Physics 2.4 - Thermal properties and temperature - 2.pptx

SangeetaTripathi8 55 views 74 slides Jun 21, 2024
Slide 1
Slide 1 of 74
Slide 1
1
Slide 2
2
Slide 3
3
Slide 4
4
Slide 5
5
Slide 6
6
Slide 7
7
Slide 8
8
Slide 9
9
Slide 10
10
Slide 11
11
Slide 12
12
Slide 13
13
Slide 14
14
Slide 15
15
Slide 16
16
Slide 17
17
Slide 18
18
Slide 19
19
Slide 20
20
Slide 21
21
Slide 22
22
Slide 23
23
Slide 24
24
Slide 25
25
Slide 26
26
Slide 27
27
Slide 28
28
Slide 29
29
Slide 30
30
Slide 31
31
Slide 32
32
Slide 33
33
Slide 34
34
Slide 35
35
Slide 36
36
Slide 37
37
Slide 38
38
Slide 39
39
Slide 40
40
Slide 41
41
Slide 42
42
Slide 43
43
Slide 44
44
Slide 45
45
Slide 46
46
Slide 47
47
Slide 48
48
Slide 49
49
Slide 50
50
Slide 51
51
Slide 52
52
Slide 53
53
Slide 54
54
Slide 55
55
Slide 56
56
Slide 57
57
Slide 58
58
Slide 59
59
Slide 60
60
Slide 61
61
Slide 62
62
Slide 63
63
Slide 64
64
Slide 65
65
Slide 66
66
Slide 67
67
Slide 68
68
Slide 69
69
Slide 70
70
Slide 71
71
Slide 72
72
Slide 73
73
Slide 74
74

About This Presentation

Thermal properties


Slide Content

CHAPTER 6: HEAT

The energy that is being transferred between two bodies as a result of temperature difference is called heat. Heat is a form of energy which causes the sensation of hotness/Coldness.

Measurement of Heat C.G.S unit: erg Calorie : 1 calorie is defined as the amount of heat required for raising the temperature of 1g of water through 1 degree Celsius from 14.5oC to 15.5oC. S.I. unit: joule (J) The units calorie and joule are related as: 1 cal = 4.186 J (or nearly 4.2 J) 1 J = 0.24 cal 1 J = 107 erg

Temperature Heat always flow from a body at higher temperature to the body at lower temperature. At molecular level, when temperature increases (means body is gaining heat), kinetic energy of molecule increases, thus internal energy of that body increases. Ice point: The temperature at which pure water and ice are in equilibrium in a mixture at 1 atmospheric pressure, represented by 0°C (32°F) Steam point: The temperature at which water vapor condenses at a pressure of one atmosphere, represented by 100°C (212°F)

Measurement of Temperature T(K) = 273 + t A degree on Celsius is 1 /100 th part of the interval between the ice point and the steam point . A degree on Fahrenheit scale is 1 /180 th part of the interval between the ice point and the steam point. 1 centigrade degree = 9 /5 Fahrenheit degree Ā 

HEAT AS A FORM OF ENERGY The Sun Gives Out Heat Heat is a form of energy. The Sun is the primary source of heat energy. Solid  liquid  gas Gas  liquid  solid ABSORB HEAT RELEASE HEAT

Test

Other Sources Of Heat Energy Ā  Apart from the sun, we can get heat energy from : Electricity Fossil fuel Radioactive metals The mantle of the Earth. Heat is produced in our daily life wherever there is friction. Friction occurs when two objects rub against each other. Ā  The Uses Of Heat In Our Daily Life. Ā  Heat is a useful form of energy. The uses of heat in our daily life include : Cooking Food drying Boiling water Drying clothes Providing warmth and etc.

The Differences Between Heat And Temperature Ā  Heat Temperature Is a form of energy due to motion of molecules in a substance. Is a degree of hotness or coldness of a body. It determines the flow of heat. Is measured in the joule ( J ) Is a measured in the Kelvin ( K ) Is the total amount of kinetic energy of a particles Tells us how fast the particles are moving. Two bodies having the same internal energy may differ in their temperature. Two bodies at same temperature may differ in the quantities of heat energy they can transfer When two bodies are placed in contact, the heat gained by one body is equal to the heat lost by another body. When two bodies at different temperatures are placed in contact, the resultant temperature is always lying between their initial temperatures. Heat is measured by using the principle of Calorimetry. Temperature is measured by a thermometer.

