Arterial blood gas.ppt1 (1)

Arterial blood gas.ppt

1. Blood Gas Analysis
and it’s Clinical
Interpretation
Manu Jacob
Perfusionist
Kmct Mch

2. Outline
1.Common Errors During ABG Sampling
2.Components of ABG
3.Discuss simple steps in analyzing ABGs
4.Calculate the anion gap
5.Calculate the delta gap
6.Differentials for specific acid-base disorders

3. Delayed Analysis
 Consumptiom of O2 & Production of CO2
continues after blood drawn
Iced Sample maintains values for 1-2 hours
Uniced sample quickly becomes invalid within
15-20 minutes
PaCO2 ­ 3-10 mmHg/hour
PaO2 ¯
pH ¯ d/t lactic acidosis generated by
glycolysis in R.B.C.

4. Temp Effect On Change of ABG
Values
Parameter37 C (Change
every 10 min)
4 C (Change
every 10 min)
¯ pH
0.01 0.001
­ PCO2
1 mm Hg 0.1 mm Hg
¯ PO2
0.1 vol % 0.01 vol %

5. FEVER OR HYPOTHERMIA
1.Most ABG analyzers report data at N body temp
2.If severe hyper/hypothermia, values of pH &
PCO2 at 37 C can be significantly diff from pt’s
actual values
3.Changes in PO2 values with temp also predictable
Hansen JE, Clinics in Chest Med 10(2), 1989 227-237
If Pt.’s temp < 37C
Substract 5 mmHg Po2, 2 mmHg Pco2 and Add
0.012 pH per 1C decrease of temperature

6. AIR BUBBLES
:
1.PO2 ~150 mmHg & PCO2 ~0 mm Hg in air bubble(R.A.)
2.Mixing with sample, lead to ­ PaO2 & ¯ PaCO2
To avoid air bubble, sample drawn very slowly and
preferabily in glass syringe
Steady State:
Sampling should done during steady state after change in
oxygen therepy or ventilator parameter
Steady state is achieved usually within 3-10 minutes

7. Leucocytosis :
¯ pH and Po2 ; and ­ Pco2
 0.1 ml of O2 consumed/dL of blood in 10
min in pts with N TLC
 Marked increase in pts with very high
TLC/plt counts – hence imm chilling/analysis
essential
EXCESSIVE HEPARIN
Dilutional effect on results ¯ HCO
3
-
& PaCO2
Only .05 ml heperin required for 1 ml blood.
So syringe be emptied of heparin after flushing or only dead
space volume is sufficient or dry heperin should be used

8. TYPE OF SYRINGE
1.pH & PCO2 values unaffected
2.PO2 values drop more rapidly in plastic syringes (ONLY
if PO2 > 400 mm Hg)
Differences usually not of clinical significance so plastic
syringes can be and continue to be used
Risk of alteration of results ­ with:
1.­ size of syringe/needle
2.¯ vol of sample
HYPERVENTILATION OR BREATH HOLDING
May lead to erroneous lab results

9. COMPONENTS OF THE ABG
pH: Measurement of acidity or alkalinity, based on the
hydrogen (H+). 7.35 – 7.45
Pao
2
:The partial pressure oxygen that is dissolved in arterial
blood. 80-100 mm Hg.
 PCO
2
: The amount of carbon dioxide dissolved in arterial
blood. 35– 45 mmHg
HCO
3

:
The calculated value of the amount of bicarbonate in
the blood. 22 – 26 mmol/L
SaO
2:
The arterial oxygen saturation.
>95%
pH,PaO
2
,PaCO
2
, Lactate and electrolytes are measured
Variables
HCO
3
(Measured or calculated)

10. Contd…
Buffer Base:
It is total quantity of buffers in blood including
both volatile(Hco
3
) and nonvolatile (as
Hgb,albumin,Po
4
)
Base Excess/Base Deficit:
Amount of strong acid or base needed to restore
plasma pH to 7.40 at a PaCO2 of 40 mm Hg,at
37*C.
 Calculated from pH, PaCO2 and HCT
Negative BE also referred to as Base Deficit
True reflection of non respiratory (metabolic) acid
base status
 Normal value: -2 to +2mEq/L

11. CENTRAL EQUATION OF ACID-BASE PHYSIOLOGY
 Henderson Hasselbach Equation:

where [ H
+
] is related to pH by
To maintain a constant pH, PCO2/HCO3
-
ratio should be
constant
When one component of the PCO2/[HCO3
-
]ratio is altered, the
compensatory response alters the other component in the
same direction to keep the PCO2/[HCO3
-
] ratio constant
 [H
+
] in nEq/L = 24 x (PCO2 / [HCO3
-
] )
 [ H
+
] in nEq/L = 10
(9-pH)

