Relation between Duty and Delta
Letthereisacropofbaseperiod(orkorperiod)Bdays.Letonem3/sec(cumec)ofwater
beappliedtothiscroponthefieldforBdays.
ThevolumeofwaterappliedtothiscropforBdaysare
V = (60x 60 x24x B)m
3
= 86400 B m
3
Asdutyisthenumberofhectarestobeirrigatedbyonecumecofdischargetillthe
maturityofcropsothisquantityofwater(Volume)irrigateDhectares.Then
Depthofwaterapplied=Volume/Area=8.64B/Dmeters.LetthisdepthisΔ.So
Δ= 8.64 x B/D
Example:Waterisreleasedattherateof5cumecsattheheadofacanal.Ifthedutyatthe
fieldis100hectares/cumecandthelossofwaterintransitis30%,findtheareaoftheland
thatcanbeirrigated.
GivenData:Q=5m
3
/sec;D=100hect/cumec;losses=30%;
Required: Areaatfield?
Solution:
Area=Duty/Discharge=duty/Q=[100hectares/(m3/sec)/(5m3/sec)]=500hectaresat
theupstreamofcanal.
Area at the field = (100-30)/(100) * 500 = 350 hectares Answer