Design for flexure and shear (rectangular & square section)

bilalakhund 4,363 views 1 slides Dec 19, 2017
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About This Presentation

this document includes the derivation of short formula for bending and shear stresses which are observed in beams of different sections.


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University of Engineering and technology Peshawar, Pakistan Prepared by: Muhammad Bilal

Design for Flexure and Shear
For any cross-sectional shape, flexure and shear are given in the following formulas:
Flexure formula ??????
�=
??????�
??????
and shear formula is ??????
??????=
????????????
??????�

Where:
??????
� = flexure/bending stress
??????
?????? = shearing stress
M = maximum moment applied to the beam
V = maximum shear applied to the beam
I = moment of inertia about the neutral axis
Q = moment of area above or below neutral axis
b = breadth
h= height/depth
c= outermost fiber distance from neutral axis

Now consider a rectangular section
in such case we know the value of ‘c’ i.e. h/2 outermost distance from neutral axis and also we know
the value of ‘I’ moment of inertia of rectangle is
�ℎ
3
12
the bending stress becomes
??????
�=
??????�
??????

Putting these values in formula
= ??????

2
x
12
�ℎ
3

=
6??????
�ℎ
2

So for rectangle bending stress becomes this, incase of
square as b=h so the denominator term will be ℎ
3


for shearing stress
??????
??????=
????????????
??????�
the value of ‘I’ remains same while Q is (

2
×??????)(

4
) =
�ℎ
2
8

Putting values in the formula
=
??????�ℎ
2
8
×
12
�
2
×1

3

=
3??????
2�ℎ
for rectangular section the shearing stresses becomes this, for square it will be
3??????
2ℎ
2