cost missing value question www.eakanchha.com

MitaliAgrawal 1,805 views 12 slides Nov 06, 2019
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cost chapter missing value question with complete solution step by step. for more economics and business studies topics login to www.eakanchha.com


Slide Content

OUTPUT AFC AC AVC MC 1 140 50 2 45 3 45 4 22.5 48 5 18 52 The value given in question are written in red colour. Solution I will write in black colour . Q.2

OUTPUT AFC AC AVC MC TFC TC 1 140 50 2 45 3 45 4 22.5 48 5 18 52 The value given in question are written in red colour. Solution I will write in black colour. Two more columns are required for calculation i.e. TFC and TC.

OUTPUT AFC AC AVC MC TFC TC 1 140 50 90 2 45 90 3 45 90 4 22.5 48 90 5 18 52 90 TFC = AFC × OUTPUT. = 22.5 × 4 = 90 And TFC remains same at all the level of output.

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 50 90 2 90 ÷ 2 = 45 45 90 3 90 ÷ 3 = 30 45 90 4 22.5 48 90 5 18 52 90 AFC = TFC ÷ OUTPUT. THE VALUES I HAVE USED HERE IN CALCULATION ARE IN GREEN COLOUR.

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 50 90 2 90 ÷ 2 = 45 45+45 =90 45 90 3 90 ÷ 3 = 30 45 90 4 22.5 22.5+48 =70.5 48 90 5 18 18+52 =70 52 90 AC=AFC+AVC.

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 140 – 90 = 50 50 90 2 90 ÷ 2 = 45 45+45 =90 45 90 3 90 ÷ 3 = 30 45 90 4 22.5 22.5+48 =70.5 48 90 5 18 18+52 =70 52 90 AVC=AC – AFC .

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 140 – 90 = 50 50 90 140 × 1 = 140 2 90 ÷ 2 = 45 45+45 =90 45 90 90 × 2 = 180 3 90 ÷ 3 = 30 45 90 4 22.5 22.5+48 =70.5 48 90 70.5 × 4 = 282 5 18 18+52 =70 52 90 70 × 5 = 350 TC= AC × OUTPUT . Now using TC we will find MC in the next slide.

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 140 – 90 = 50 50 90 140 × 1 = 140 2 90 ÷ 2 = 45 45+45 =90 45 180 – 140 = 40 90 90 × 2 = 180 3 90 ÷ 3 = 30 45 90 4 22.5 22.5+48 =70.5 48 90 70.5 × 4 = 282 5 18 18+52 =70 52 90 70 × 5 = 350 MC n = TC n – TC n-1.

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 140 – 90 = 50 50 90 140 × 1 = 140 2 90 ÷ 2 = 45 45+45 =90 45 180 – 140 = 40 90 90 × 2 = 180 3 90 ÷ 3 = 30 45 90 4 22.5 22.5+48 =70.5 48 90 70.5 × 4 = 282 5 18 18+52 =70 52 90 70 × 5 = 350 Now find TC value at output = 3. So that we can find corresponding value of AC and AVC. ∑MC= TVC. 50+40+45=TVC. Therefore; TVC= 135. AND TC= TVC + TFC. TC= 135 + 90 = 225. (at output = 3) 225

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 140 – 90 = 50 50 90 140 × 1 = 140 2 90 ÷ 2 = 45 45+45 =90 45 180 – 140 = 40 90 90 × 2 = 180 3 90 ÷ 3 = 30 225 ÷ 3 =75 45 90 225 4 22.5 22.5+48 =70.5 48 90 70.5 × 4 = 282 5 18 18+52 =70 52 90 70 × 5 = 350 AC = TC ÷ OUTPUT.

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 140 – 90 = 50 50 90 140 × 1 = 140 2 90 ÷ 2 = 45 45+45 =90 45 180 – 140 = 40 90 90 × 2 = 180 3 90 ÷ 3 = 30 225 ÷ 3 =75 75 – 30 = 45 45 90 225 4 22.5 22.5+48 =70.5 48 90 70.5 × 4 = 282 5 18 18+52 =70 52 90 70 × 5 = 350 AVC = AC – AFC.

OUTPUT AFC AC AVC MC TFC TC 1 90 ÷ 1 = 90 140 140 – 90 = 50 50 90 140 × 1 = 140 2 90 ÷ 2 = 45 45+45 =90 45 180 – 140 = 40 90 90 × 2 = 180 3 90 ÷ 3 = 30 225 ÷ 3 =75 75 – 30 = 45 45 90 225 4 22.5 22.5+48 =70.5 48 282 – 225 = 57 90 70.5 × 4 = 282 5 18 18+52 =70 52 350 – 282 = 68 90 70 × 5 = 350 MC n = TC n – TC n-1.