The presence of material bodies complicates Maxwell’s equations. The fields in material media are related to each other through constitutive relations
AliALKHAYYAT8
9 views
28 slides
May 12, 2025
Slide 1 of 28
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
About This Presentation
The presence of material bodies complicates Maxwell’s equations.
The fields in material media are related to each other through constitutive relations
Size: 1.1 MB
Language: en
Added: May 12, 2025
Slides: 28 pages
Slide Content
Overview Rectangular waveguides TE solution TM solution Cutoff frequency and cutoff wavelength
Rectangular waveguides Used for the frequency range 320 MHz to 333 GHz At 320MHz: 148.39cm x 73.9cm At 333 GHz: 0.086cm x 0.043cm The standard WR-90 X-band waveguide is used for 8.2-12.5GHz and has dimensions 2.29 cm x 1 cm. Applications: mainly to couple transmitters and receivers to antenna Rectangular metal waveguide
Unique circuits and currents do not exist and the waveguide is analysed as a field problem rather than as a distributed circuit parameter problem Rectangular waveguide supports TE nm and TM nm modes The integers n and m determine the number of standing wave interference maxima along the two transverse directions Each mode has its characteristic frequency below which it cannot exist (propagate) The cut-off frequency is defined by the geometry (size) of the waveguide
Rectangular waveguide Boundary conditions for the E field: Tangential E field components are zero on the metal boundary
TM modes – rectangular waveguide For the TM modes Hz=0 Wave equation is solved for E z k c is the cut-off wavenumber To solve (1) the technique known as separation of variables is used. The Ez component of the field is given as: The boundary conditions are: E z =0 at x=0,a E z =0 at y=0,b (1) where a b
TM modes - solution TM mode field solution ( see Appendix B for more detail ): k c is the cut-off wavenumber The cutoff frequency is: and
TM modes - solution The cutoff wavelength is: The propagation constant is given by: It is a function of dimensions and integers n and m only!
The transverse field components for the TMnm mode are:
TM modes - solution TM mode field solution: Observe the field expressions on the previous slide for n=0 or m=0. There is no field solution when n=0 or m=0. The lowest propagating mode is the n=m=1 mode! The cutoff wavelenght of the lowest TM propagating mode is:
x [m] y [m] TM 11 mode field profile Waveguide: a=22.9mm, b=10mm
TM 11 mode field profile
TM 21
TM 12
TM 22 TM 32
TE modes for rectangular waveguides - solution Ez=0 k c is the cut-off wavenumber The cutoff frequency is:
TE modes - solution The cutoff wavelenght is: The propagation factor is given by:
TE modes - solution TE mode field solution: The lowest propagating mode is the n=1, m=0 mode The cutoff wavelenght of the lowest TE propagating mode is: A typical guide has dimensions a=2b. For the wavelengths from l =a to l =2a only TE 10 - mode propagates – this is a dominant mode of the metal waveguides
The dominant TE 10 mode The lowest propagating mode is the n=1, m=0 mode TE 10 mode field solution: The cutoff wavelength of the lowest TE propagating mode is:
The dominant TE 10 mode A typical guide has dimensions a=2b. Lets calculate cutoff frequencies for the first few modes: For the wavelengths from l =a to l =2a only TE 10 - mode propagates – this is a dominant mode of the metal waveguides
General solution: At y=0, E=0: At y=b, E=0: Final solution: The wave equation to be solved: Constants A and B are found by satisfying boundary conditions: k y =transversal prop.constant Appendix A: TE modes of the planar waveguides
Appendix B: TM mode derivation for the rectangular waveguide Maxwell’s equations are: If we assume that the fields propagate along z coordinate as e -j b z then above equations (1,2) can be simplified by replacing derivatives along z as d/dz=-j b. We can also eliminate Ez and Hz from above set of 6 equation and re-express transversal field components (Ex, Ey, Hx, Hy) in terms of Ez and Hz as: (1) (2)
(3) If we know either Ez or Hz we can find TE or TM field components.
Appendix B: TM mode derivation for the rectangular waveguide At the metal boundary x=0, for all y E z =0 so: For the TM mode we know that Hz=0 so we need to solve wave equation for Ez. The solution can be found by assuming that the field is given in the form where
At x=a, for all y values we get: Two solutions are possible for the above equation: A 1 =0 (trivial solution) or sin( k x a )=0. If A 1 =0 then we will completely remove function f(x) from the field solution, so it must be
Similarly for y=0, and all x, E=0: Two solutions are possible for the above eq : B 1 =0 or sin( k y b )=0. If B 1 =0 then we will completely remove function f(y) from the field solution, so it must be For y=b, and all x E=0:
The solution for Ez is: Other field components are found from Maxwell’s equation eq(3) by replacing the above solution and assuming Hz=0, i.,e: For more detail see: (1) David M. Pozar , Microwave Engineering ; (2) Simon Ramo , Fields and wave in communication electronics ; (3) Robert Collin, Foundations for Microwave Engineering