Effect of heat on matter

Thermometry Types of thermometer: (a) Mercury thermometer (b) Alcohol thermometer

Thermal Expansion of Solids: Effect of Heat on Solids Thermal Expansion Formula Linear Expansion: Volume Expansion (Cubical expansion) Superficial Expansion (Areal expansion)

Four rods, each of same initial length but made of copper, glass, iron and aluminium are heated to the same rise in temperature. Which rod will expand more? Specific heat of Copper isĀ  0.385J/ goC Specific heat of glass isĀ  0.84J/ goC Specific heat of iron isĀ  0.450J/ goC Specific heat of Aluminium isĀ  0.902J/ goC

Relation between Three Coefficients of Expansion

Apparent Expansion of Liquid and Real expansion of liquid

Anomalous Expansion of Water

Thermal Equilibrium Heat flows from a body at a higher temperature to a body at lower temperature till their temperatures become equal. Two bodies are said to be in thermal equilibrium, if they are at the same temperature.

SPECIFIC HEAT CAPACITY

Thermal (heat) capacity What requires more energy to heat up by 1 o C?

Thermal (heat) capacity What requires more energy to heat up by 1 o C? 1 kg water

Thermal (heat) capacity What requires more energy to heat up by 1 o C? 1 kg water 1 kg aluminium

Thermal (heat) capacity What requires more energy to heat up by 1 o C? 1 kg water 1 kg aluminium 4200 joules of energy 900 joules of energy

Thermal (heat) capacity What requires more energy to heat up by 1 o C? 1 kg water 1 kg aluminium 4200 joules of energy 900 joules of energy Water must be supplied with nearly five times as much energy as aluminium for the same rise in temperature.

Thermal (heat) capacity What requires more energy to heat up by 1 o C? 1 kg water 1 kg aluminium 4200 joules of energy 900 joules of energy Water must be supplied with nearly five times as much energy as aluminium for the same rise in temperature. It’s all to do with the SPECIFIC HEAT CAPACITY of the material

SPECIFIC HEAT CAPACITY Amount of heat (Q) absorbed or given out by a body depends upon the following factors: Mass of the body (m ). The rise or fall in temperature of the body The nature of the material which the body is made of Now we can say that: š‘„ āˆ š‘šāˆ†š‘‡ or, š‘„ = š‘šš‘ āˆ†š‘‡ Where s is a constant which explain heat absorption in terms of nature of material. It is a physical quantity which is known as specific heat or specific heat capacity

Thermal (heat) capacity The specific heat capacity of a substance is the amount of energy needed to change the temperature of 1kg of the substance by 1 o C.

Thermal (heat) capacity The specific heat capacity of a substance is the amount of energy needed to change the temperature of 1kg of the substance by 1 o C. Substance SHC (J / kg o C ) Water 4181 Oxygen 918 Lead 128

Thermal (heat) capacity The specific heat capacity of a substance is the amount of energy needed to change the temperature of 1kg of the substance by 1 o C. Substance SHC (J / kg o C ) Water 4181 Oxygen 918 Lead 128 Water has a particularly high SHC, making it very useful for storing heat energy, and for transporting it, eg . in central heating

Thermal (heat) capacity The equation (just what you wanted!)

Thermal (heat) capacity The equation (just what you wanted!) Energy transferred = mass x specific heat capacity x temperature Energy transferred = m c Ī” T Where: m is the mass in kg, c is the SHC in J/( kg o C ) Ī” T is the temperature change in o C (or in K)

Thermal (heat) capacity The equation How much energy needs to be transferred to raise the temperature of 2kg of water from 20 o C to 30 o C?

Thermal (heat) capacity The equation How much energy needs to be transferred to raise the temperature of 2kg of water from 20 o C to 30 o C? Energy transferred = mass x SHC x temp. change = 2 x 4181 x (30 – 20) = 2 x 4181 x 10 = 83,620 J = 83.62 kJ

Thermal (heat) capacity So what’s this ā€˜thermal capacity’ bit?

