GAS LAWS Boyle's Charles law ideal gas law

renald7 357 views 21 slides Mar 06, 2024
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About This Presentation

Physics


Slide Content

I. Physical
Properties

A. Kinetic Molecular Theory
Particles in an ideal gas…
•have no volume.
•have elastic collisions.
•are in constant, random, straight-
line motion.
•don’t attract or repel each other.
•have an avg. KE directly related
to Kelvin temperature.

C. Characteristics of Gases
Gases expand to fill any container.
•random motion, no attraction
Gases are fluids (like liquids).
•no attraction
Gases have very low densities.
•no volume = lots of empty space

C. Characteristics of Gases
Gases can be compressed.
•no volume = lots of empty space
Gases undergo diffusion & effusion.
•random motion

D. Temperature
ºF
ºC
K
-459 32 212
-273 0 100
0 273 373 32FC
9
5

K = ºC + 273
Always use absolute temperature
(Kelvin) when working with gases.

E. Pressurearea
force
pressure
Which shoes create the most pressure?

E. Pressure
Barometer
•measures atmospheric pressure
Mercury Barometer
Aneroid Barometer

E. Pressure
Manometer
•measures contained gas pressure
U-tube Manometer Bourdon-tube gauge

E. Pressure2
m
N
kPa
KEY UNITS AT SEA LEVEL
101.325 kPa (kilopascal)
1 atm
760 mm Hg
760 torr
14.7 psi

F. STP
Standard Temperature & Pressure
0°C 273 K
1 atm 101.325 kPa
-OR-
STP

II. The Gas
Laws
BOYLES
CHARLES
GAY-
LUSSAC

A. Boyle’s Law
P
V
PV = kVolume
(mL)
Pressure
(torr)
P·V
(mL·torr)
10.0 760.0 7.60 x 10
3

20.0 379.6 7.59 x 10
3

30.0 253.2 7.60 x 10
3

40.0 191.0 7.64 x 10
3

A. Boyle’s Law
The pressure and volume
of a gas are inversely
related
•at constant mass & temp
P
V
PV = k

k
T
V
 V
T
B. Charles’ LawVolume
(mL)
Temperature
(K)
V/T
(mL/K)
40.0 273.2 0.146
44.0 298.2 0.148
47.7 323.2 0.148
51.3 348.2 0.147

k
T
V
 V
T
B. Charles’ Law
The volume and absolute
temperature (K) of a gas
are directly related
•at constant mass &
pressure

k
T
P
 P
T
C. Gay-Lussac’s LawTemperature
(K)
Pressure
(torr)
P/T
(torr/K)
248 691.6 2.79
273 760.0 2.78
298 828.4 2.78
373 1,041.2 2.79

k
T
P
 P
T
C. Gay-Lussac’s Law
The pressure and absolute
temperature (K) of a gas
are directly related
•at constant mass &
volume

= kPV
P
T
V
T
PV
T
D. Combined Gas Law
P
1V
1
T
1
=
P
2V
2
T
2
P
1V
1T
2 =P
2V
2T
1

GIVEN:
V
1= 473 cm
3
T
1= 36°C = 309K
V
2= ?
T
2= 94°C = 367K
WORK:
P
1V
1T
2 = P
2V
2T
1
E. Gas Law Problems
A gas occupies 473 cm
3
at 36°C.
Find its volume at 94°C.
CHARLES’ LAW
TV
(473 cm
3
)(367 K)=V
2(309 K)
V
2= 562 cm
3

GIVEN:
V
1= 100. mL
P
1= 150. kPa
V
2= ?
P
2= 200. kPa
WORK:
P
1V
1T
2 = P
2V
2T
1
E. Gas Law Problems
A gas occupies 100. mL at 150.
kPa. Find its volume at 200. kPa.
BOYLE’S LAW
PV
(150.kPa)(100.mL)=(200.kPa)V
2
V
2= 75.0 mL

GIVEN:
V
1=7.84 cm
3
P
1=71.8 kPa
T
1=25°C = 298 K
V
2=?
P
2=101.325 kPa
T
2=273 K
WORK:
P
1V
1T
2= P
2V
2T
1
(71.8 kPa)(7.84 cm
3
)(273 K)
=(101.325 kPa)V
2 (298 K)
V
2= 5.09 cm
3
E. Gas Law Problems
A gas occupies 7.84 cm
3
at 71.8 kPa &
25°C. Find its volume at STP.
PTV
COMBINED GAS LAW