ECEPurdue-PSF-Lundstrom-L2.5v1.pdf.123456

ShivendraPratapSingh720416 29 views 20 slides Aug 26, 2024
Slide 1
Slide 1 of 20
Slide 1
1
Slide 2
2
Slide 3
3
Slide 4
4
Slide 5
5
Slide 6
6
Slide 7
7
Slide 8
8
Slide 9
9
Slide 10
10
Slide 11
11
Slide 12
12
Slide 13
13
Slide 14
14
Slide 15
15
Slide 16
16
Slide 17
17
Slide 18
18
Slide 19
19
Slide 20
20

About This Presentation

dos


Slide Content

Primer on Semiconductors

Unit 2: Quantum Mechanics

Lecture 2.5:
Density of states

Mark Lundstrom
[email protected]
Electrical and Computer Engineering
Purdue University
West Lafayette, Indiana USA
1 Lundstrom: 2018

Conduction and valence bands
conduction “band”
valence “band”
mostly full states
mostly states empty
E
energy vs. position
It will be important for us to know
how the states are distributed in
energy within the conduction and
valence bands.
Most of the empty states (the
holes) in the valence band are
very near E
V.
Most of the filled states (the
electrons) in the conduction
band are very near E
C.
Lundstrom: 2018 2

Density of states
The number of states between E and E + dE is D(E)dE,
where D(E) is the “density of states” (DOS).
In this lecture, we will calculate the DOS. This calculation is
greatly simplified because only the region near the band
edges are important, and in that region, the bands are
nearly parabolic:
valence
band
conduction band
Lundstrom: 2018
3

States in a finite volume of semiconductor
4
ˆx
ˆy
ˆz
Finite volume, Ω
(part of an infinite volume)
Finite number of states
xyz
LLLΩ=
Lundstrom: 2018
Periodic boundary conditions:

x-direction
5
()()
x
ik x
k
x u xeψ=
0
()()01
xx
ik L
x
Leψψ= →=
2 1,2,3,...
xx
kL j jπ= =
2
x
x
kj
L
π
=
2
x
L
π
dk
( )
# of states 2
2
x
k
x
dk
N dk
L
π
= ×== = density of states in -space
x
k
L
Nk
π
“Brillouin zone”
spin

Density- of-states in k- space
6
1D:
2D:
3D:
dk
xy
dk dk
xyz
dk dk dk
Lundstrom: 2018
independent of E(k)

DOS: k-space vs. energy space
7
Lundstrom: 2018
x
dk
dE
E
k
2
x

States are uniformly
distributed in k-space,
but non- uniformly
distributed in energy space.

Depends on E(k)
(e.g. different for parabolic
bands and linear bands)

Example 1: DOS(E) for 1D nanowire
8 Lundstrom: 2018
ˆx
ˆy
ˆz
Find DOS(E) per unit energy, per unit length, a
single subband assuming parabolic energy bands.

1D (single subband)
9
Lundstrom: 2018
E
k
dk2Lπ
dE

1D DOS
10
Lundstrom: 2018
DOS in subband, n. n = 1, 2, 3...

Don’t forget to multiply by 2
11
Lundstrom: 2018
2Lπ
dk
E
k
dk
dE
Multiply by 2 to
account for the
negative k-
states.
(parabolic
energy bands)

Multiple subbands
12
Lundstrom: 2018

Example 2: DOS(E ) for 2D electrons
13
Lundstrom: 2018
Find DOS(E) per unit energy, per unit area, for a
single subband assuming parabolic energy bands.
(large) normalization area
A

Example 2: DOS(E) for 2D electrons
14
Lundstrom: 2018
Area of each
state in k-space:

Example 3: DOS(E) for 3D electrons
15
Lundstrom: 2018
Volume of each
state in k-space:

Ellipsoidal band and valley degeneracy
16
Conduction band of Si:
6 equivalent ellipsoidal valleys:
Lundstrom: 2018

Comments on 3D DOS
17
Lundstrom: 2018
For a bulk semiconductor with parabolic bands:
Si:

GaAs:

Parabolic bands: 1D, 2D, and 3D
18
D
3D
E
D
2D
E
D
1D
E
18 Lundstrom: 2018

Lundstrom: 2018
19
Exercise
19
()Ek
“neutral point”
(“Dirac point”)
D
2D
E
Show that for graphene, the
2D DOS is:

20
Summary
Lundstrom: 2018
The DOS is an important concept – one that we will use
frequently in the next unit.
The DOS depends on dimension.
DOS( k) is constant, but DOS(E) depends on the band
structure.
For 3D, bulk semiconductors with parabolic bands,
DOS ~ (m*)
3/2
and DOS ~ sqrt(E – E
C)