In complement of a set if ξ be the universal set and A a subset of ξ, then the
complement of A is the set of all elements of ξ which are not the elements of A.
Symbolically, we denote the complement of A with respect to ξ as A’.
For Example;
If ξ = {1, 2, 3, 4, 5, 6, 7}
A = {1, 3, 7} find A’.
Solution:
We observe that 2, 4, 5, 6 are the only elements of ξ which do not belong to A.
Therefore, A’= {2, 4, 5, 6}
Note:
The complement of a universal set is an empty set.
The complement of an empty set is a universal set.
The set and its complement are disjoint sets.
For Example;
1. Let the set of natural numbers be the universal set and A is a set of even natural
numbers,
then A’ {x: x is a set of odd natural numbers}
2. Let ξ = The set of letters in the English alphabet.
A = The set of consonants in the English alphabet
then A’ = The set of vowels in the English alphabet.
3. Show that;
(a) The complement of a universal set is an empty set.
Let ξ denote the universal set, then
ξ' = The set of those elements which are not in ξ.
= empty set = ϕ
Therefore, ξ = ϕ so the complement of a universal set is an empty set.
(b) A set and its complement are disjoint sets.
Let A be any set then A’ = set of those elements of ξ which are not in A’.
Let x ∉ A, then x is an element of ξ not contained in A’
So x ∉ A’
Therefore, A and A’ are disjoint sets.
Therefore, Set and its complement are disjoint sets
Complement of a set, let U be the universal set and A is a subset of U. Then the
complement of A is the set all elements of U which are not the elements of A.
Symbolically, we write A’ to denote the complement of A with respect to U.
Thus, A’ = {x : x ∈ U and x ∉ A}
Obviously A’ = {U - A}
For Example;
Let U = {2, 4, 6, 8, 10, 12, 14, 16}
A = {6, 10, 4, 16}
A = {2, 8, 12, 14}
We observe that 2, 8, 12, 14 are the only elements of U which do not belong to A.
Some properties of complement sets
(i) A∪A’ = A’∪A = ∪ (Complement law)