Optical fiber Experiment.docx

This experiment is for the Undergraduate students of Engineering and Science background. The optical fiber experiment explains the principle of working of optical fiber and theory to determine the angle of acceptance and numerical aperture.

1. Engineering Physics Experiments, Prof. Praveen N. Vaidya, SDMCET Dharwad.

STUDY OF OPTICAL FIBER
Aim: To determine the Angle of acceptance hence the Numerical aperture of the given optical fiber.
Apparatus: Optical fiber, Laser (10mW) source, converging lens and stands.
Principle: Optical fiber is working on the principle of Total Internal Diffraction (TIR). This is the
phenomenon in which, the light beam is travelling in a denser medium, incident on the surface of rarer
medium with an angle of incidence greater than critical angle (C), then the light reflects totally internally
back to the denser medium instead of undergoing refraction.

Theory:
Optical fiber is a solid cylindrical structure whose diameter is negligible compare to length. It consists of
solid ultra transparent region called ‘core’. The transparent ‘cladding’ is coated to the core and a protective
sheet called ‘Jacket’ covered the fiber. The Refractive index (n1) of core is slightly greater than that of
cladding (n2), to get the total internal reflection.
Mathematically, ????????????�??????
0=????????????=
√??????
1
2
−??????
2
2
????????????
,
Where, no – Refractive index of medium in which Optical fiber is present. θ0 -Angle of acceptance.
Consider an optical fiber placed in the air of refractive index one. A sharp beam of light incident on its one
face at an angle ‘i’,
i) When i=0, light travels through optical fiber along the direction of normal, is called axial mode
ii) If the value of ‘i’ goes on increase above zero, the light, suffer total internal reflection at core cladding
interface continuously and travels through core without the losing its strength.
iii) If the value of ‘i=??????
0′, the light enter the core and travels at core-cladding interface and again refracts at an
angle 90
o
. The angle of incidence of beam at core cladding interface is called Critical angle (C) and the
angle (θ0) at which light beam focused on optical fiber face is called as ‘Angle of acceptance’ and term Sin
θ0 is called as ‘numerical aperture’.

2. Engineering Physics Experiments, Prof. Praveen N. Vaidya, SDMCET Dharwad.

iv) If the value of i>??????
0, then light beam entered into the core will completely refracts into the cladding.







For all the angle incidence, which equal to or less than critical angle light ray gives total internal reflection
through core, come out from the other face of optical fiber and falls on the screen placed on opposite side at
distance ‘l’ in circular shape of diameter ‘d’, now the critical angle θc is given by,
�??????�??????
�=
�/2
??????
�?????? �??????�??????
�=
�
2??????

�?????? ??????���� �� ??????�����??????���,??????
�=�??????�
−1
�
2??????
,
∴??????���????????????�??????� ??????��??????��??????�,??????.??????=????????????�[�??????�
−1
�
2�
]
Procedure:

Set up the apparatus of optical fiber experiment as shown in the diagram.
The laser beam is to be converted into a sharp beam by the use of condensing lens.
The beam emerged of the lens is focused on the one face of optical fiber at right direction.
The screen with a white drawing paper fitted is kept opposite to other face of optical fiber, so that the beam
appeared on the screen.
The intensity of image of laser beam appeared on the screen is adjusted to be high.
Mark the circumference of image using pencil and hence measure its diameter (d). The length between
screen and optical fiber face also measured (l ).
Determine value of angle of acceptance, using formula ??????
�=�??????�
−1
�
2??????
and NA using formula
??????.??????=????????????�[�??????�
−1
�
2�
]
Repeat the experiment for different values of ‘l’ and‘d’ and tabulate the readings.
Determine the average value of N.A. and note down the result.

θ0 O
C O θ0
l
d

3. Engineering Physics Experiments, Prof. Praveen N. Vaidya, SDMCET Dharwad.

Diagram:

Formula used for calculation of Angle of acceptance.
??????
0=�??????�
−1
�
2�

Formula used for calculation of Numerical Aperture.
??????.??????=????????????�[�??????�
−1
�
2�
]

Average value of Acceptance angle ____________
o
,
Average value of Numerical aperture, N.A._______

Result: Acceptance angle of optical fiber ________________
o
.
Numerical aperture of the optical fiber ____________.
******
Trial
No.
Distance between
output end of the
optical fiber and
screen. ‘l’ cm
Diameter of the
image of the laser
beam on the screen
‘d’ cm
�
2�

Angle of
acceptance
??????
0=�??????�
−1
�
2�

Numerical
Aperture
??????.??????=????????????�??????
0
1
2
3
4
5
6
7
8