12. Compensatory response or regulation
of pH
By 3 mechanisms:
Chemical buffers:
React instantly to compensate for the addition or
subtraction of H+ ions
CO2 elimination:
Controlled by the respiratory system
Change in pH result in change in PCO2 within
minutes
HCO3
-
elimination:
Controlled by the kidneys
Change in pH result in change in HCO3-
It takes hours to days and full compensation occurs
in 2-5 days

13. Normal Values
Variable Normal Normal
Range(2SD)
pH 7.40 7.35 - 7.45
pCO2 40 35-45
Bicarbonate 24 22-26
Anion gap 12 10-14
Albumin 4 4

14. Steps for ABG analysis
1.What is the pH? Acidemia or Alkalemia?
2.What is the primary disorder present?
3.Is there appropriate compensation?
4.Is the compensation acute or chronic?
5.Is there an anion gap?
6.If there is a AG check the delta gap?
7.What is the differential for the clinical
processes?

15. Step 1:
Look at the pH: is the blood acidemic or alkalemic?
EXAMPLE :
65yo M with CKD presenting with nausea, diarrhea and acute
respiratory distress
ABG :ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 7/BUN 119/ Cr 5.1
 ACIDMEIA OR ALKALEMIA ????

16. EXAMPLE ONE
ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 7/BUN 119/
Cr 5.1
Answer PH = 7.23 , HCO3 7
Acidemia

17. Step 2: What is the primary disorder?
What disorder is
present?
pH pCO2 HCO3
Respiratory AcidosispH low high high
Metabolic AcidosispH low low low
Respiratory AlkalosispH high low low
Metabolic AlkalosispH high high high

18. Contd….
Metabolic Conditions are suggested if
pH changes in the same direction as pCO2 or pH is
abnormal but pCO2 remains unchanged
Respiratory Conditions are suggested if:
pH changes in the opp direction as pCO2 or pH is
abnormal but HCO3- remains unchanged

19. EXAMPLE
ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 7/BUN 119/ Cr 5.
PH is low , CO2 is Low
PH and PCO2 are going in same directions then its most likely
primary metabolic

20. EXPECTED CHANGES IN ACID-BASE DISORDERS

Primary Disorder Expected Changes

Metabolic acidosis PCO2 = 1.5 × HCO3 + (8 ± 2)
Metabolic alkalosis PCO2 = 0.7 × HCO3 + (21 ± 2)
Acute respiratory acidosis delta pH = 0.008 × (PCO2 - 40)
Chronic respiratory acidosis delta pH = 0.003 × (PCO2 - 40)
Acute respiratory alkalosis delta pH = 0.008 × (40 - PCO2)
Chronic respiratory alkalosis delta pH = 0.003 × (40 - PCO2)
From: THE ICU BOOK - 2nd Ed. (1998) [Corrected]

21. Step 3-4: Is there appropriate
compensation? Is it chronic or acute?
Respiratory Acidosis
Acute (Uncompensated): for every 10 increase in pCO2 -> HCO3 increases by
1 and there is a decrease of 0.08 in pH
Chronic (Compensated): for every 10 increase in pCO2 -> HCO3 increases by
4 and there is a decrease of 0.03 in pH
Respiratory Alkalosis
Acute (Uncompensated): for every 10 decrease in pCO2 -> HCO3
decreases by 2 and there is a increase of 0.08 in PH
Chronic (Compensated): for every 10 decrease in pCO2 -> HCO3 decreases
by 5 and there is a increase of 0.03 in PH

Partial Compensated: Change
in pH will be between 0.03 to
0.08 for every 10 mmHg
change in PCO2

22. Step 3-4: Is there appropriate
compensation?
Metabolic Acidosis
Winter’s formula: Expected pCO2 = 1.5[HCO3] + 8 ± 2
OR
D pCO2 = 1.2 (D HCO3)
If serum pCO2 > expected pCO2 -> additional respiratory acidosis
and vice versa
Metabolic Alkalosis
Expected PCO2 = 0.7 × HCO3 + (21 ± 2)
OR
D pCO2 = 0.7 (D HCO3)
If serum pCO2 < expected pCO2 - additional respiratory
alkalosis and vice versa

23. EXAMPLE
ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 7/BUN 119/ Cr
5.
Winter’s formula : 17= 1.5 (7) +8 ±2 = 18.5(16.5
– 20.5)
So correct compensation so there is only one
disorder Primary metabolic

