11 X1 T05 05 Perpendicular Distance

9,094 views 19 slides May 12, 2009
Slide 1
Slide 1 of 19
Slide 1
1
Slide 2
2
Slide 3
3
Slide 4
4
Slide 5
5
Slide 6
6
Slide 7
7
Slide 8
8
Slide 9
9
Slide 10
10
Slide 11
11
Slide 12
12
Slide 13
13
Slide 14
14
Slide 15
15
Slide 16
16
Slide 17
17
Slide 18
18
Slide 19
19

About This Presentation

No description available for this slideshow.


Slide Content

Perpendicular Distance
Formula

Perpendicular Distance
Formula
The shortest distance from a point to a line is the perpendicular distance.

Perpendicular Distance
Formula
The shortest distance from a point to a line is the perpendicular distance.
( )
1 1
,x y

Perpendicular Distance
Formula
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
( )
1 1
,x y

Perpendicular Distance
Formula
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y
( )1,4

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y
( )1,4
3x – 4y – 12 = 0

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y
( )1,4
3x – 4y – 12 = 0
r

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y
( )1,4
3x – 4y – 12 = 0
r
() ()
( )
22
3 1 4 4 12
3 4
r
- -
=
+ -

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
25
25
=
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y
( )1,4
3x – 4y – 12 = 0
r
() ()
( )
22
3 1 4 4 12
3 4
r
- -
=
+ -

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
25
25
=
5 units=
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y
( )1,4
3x – 4y – 12 = 0
r
() ()
( )
22
3 1 4 4 12
3 4
r
- -
=
+ -

Perpendicular Distance
Formula
1 1
2 2
Ax By C
d
A B
+ +
=
+
e.g. Find the equation of the circle with tangent 3x – 4y – 12 = 0 and
centre (1,4).
25
25
=
5 units=
The shortest distance from a point to a line is the perpendicular distance.
Ax + By + C = 0
d
( )
1 1
,x y
( )1,4
3x – 4y – 12 = 0
r
() ()
( )
22
3 1 4 4 12
3 4
r
- -
=
+ -
( ) ( )
2 2
the circle is
1 4 25x y
\
- + - =

If has different signs for different points, they are
on different sides of the line.
( )
1 1
Ax By C+ +

If has different signs for different points, they are
on different sides of the line.
( )
1 1
Ax By C+ +
Ax + By + C = 0

If has different signs for different points, they are
on different sides of the line.
( )
1 1
Ax By C+ +
Ax + By + C = 0
Ax + By + C > 0

If has different signs for different points, they are
on different sides of the line.
( )
1 1
Ax By C+ +
Ax + By + C = 0
Ax + By + C > 0
Ax + By + C < 0

If has different signs for different points, they are
on different sides of the line.
( )
1 1
Ax By C+ +
Exercise 5E; 1b, 2cf, 5a, 6a, 7bd, 8b,
9abc, 10, 13, 14, 18*
Ax + By + C = 0
Ax + By + C > 0
Ax + By + C < 0