Non-ideal diode rectifier lecture note Nottingham Uni

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A non-ideal diode rectifier is a rectifier circuit in which the diodes used are modeled with practical, non-ideal characteristics rather than assuming an ideal diode. In reality, semiconductor diodes deviate from the ideal model due to physical limitations, and these deviations directly affect the p...


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Non-ideal 
Diode Rectifier (1)
0
Neutral
A
B
C
Line A
Phase
voltage
V
xy
D1 D3 D5
D4 D6 D2
Id=constant
x
y
h
h
h
a’
b’
c’
Effect of supply inductance = this causes overlap since current
cannot transfer instantaneously from one device to another
VA VB VC
D1
a’
D3
b’
x
ia
0
a
a
di
i const h
dt
= = 0
a
a d
di
i I h
dt
= → =∞
Instant commutation between D1 and D3 is not possible !
ia
ib
2009/10
Lecture notes and much more@ http://webct.nottingha m.ac.uk
Commutation group “P”
D1
⇒D3

Non-ideal 
Diode Rectifier (2)
'
a
a AN
di
V V h
dt
= −
'
b
b BN
di
V V h
dt
= −
a b d
i i I const+ = =
a b
di di
dt dt
⇒ =−
Outgoing diode (D1) Incoming diode (D3)
Both diodes conduct simultaneously (overlap)
' 'a b
V V=
a a
AN BN
di di
V h V h
dt dt
− = +
2
a AN BN
di V V
h
dt

⇒ =
'
2 2
AN BN AN BN
a AN x
V V V V
V V V
− +
= − = =
y CN
V V=
μ
Loss in Volt-time area!! ⇒smaller V xy
2 2 2
AC BC BC AC BA
xy BC
V V V V V
V V
+ −
∆ = − = =
2 2
AN BN AC BC
xy CN
V V V V
V V
+ +
⇒ = − =
Voltage Loss
2009/10
Lecture notes and much more@ http://webct.nottingha m.ac.uk
Is half the commutating voltage B=(incoming D3) A=(outgoing D1)
VANVBN

Non-ideal 
Diode Rectifier (3)
The missing VTA in Vxyis required to commutate the load
current I
dfrom D1 to D3
Loss in mean V
xy
Total VTA lost from Vxin one cycle = 3*h*I d
a
L
di
V h
dt
=
6 3
2
d d
I h I h
= ⋅ ⋅ ⋅ = ⋅ ⋅ ⋅
ω ω
π π
Effect on the line current waveform
lost L a d
VTA V dt h i h I⇒ = = ⋅∆ = ⋅∫
Similar for Vy⇒hence total VTA loss in Vxy= 6*h*I d
3 3
3
xy d
E
V I h
⋅= − ⋅ ⋅ ⋅
ω
π π
Causes volt-drop with Id
known as “regulation”
Negligible effect on the
harmonics unless μis
very large
⇒Same Power Quality
measures (DPF, DF, PF)
as for ideal diode rectif.
ia ib
Id
0
μ
a b d
i i I+ =
2009/10
Lecture notes and much more@ http://webct.nottingha m.ac.uk
Only a small change of shape during commut.

Non-ideal 
Diode Rectifier (4)
Calculation of μμμμ
0
A
B
D1D3
Id=const
x
h
h
a’
b’
VBA
ia
ib
Easiest way to find it is by considering the following loop:
μ
3E⋅
VBA=commut.
voltage
( )3 cos0 cos 2
d
E h I μ⋅ − = ⋅
( )
3
1 cos
2
d
I h E⋅ = ⋅ ⋅ − μ
Area = 2 Id*h
twice of what’s lost
⇒Determine μ
During this time, Vbacauses the change of :
• i
afrom Idto 0 in phase A inductance
• i
bfrom 0 to Idin phase B inductance
Detrimental effect on other users
0
A
B
C
Id=const
L1 L2
L1 L2
To other users
Current in L2 is
distorted due to
overlap
Voltage in PCC =
partially distorted
PCC
1
1 2
L
L L+

2009/10
Lecture notes and much more@ http://webct.nottingha m.ac.uk