Thermal (heat) capacity So what’s this ā€˜thermal capacity’ bit? Thermal capacity = mass x SHC

Thermal (heat) capacity So what’s this ā€˜thermal capacity’ bit? Thermal capacity = mass x SHC e g . If there is 3kg of water in a kettle: Thermal capacity = 3 x 4181 = 12,543 J/ o C

Thermal (heat) capacity So what’s this ā€˜thermal capacity’ bit? Thermal capacity = mass x SHC e g . If there is 3kg of water in a kettle: Thermal capacity = 3 x 4181 = 12,543 J/ o C This means that for every 1 o C rise in temperature of the water in the kettle, 12,543 J of energy need to be supplied.

Measuring specific heat capacity

Measuring specific heat capacity http://www.schoolphysics.co.uk/age16-19/Thermal%20physics/Heat%20energy/text/Specific_heat_capacity_measurement/index.html Energy = power x time Apparatus for determining the SHC of a solid, eg . Aluminium Apparatus for determining the SHC of a liquid, eg . Water

Measuring specific heat capacity http://www.schoolphysics.co.uk/age16-19/Thermal%20physics/Heat%20energy/text/Specific_heat_capacity_measurement/index.html Energy = power x time Apparatus for determining the SHC of a liquid, eg . Water Beaker contains 0.75 kg of water. Immersion heater (200W) switched on for 200 seconds Temperature of the water rises by 12.5 o C Calculate the SHC of water

Measuring specific heat capacity http://www.schoolphysics.co.uk/age16-19/Thermal%20physics/Heat%20energy/text/Specific_heat_capacity_measurement/index.html Energy = power x time Apparatus for determining the SHC of a liquid, eg . Water Beaker contains 0.75 kg of water. Immersion heater (200W) switched on for 200 seconds Temperature of the water rises by 12.5 o C Calculate the SHC of water Energy transferred = power x time = 200 x 200 = 40,000J = 0.75 x c x 12.5 c = 40 000 / (0.75 x 12.5) SHC of water = 4267 J( kg o C )

Measuring specific heat capacity http://www.schoolphysics.co.uk/age16-19/Thermal%20physics/Heat%20energy/text/Specific_heat_capacity_measurement/index.html Energy = power x time Apparatus for determining the SHC of a liquid, eg . Water Beaker contains 0.75 kg of water. Immersion heater (200W) switched on for 200 seconds Temperature of the water rises by 12.5 o C Calculate the SHC of water Actual value for the SHC of water is 4181 J / kg o C . The method described does not make any allowance for heat loss to the surroundings or the beaker.

Thermal (heat) capacity Using the high SHC of water: Central heating system, water carries thermal energy from the boiler to the radiators. M Boiler R adiator Pump

Thermal (heat) capacity Using the high SHC of water: Central heating system, water carries thermal energy from the boiler to the radiators. M Boiler R adiator Pump In car cooling systems, water carries unwanted heat energy from the engine to the radiator.

Latent Heat

Solid Liquid Gas { melting { Boiling (evaporating) } condensing } freezing Latent Heat

Solid Liquid Gas { melting { Boiling (evaporating) } condensing } freezing Latent Heat Water has three phases or states : Solid (ice) Liquid Gas ( steam )

Latent Heat Thermal energy

Latent Heat Thermal energy Time

Latent Heat Thermal energy Time At this point the ice continues to absorb energy , but it’s temperature does not change .

Latent Heat Thermal energy Time At this point the ice continues to absorb energy , but it’s temperature does not change . The energy absorbed at this point is called the latent heat of fusion - It is needed to separate the particles so they can form a liquid .

Latent Heat Thermal energy Time At this point the ice continues to absorb energy , but it’s temperature does not change . The energy absorbed at this point is called the latent heat of fusion - It is needed to separate the particles so they can form a liquid . The energy is released again when a liquid changes back to a solid.

Latent Heat The specific latent heat of fusion of ice is 330 000 J/kg

Latent Heat The specific latent heat of fusion of ice is 330 000 J/kg This means that 330 000 joules of energy are transferred to change each kilogram of ice into water at the same temperature (0 o C).