24. Step 5: Calculate the anion gap
AG used to assess acid-base status esp in D/D of met
acidosis
D AG & D HCO
3
-
used to assess mixed acid-base disorders
AG based on principle of electroneutrality:
Total Serum Cations = Total Serum Anions
Na + (K + Ca + Mg) = HCO3 + Cl + (PO4 + SO4
+ Protein + Organic Acids)
Na + UC = HCO3 + Cl + UA
Na – (HCO3 + Cl) = UA – UC
Na – (HCO3 + Cl) = AG
Normal =12 ± 2

25. Contd…
AG corrected = AG + 2.5[4 – albumin]
If there is an anion Gap then calculate
the Delta/delta gap (step 6) to determine
additional hidden nongap metabolic
acidosis or metabolic alkalosis
If there is no anion gap then start
analyzing for non-anion gap acidosis

26. EXAMPLE
Calculate Anion gap
ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 7/BUN 119/ Cr 5/ Albumin
2.
AG = Na – Cl – HCO3 (normal 12 ± 2)
123 – 97 – 7 = 19
AG corrected = AG + 2.5[4 – albumin]
= 19 + 2.5 [4 – 2]
= 19 + 5 = 24

27. Step 6: Calculate Delta Gap
Delta gap = (actual AG – 12) + HCO3
Adjusted HCO3 should be 24 (+_ 6) {18-30}
If delta gap > 30 -> additional metabolic alkalosis
If delta gap < 18 -> additional non-gap metabolic
acidosis
If delta gap 18 – 30 -> no additional metabolic disorders

28. EXAMPLE : Delta Gap
ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 7/BUN 119/ Cr 5/ Albumin
4.
Delta gap = (actual AG – 12) + HCO3
(19-12) +7 = 14
Delta gap < 18 -> additional non-gap metabolic
acidosis
So Metabolic acidosis anion and non anion gap

29. Metobolic acidosis: Anion gap acidosis

30. EXAMPLE: WHY ANION GAP?
65yo M with CKD presenting with nausea, diarrhea and acute
respiratory distress
ABG :ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 7/BUN 119/ Cr 5.1
So for our patient for anion gap portion its due to BUN of
119 UREMIA
But would still check lactic acid

31. Nongap metabolic acidosis
For non-gap metabolic acidosis, calculate the urine anion gap
URINARY AG
Total Urine Cations = Total Urine Anions
Na + K + (NH4 and other UC) = Cl + UA
(Na + K) + UC = Cl + UA
(Na + K) – Cl = UA – UC
(Na + K) – Cl = AG

Distinguish GI from renal causes of loss of HCO3 by estimating
Urinary NH4+ .
Hence a -ve UAG (av -20 meq/L) seen in GI, while +ve value (av
+23 meq/L) seen in renal problem.
UAG = UNA + UK – UCL
Kaehny WD. Manual of Nephrology 2000; 48-62

32. EXAMPLE : NON ANION GAP ACIDOSIS
65yo M with CKD presenting with nausea, diarrhea and acute
respiratory distress
ABG :ABG 7.23/17/235 on 50% VM
BMP Na 123/ Cl 97/ HCO3 14
AG = 123 – 97-14 = 12
Most likely due to the diarrhea

33. Causes of nongap metabolic acidosis - DURHAM
Diarrhea, ileostomy, colostomy, enteric fistulas
Ureteral diversions or pancreatic fistulas
RTA type I or IV, early renal failure
Hyperailmentation, hydrochloric acid administration
Acetazolamide, Addison’s
Miscellaneous – post-hypocapnia, toulene, sevelamer, cholestyramine ingestion

34. Metabolic alkalosis
Calculate the urinary chloride to differentiate saline responsive vs
saline resistant
Must be off diuretics in order to interpret urine chloride
Saline responsive UCL<25 Saline-resistant UCL >25
Vomiting If hypertensive: Cushings, Conn’s, RAS, renal failure
with alkali administartion
NG suction If not hypertensive: severe hypokalemia,
hypomagnesemia, Bartter’s, Gittelman’s, licorice
ingestion
Over-diuresis Exogenous corticosteroid administration
Post-hypercapnia

35. Respiratory Alkalosis
Causes of Respiratory Alkalosis
Anxiety, pain, fever
Hypoxia, CHF
Lung disease with or without hypoxia – pulmonary embolus, reactive airway,
pneumonia
CNS diseases
Drug use – salicylates, catecholamines, progesterone
Pregnancy
Sepsis, hypotension
Hepatic encephalopathy, liver failure
Mechanical ventilation
Hypothyroidism
High altitude

36. Case1.
7.27/58/60 on 5L, HCO
3
-
26, anion gap is
12, albumin is 4.0
1. pH= Acidemia (pH < 7.4)
2.CO
2
= Acid (CO2>40)
Opposite direction so Primary disturbance =
Respiratory Acidosis
3 &4: Compensation : Acute or chronic? ACUTE
CO
2
has increased by (58-40)=18
If chronic the pH will decrease 0.05 (0.003 x 18 = 0.054)
 pH would be 7.35
If acute the pH will decrease 0.14 (0.008 x 18 = 0.144)
pH would be 7.26.

