Basics of Rocket Propulsion Part 2 The Thrust Equation
ZackWanambwa
6,383 views
9 slides
Feb 26, 2015
Slide 1 of 9
1
2
3
4
5
6
7
8
9
About This Presentation
No description available for this slideshow.
Size: 150.74 KB
Language: en
Added: Feb 26, 2015
Slides: 9 pages
Slide Content
Basics of Rocket Propulsion Part 2 The Thrust Equation
Newton’s Second Law of Motion The rate of change of linear momentum of a body is directly proportional to the external force applied on the body, and this change takes place in the direction of the applied force.
1.Constant Mass System An external force will cause the body to accelerate at a rate that is proportional to the force, We know that:- F = ma For a force F, applied for a time dt , :- This law can also be expressed as F = dP / dt i.e rate of change of Momentum.
2. Rocket System Consider a rocket of mass m, drifting at velocity Vo. The Initial Momentum Po, would be INITIAL MOMENTUM at Time = 0
Rocket System FINAL MOMENTUM at Time = t When a rocket is fired, it releases gases weighing mass dm, the rocket it self now weighs m-dm. The final velocity become Vo + dV . The gases leave the exhaust at a velocity u. Momentum at time t, Pt would be:
Rocket System The Term dVdm is very small and can be ignored. (Very small number multiplied by a very small number)
Rocket System Change in Momentum The change in Momentum therefore would be: Since it’s a closed system, the net force is zero, giving:-
Thrust Equation Dividing both sides per unit time t, we get: This is the thrust Equation
Thrust Equation The thrust of a rocket is given by the exhaust velocity multiplied by the Rate of mass ejection.