4f)

(O 50-40

c v2D(D - 4f)

D vD?+4f

79. A convex lens when placed in the first position forms a real image of an object ona
fixed screen. The distance between the object and the screen is 75cm. On displacing
the lens from first position by 25 cm to the second position, again a real image is
formed on the screen. Then the focal length of the lens is

= ox?
/ To

= Tes”

bx 75
= 25° (27-1?)
5x75 Fu
250151 87 SO on,
DPS: 3

First position Second position

80. A convex lens when placed in the first position forms a real image of an object ona
fixed screen. The distance between the object and the screen is 75cm. On displacing
the lens from first position by 25 cm to the second position, again a real image is
formed on the screen. Then the focal length of the lens is

First position Second position

ANS - (50/3) cm

81. 14. Prism : Concept

e AIM - The plot of the angle of deviation v/s angle of incidence for a triangular prism.

) ars! =A |= onge AF pusin

If=ire-A
Snell Us Sint Sine

Sah sinh

B Cc

d= (i- 1) + (e - r')
=i+e-A

82. e AIM - The plot of the angle of deviation v/s angle of incidence for a triangular prism.

8

&

7 8

|
5
|
Ë

35° 40 45° 50% 55° 60°
Angle of incidence () —»

Graph between i and D

83. For an equilateral prism the deviation is same for 55° and 35°. ;" minimum deviation = 80°
Refractive index ? Angle of incidence for minimum deviation ? Graph of deviation vs angle of
incidence

Fa Smin € y
.ise=4#5

l= sin ( Atse)
sin A
=

= kr
EAS

U=f2 ) sin (©) Sinzo

84. 15. Refractive Index

e AIM - Refractive index of glass slab using a travelling microscope.

AX opponent shit : .
produced by Slab rs | i

Sarre os Ho oust by which |

M- Scapa. hor to be moved . M

b focus ago:

P
(a) (b)

85. py bapp? ectuctonpth E

| index uw

AX= t — hanp = a= 2
E FA
¿| AX

vs
PL
df Slob

86. A microscope is focussed on a point marked on a paper. If a glass slab of thickness 12 cm is
used then the shift in microscope position is 4 cm then the refractive index is ?

87. A microscope is focussed on a point marked on a paper. If a glass slab of thickness 12 cm is
used then the shift in microscope position is 4 cm then the refractive index is ?

88. . p-n Junction Diode

Characteristics curves of a p-n junction diode in forward and reverse bias.

Cathode

Diode (P-N junction)
forward based

89. p-n Junction Diode : Forward Bias

e AIM - Characteristics curves of a p-n junction diode in forward and reverse bias. . Pour
voltoge =, !diffusien
E <— nt +.
Lovuar smola p
c00e [818] 09098

voltoae Potential ve vu.
Knee 9 divider + ecee lolo 0000

Larnien is Meher | —
voltsat “E
! lange went e

P-N Junction Diode in Forward Bias

90. p-n Junction Diode : Reverse Bias
e AIM - Characteristics curves of a p-n junction diode in forward and reverse bias.
ae aiff Srake

sm
——

kage
DT A Oat ot ta +
p

[d

Stop CORA — pera ess lelalooco
ávider -1 6660 lolol e000
++ ++ ————

P-N Junction Diode in Reverse Bias

91. p-n Junction Diode I vs V

Cathode (K) Anode (A) +1 (ma)

- -

—

Conventional Current Flow

Reverse Voltage

Leakage Current
Zener” <20uA Silicon
Breakdown <50uA Germanium
or Avalanche
Region Reverse

Bias

Forward
Current

| Forward Voltage
|

| 0.3v Germanium
1 0.7 Silicon

Reverse

ImA)Y Current

92. The reading of the ammeter for a silicon diode in the given circuit is :

vrik
(a) O mA

2-3=4% 200
(b) 15 mA

L= 23

(c) 11.5 mA
200
(d) 13.5 mA =23 UN

2” 1000
=11.5 mA

< 0: 7V—

2018

2.3 V
<—
2000

93. The reading of the ammeter for a silicon diode in the given circuit is :

2018
(a) 0 mA

(b) 15 mA

(c) 11.5 mA

(d) 13.5 mA

94. e AIM - Characteristics curves of a zener diode and finding reverse breakdown voltage.

=
1N4735
0) +
(0-200)mA (0-200)mA (A ) az

95. +To negulate voltage
+ operated in Raw bios
= Región Y Revove bros Breakdown

97. ©
=
|
©
a
O

e AIM - Characteristics curves of a zener diode and finding reverse breakdown voltage.
a

Zener Voltage
Vz(v)
+

>
Forward Voltage Ve (v)

Zener Current Iz(mA) | Forward Current [-(mA)

98. A Zener diode is connected to a battery and a loas as show below : The currents, | la
and |, are respectively.

Veit 60-10 2014
(a) 15 mA, 5 mA, 10 mA 50-i 4x00? <——50V_>

4KQ
(b) 15 mA, 7.5mA,75mA Ü =125mA a

I
60V—

(c)12.5mA,5mA,7.5mA V=tR

(d) 12.5 mA , 7.5 mA, 5 mA des UL 2x103
ıL=:5mA B
Üzigriu ip 7.5mfl

99. A Zener diode is connected to a battery and a loas as show below : The currents, | la
and |, are respectively.

2014
(a) 15 mA, 5 mA, 10 mA

(b) 15 mA, 7.5 mA, 7.5 mA
(c) 12.5 mA, 5 mA, 7.5 mA

(4) 12.5 mA, 7.5 mA, 5 mA

100. Phun with Physics Practicals