INTRODUCTION TO CHANNEL MODEL AND CHANNEL CAPACITY
PRESENTED BY- SHILPA DE(35000116019)
CONTENTS: BINARY SYMMETRIC CHANNEL DISCRETE MEMORYLESS CHANNEL TYPES OF CHANNEL EXAMPLES OF CHANNEL CHANNEL CAPACITY CROSSOVER PROBABILITY
BINARY SYMMETRIC CHANNEL A Binary Symmetric Channel is viewed as , a binary bit stream enters at the transmitting end and another bit stream comes out at the receiving end.
Representation of a Binary Symmetric Channel This binary Discrete-input ,Discrete –output channel is characterized by the possible input set X={0,1} and possible output set Y={0,1} and a set of conditional probabilities that relate X and Y.
Let the noise in the channel cause independent errors with average probability of error p. P(Y=0|X=1) = P(Y=1|X=0) = p P(Y=1|X=1) = P(Y=0|X=0) = 1-p A BSC is a special case of Discrete Memoryless Channel.
Representation of DMC Discrete: implies when input set X and output set Y gives us finite values. Memory less : Implies when current o/p value depends on current i /p value , not previous i /p value. X Y x1 x2 x3 . ; xm y 1 y 2 y 3 . . y m P( Yi|Xj )
DEFINITION OF DMC When channel accept a input symbol X, and in respond generate output symbol Y, this input and output along with a conditional probability called DMC. The conditional probability- P(Y= y i | X= x j ) = P( y i | x j ) that characterized a DMC is arranged in the matrix form called the Probability transition matrix.
TYPE OF CHANNELS: 1)Single Input Single Output (SISO) 2) Single Input Multiple Output (SIMO) 3) Multiple Input Single Output (MISO) 4) Multiple Input Multiple Output (MIMO)
single input single output In the diagram, S is input , Y is output, X T is Transmitting antenna and Y R is the Receiving antenna. Where C is the capacity. B is the Bandwidth of the signal and S/N is the signal to noise ratio.
In the diagram, S is input,Y 1 and Y 2 are two output from two receiving antenna , X T is transmitting antenna. Y R1 and Y R2 are two receiving antenna. The channel capacity of the SIMO system is Single Input Multiple Output
In the diagram,S 1 and S 2 are inputs from Transmitting antenna. X T1 and X T2 are two Transmitting antenna. Y R receiving antenna The capacity of this system is C is the capacity, M T is the number of antennas used at transmitter side, B is Bandwidth Of the signal and S/N is the signal to noise ratio. Multiple Input Single Output
Multiple Input Multiple Output
SOME EXAMPLE OF CHANNEL RELAY CHANNEL: In Relay channels there is a source ,a destination and intermediate relay nodes. This relay nodes facilitate communicate between source and destination. There is two way to facilitate the transfer of information- 1)Amplify-and-Forward 2)Decode-and-Forward
RELAY CHANNEL Amplify-and-Forward: Each relay node simply amplifies the received signal and forward it to the next relay node , maintaining a fixed average transmit power. Decode-and-Forward: The relay node can first decode the received signal and then re-encodes the signal before forwarding it to the next relay node .
MULTIPLE ACCESS CHANNEL In Multiple Access Channel, Suppose M transmitters wants to communicate with a single receiver over a common channel.
BROADCAST CHANNEL In Broadcast Channel a single transmitter wants to communicate with M receivers over a common channel.
CHANNEL CAPACITY: The channel capacity of a discrete memoryless channel is defined as- The maximum average mutual information in any single use of the channel,where the maximization is over all possible input probabilities .
C=max I(x;y) p(xj) Where average mutual information provided by the output y about input x is given by- q-1 r-1 I(x;y)=∑ ∑ p(xj)p(yi|xj) log(yi|xj)/p(yi) j=0 i=0 where, P(xj)=input symbol probability P(yi)=output symbol probability P(yi|xj)=channel transition probability(determined by channel characteristics)
So, C=max I(x;y) p(xj) q-1 r-1 = max∑ ∑p(xj)p(yi|xj) logp(yi|xj)/p(yi) j=0 i=0 The maximization of I(x;y) is performed under the constraints P(xj)>=0 and q-1 ∑p(xj)=1 j=0
Units: The units of channel capacity is bits/channel use(where base of logarithm is 2) If base of the logarithm is e,the units of channel capacity will be nats/channel use(coming from natural logarithm)
Crossover probability : In case of BSC with channel transition probability p(0|1)=p(1|0)=p Thus,the transition probability matrix is given by P= 1-p p p 1-p Here,P is reffered to as crossever probability.
Now by symmetry,the capacity- C=max I(x;y) P(xj) Is achieved for input probabilities p(0)=p(1)=0.5 So,we obtain the capacity of a BSC as C=max I(x;y) =max H(yi)-H(yi|xj) =1-(+plog(1/p)+(1-p)log(1/1-p)) =1+plogp+(1-p)log(1-p)
Let us define the entropy function, H(yi|xj)=H(p)=plog(1/p)+(1-p)log(1/1-p) =-plogp-(1-p)log(1-p) Hence,we can rewrite the capacity of a binary symmetric channel as C=1-H(p)
The capacity of a BSC is-
Now,from previous equation of channel capacity- For p=0(noise free channel),the capacity is 1bit/channel use.Here we can successfully transmit 1 bit of information. For p=0.5,the channel capacity is 0.Output gives no information about input.it occurs when the channel is broken. For 0.5<p<1,the capacity increases with increasing p. For p=1,again channel capacity is 1 bit/channel use.
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