Formation of high spin and low spin complexes takes placebasing on t.pdf

Formation of high spin and low spin complexes takes placebasing on their electronic
configurations.
a) Mo3+
Mo - Z = 42
Electronic configuration : (Kr)4d55s1
Mo3+ : (Kr)4d35s0
There are only threeunpaired electrons in the valency shell. So in the presence ofstrong or
weak ligand only low spin complex is formed. SoMo3+ can only for low spin complex.
b) Rh3+
Z = 45
Electronic configuration : (Kr)4d85s1
Rh3+ : (Kr)4d65s0
Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
Z = 27
Electronic configuration : (Ar)3d74s2
Co2+ : (Ar)3d74s0
Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
Z = 78
Electronic configuration : (Xe)4f145d96s1
Pt2+ : (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+ can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Electronic configuration : (Kr)4d85s1
Rh3+ : (Kr)4d65s0
Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
Z = 27
Electronic configuration : (Ar)3d74s2
Co2+ : (Ar)3d74s0
Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
Z = 78
Electronic configuration : (Xe)4f145d96s1
Pt2+ : (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+ can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
Z = 27
Electronic configuration : (Ar)3d74s2
Co2+ : (Ar)3d74s0
Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ .

1. Formation of high spin and low spin complexes takes placebasing on their electronic
configurations.
a) Mo3+
Mo - Z = 42
Electronic configuration :   (Kr)4d55s1
Mo3+  :      (Kr)4d35s0
       There are only threeunpaired electrons in the valency shell. So in the presence ofstrong or
weak ligand only low spin complex is formed. SoMo3+ can only for low spin complex.
b) Rh3+
                                Z = 45

Electronic configuration :   (Kr)4d85s1
                          Rh3+  :   (Kr)4d65s0
       Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Electronic configuration :   (Kr)4d85s1
                          Rh3+  :   (Kr)4d65s0

2.        Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
       Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0

3. There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

4. Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.

Solution

Formation of high spin and low spin complexes takes placebasing on their electronic
configurations.
a) Mo3+
Mo - Z = 42
Electronic configuration :   (Kr)4d55s1
Mo3+  :      (Kr)4d35s0
       There are only threeunpaired electrons in the valency shell. So in the presence ofstrong or
weak ligand only low spin complex is formed. SoMo3+ can only for low spin complex.
b) Rh3+

5.                                 Z = 45

Electronic configuration :   (Kr)4d85s1
                          Rh3+  :   (Kr)4d65s0
       Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Electronic configuration :   (Kr)4d85s1
                          Rh3+  :   (Kr)4d65s0
       Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak

6. ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
       Thereare six unpaired electrons in the valency shell. So in thepresence of strong ligand six
can pair up to formthree electron pairs and allow the two orbitals for theformation of low spin
comples. When weak field complex isthere six electrons remains as unpaired and forms highspin
complex.So it can form both high as well as low spin complexes.
c) Co2+
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
                                Z = 27

Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.

7. d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Electronic configuration :   (Ar)3d74s2
                          Co2+  :   (Ar)3d74s0
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
       Thereare seven unpaired electrons in the valency shell. So in thepresence of strong or weak
ligand only high spin complex isformed. So Co2+ can only for high spincomplex.
d) Pt2+
                                Z = 78

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.

Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0

8. There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
Electronic configuration :   (Xe)4f145d96s1
                           Pt2+  :   (Xe)4f145d86s0
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.
There are eight unpaired electrons in thevalency shell. So in the presence of strong or weak
ligandonly high spin complex is formed. So Pt2+ canonly for high spin complex.
So out of the above four Pt2+ ,Co2+ , Mo3+   can not form bothhigh and low spin complexes.
Hope it helps you. For further doubts let me know.