37. Contd.
5: Anion gap –N/A
6: There is an acute respiratory acidosis, is
there a metabolic problem too?
ΔHCO
3
-
= 1 mEq/L↑/10mmHg↑pCO
2
The pCO
2
is up by 18  so it is expected that the
HCO
3
-
will go up by 1.8. Expected HCO
3
-
is 25.8,
compared to the actual HCO
3
-
of 26, so there is no
additional metabolic disturbance.
Dx-ACUTE RESPIRATORY ACIDOSIS

38. Case.2
7.54/24/99 on room air, HCO
3
-
20, anion
gap is 12, albumin is 4.0.
1: pH= Alkalemia (pH > 7.4)
2.CO
2
= Base (CO2<40)
pH & pCO2 change in opposite Direction So
Primary disturbance = Respiratory Alkalosis
3 &4: Compensation ? acute or chronic? ACUTE
ΔCO
2
=40-24=16
If chronic the pH will increase 0.05 (0.003 x 16 = 0.048)
 pH would be 7.45
If acute the pH will increase 0.13(0.008 x 16 = 0.128)
pH would be 7.53

39. Contd…
5:Anion gap – N/A
6: There is an acute respiratory alkalosis, is
there a metabolic problem too?
ΔHCO
3
-
= 2 mEq/L↓/10mmHg↓pCO
2
The pCO
2
is down by 16  so it is expected that the
HCO
3
-
will go down by 3.2. Expected HCO
3
-
is 20.8,
compared to the actual HCO
3
-
of 20, so there is no
additional metabolic disturbance.
Dx-ACUTE RESPIRATORY ALKALOSIS

40. Case-3
7.58/55/80 on room air, HCO
3
-
46, anion gap is
12, albumin is 4.0. Ucl -20
1: pH= Alkalemia(pH > 7.4)
 2:CO
2
= Acid (CO2>40)
Same direction so Primary disturbance = Metabolic
Alkalosis
3&4: Compensation:
∆ pCO
2
=0.7 x ∆ HCO
3
-
The HCO
3
-
is up by 22.CO
2
will increase by 0.7x22 = 15.4.
Expected CO
2
is 55.4, compared to the actual CO
2
of 55,
therefore there is no additional respiratory disturbance.

41. contd
5: No anion gap is present; and no adjustment
needs to be made for albumin. Metabolic
Alkalosis
Urinary chloride is 20 meq/l (< 25 meq/l)so
chloride responsive, have to treat with Normal
saline.
Dx-METABOLIC ALKALOSIS

42. Case-4
7.46/20/80 on room air, HCO
3
-
16, anion
gap = 12, albumin = 4.0
1: pH = Alkalemia (pH > 7.4)
2:CO
2
= Base (CO2<40)
So Primary disturbance = Respiratory Alkalosis
3 &4: Compensation? acute or chronic? Chronic
ΔCO
2
=40-20= 20.
If chronic the pH will increase 0.06 (0.003 x 20 = 0.06) 
pH would be 7.46.
If acute the pH will increase 0.16 (0.008 x 20 = 0.16)
pH would be 7.56.

43. Contd….
5: Anion gap – N/A
6: There is a chronic respiratory alkalosis, is
there a metabolic problem also?
Chronic: ΔHCO
3
-
= 4 mEq/L↓/10mmHg↓pCO
2
The pCO
2
is down by 20  so it is expected that the
HCO
3
-
will go down by 8. Expected HCO
3
-
is 16,
therefore there is no additional metabolic disorder.
 Dx-CHRONIC RESPIRATORY ALKALOSIS

44. Case-5
7.19/35/60 on 7L, HCO
3
-
9, anion gap = 18,
albumin = 4.0
1: pH = Acidemia (pH < 7.4)
2:CO
2
= Base (CO2<40)
So Primary disturbance: Metabolic Acidosis
3&4: Compensation ?
∆ pCO
2
=1.2 x ∆ HCO
3
-
CO
2
will decrease by 1.2 (∆HCO
3
-
)  1.2 (24-9) 18. 40 – 18=
22 Actual CO
2
is higher than expected Respiratory
Acidosis
5: Anion Gap = 18 (alb normal so no correction
necessary)

