throughout, making the second arm resistance of magnitude 0.2 ohm using standard
resistance,
The readings are taken by interchanging the arms and calculating the mean.
(ii) Using thick copper wires for connections, a voltmeter of nearly infinite.
resistance and a sensitive ammeter of nearly zero resistance can be used to measure the potential
drop across the given resistance and the current through it. Applying Ohm's law, the value of resistance can
determined.
Q. 22. What is S.I. unit of specific resistance?
Ans. Ohm-m.
Q. 23. State the relation of p with R, I and d.
Ans. p = R. A/l = R
Q. 24. What is the shape of the graph of R vs. I for a wire of uniform cross-section and
of a given homogeneous composition material?
Ans. It would be a straight line through the origin.
Q. 25. The radius of a bridge wire increases uniformly, how wil its resistance vary as
you move along the length?
Ans. Resistance will not increase linearly with length. As area of cross-section increases, it
will cause decrease in resistance. Therefore, increase will not be uniform rather as we move along
the wire, rate of increase of resistance will be less.
0. 26. What is the general formula for combination of n resistances R, R, Ry ..., R, to be connected in series?
41
Ans. Combined resistance is given by R, = 2K= R, + R, + R, +
Ans.
R,
0. 27. What is the general formula for combination of n resistances R,, R,, R9 .., R,
to be connected in parallel? EM
Ans. Current.
i=l R
1,1
R R,
t ... t
i=1
0. 28. If three resistances of different values are connected in series in a circuit, which
would be the same in both --current or the potential difference across their ends?
1
R
0. 29. Resistances of 10 2 and 15 2 are connected across a source of e.m.f. 12 Y
(r= 0). What current would be drawn from the battery?
1
Ans. When in series : R. = 25 S2 and I = 0.48 A, when in parallel : R = 6 2 and 1, = 2.0 A.
P.
Q. 30. Two appliances of 100 W and 200 W are connected across mains of 250 V. Find the equivalent power consumption by them if connected in (a) parallel, and (b) series.
Ans. In parallel, P, = P, + P, = 100 + 200 = 300 W
......... t R.
1
In series, the current through them will decrease, thereby decreasing the power consumpuo
P P >P,=
P+P,
= 66.67 W