Latent Heat The specific latent heat of fusion of ice is 330 000 J/kg This means that 330 000 joules of energy are transferred to change each kilogram of ice into water at the same temperature (0 o C). Equation: Energy transferred = mass x specific latent heat E = mL

Latent Heat The specific latent heat of fusion of ice is 330 000 J/kg This means that 330 000 joules of energy are transferred to change each kilogram of ice into water at the same temperature (0 o C). Equation: Energy transferred = mass x specific latent heat E = mL e g . If 3.5 kg of ice is melted (at 0 o C) E = mL Energy transferred = 3.5 x 330 000 E = 1 155 000 J

Latent Heat Measuring the specific latent heat of fusion of ice.

Latent Heat Measuring the specific latent heat of fusion of ice.

Latent Heat Measuring the specific latent heat of fusion of ice. 100 W immersion heater switched on for 300 seconds. Mass of water collected = 0.10kg E = mL L = E / m E = 100 x 300 = 30 000 J L = 30 000 / 0.10 = 300 000 J/kg Power = energy / time So, energy = Power x time

Latent Heat Measuring the specific latent heat of fusion of ice. 100 W immersion heater switched on for 300 seconds. Mass of water collected = 0.10kg E = mL L = E / m E = 100 x 300 = 30 000 J L = 30 000 / 0.10 = 300 000 J/kg Power = energy / time So, energy = Power x time Only an approximate figure for L as no allowance made for heat loss to the surroundings.

Latent Heat of Fusion Measuring the specific latent heat of fusion of ice. 100 W immersion heater switched on for 300 seconds. Mass of water collected = 0.10kg E = mL L = E / m E = 100 x 300 = 30 000 J L = 30 000 / 0.10 = 300 000 J/kg Power = energy / time So, energy = Power x time Only an approximate figure for L as no allowance made for heat loss to the surroundings.

Latent Heat of Vaporization

Latent Heat of Vaporization Water boils at 100 o C, producing steam.

Latent Heat of Vaporization Water boils at 100 o C, producing steam. If the kettle is not switched off, more thermal energy is absorbed by the water, producing more steam at 100 o C.

Latent Heat of Vaporization Water boils at 100 o C, producing steam. If the kettle is not switched off, more thermal energy is absorbed by the water, producing more steam at 100 o C. The energy absorbed by the water is called the latent heat of vaporization

Latent Heat of Vaporization Water boils at 100 o C, producing steam. If the kettle is not switched off, more thermal energy is absorbed by the water, producing more steam at 100 o C. The energy absorbed by the water is called the latent heat of vaporization Most of the thermal energy is need to separate the particles so they can form a gas. Some energy is required to push back the atmosphere as the gas forms.

Latent Heat of Vaporization The specific latent heat of vaporization of water is 2 300 000 J/kg

Latent Heat of Vaporization The specific latent heat of vaporization of water is 2 300 000 J/kg This means that 2 300 000 joules of energy are transferred to change each kilogram of liquid water into steam at the same temperature (100 o C).

Latent Heat of Vaporization The specific latent heat of vaporization of water is 2 300 000 J/kg This means that 2 300 000 joules of energy are transferred to change each kilogram of liquid water into steam at the same temperature (100 o C). Same equation as for the specific latent heat of fusion: E = mL But this time ā€˜L’ is the specific latent heat of vaporization .

Measuring the specific latent heat of vaporization of water. Latent Heat of Vaporization

Measuring the specific latent heat of vaporization of water. Latent Heat of Vaporization http://spmphysics.onlinetuition.com.my/2013/07/measuring-specific-latent-heat-of_6.html

Measuring the specific latent heat of vaporization of water. Latent Heat of Vaporization http://spmphysics.onlinetuition.com.my/2013/07/measuring-specific-latent-heat-of_6.html Power = energy / time So, energy = Power x time 100 W immersion heater switched on for 500 seconds. Mass of water boiled away = 20.0g E = mL L = E / m E = 100 x 500 = 50 000 J L = 50 000 / 0.02 = 2 500 000 J/kg

Measuring the specific latent heat of vaporization of water. Latent Heat of Vaporization http://spmphysics.onlinetuition.com.my/2013/07/measuring-specific-latent-heat-of_6.html Power = energy / time So, energy = Power x time 100 W immersion heater switched on for 500 seconds. Mass of water boiled away = 20.0g E = mL L = E / m E = 100 x 500 = 50 000 J L = 50 000 / 0.02 = 2 500 000 J/kg Only an approximate figure for L as no allowance made for heat loss to the surroundings.
Tags