45. Contd…..
6: Delta Gap:
Delta gap = (actual AG – 12) + HCO3
= (18-12) + 9
= 6 + 9 = 15 which is<18 Non-AG Met Acidosis
Dx-ANION GAP METABOLIC ACIDOSIS with NON-ANION GAP
METABOLIC ACIDOSIS with RESPIRATORY ACIDOSIS

46. Case-6
7.54/80/65 on 2L, HCO
3
-
54, anion gap
12,albumin = 4.0 , Ucl 40 meq/l
1: pH = Alkalemia (pH > 7.4)
2:CO
2
= Acid (CO2>40)
So Primary disturbance: Metabolic Alkalosis
3&4: Compensation?
∆ pCO
2
=0.7 x ∆ HCO
3
-
CO
2
will increase by 0.7 (∆HCO
3
-
)  0.7 (54-24)
2140 + 21 = 61 Actual CO
2
is higher than
expected Respiratory Acidosis

47. Contd….

5: Anion Gap = 12 (alb normal so no correction
necessary)
Urinary chloride is 40 meq/l (> 25 meq/l)so
chloride resistant. So treatment would be
disease specific and repletion of potassium
Dx-METABOLIC ALKALOSIS with RESPIRATORY
ACIDOSIS

48. Case-7
7.6/30/83 on room air, HCO
3
-
28, anion gap = 12,
albumin = 4.0
1: pH = Alkalemia (pH > 7.4)
2:CO
2
= Base (CO2<40)
SoPrimary Disturbance: Metabolic Alkalosis
3&4: Compensation ?
∆ pCO
2
=0.7 x ∆ HCO
3
-
CO
2
will increase by 0.7 (∆HCO
3
-
)  0.7 (28-24) 2.8 40 + 2.8 =
42.8 Actual CO
2
is lower than expected Respiratory Alkalosis
 Anion Gap = 12 (alb normal so no correction necessary)
See urinary chloride for further Dx.
Dx-METABOLIC ALKALOSIS with RESPIRATORY ALKALOSIS

49. Case-8
A 50 yo male present with sudden onset of SOB with
following ABG 7.25/46/78 on 2L, HCO
3
-
20, anion gap =
10, albumin = 4.0
1: pH = Acidemia (pH < 7.4)
2:CO
2
= Acid (CO2>40)
So Primary disturbance: Respiratory Acidosis
3 &4: If respiratory disturbance is it acute or chronic?
ACUTE
∆ CO
2
= 46-40= 6
If chronic the pH will decrease 0.02 (0.003 x 6 =
0.018)  pH would be 7.38
If acute the pH will decrease 0.05 (0.008 x 6 = 0.048)
pH would be 7.35.

50. Contd…
 Anion Gap = 10 (alb normal so no correction necessary)
6: There is an acute respiratory acidosis, is there a metabolic
problem too?
∆ HCO
3
-
= 1 mEq/L↑/10mmHg↑pCO
2
The HCO
3
-
will go up 1mEq/L for every 10mmHg the pCO
2
goes up
above 40
The pCO
2
is up by 6  so it is expected that the HCO
3
-
will go up by
0.6. Expected HCO
3
-
is 24.6, compared to the actual HCO
3
-
of 20.
Since the HCO
3
-
is lower than expected Non-Anion Gap Metabolic
Acidosis (which we suspected).
Dx-RESPIRATORY ACIDOSIS with NON-ANION GAP
METABOLIC ACIDOSIS
 

51. Case-9
7.15/22/75 on room air, HCO
3
-
9, anion gap = 10,
albumin = 2.0
1: pH = Acidemia (pH < 7.4)
2:CO
2
= Base (CO2<40)
 So Primary disturbance: Metabolic Acidosis
3&4:∆ Compensation ?
pCO
2
=1.2 x ∆ HCO
3
-
Expected pCO
2
= 1.2 x ∆ HCO
3
-
 1.2 (24 -9)  1.2
(15) 18. The expected pCO
2
is 22mmHg. The actual
pCO
2
is 22, which is expected, so there is no
concomitant disorder.

52. Contd….

5: Anion Gap = 10
AGc = 10 + 2.5(4-2) = 15  Anion Gap Metabolic
Acidosis
6: Delta Gap:
Delta gap = (actual AG – 12) + HCO3
= (15-12) + 9
= 3+ 9 = 12 which is<18 Non-AG
Met Acidosis
Dx-ANION GAP METABOLIC ACIDOSIS with NON-
ANION GAP METABOLIC ACIDOSIS