Electrochemistry 05 _ Class Notes __ Parishram 2025.pdf

hbiiuhiuhuh

1. —2025—
FOR CLASS 127

Chemistry

Llectrochemistr
{ Lecture - 05 177 Y.

By- Bharti Ma'am

O

la

E. +

2. TOPICS they :

vision
@ Relation with ms er id
(2) Nouat y"

O qu

3. CHAPTER NAM

3

A
Electrochemistry

nt
2

pe
ve

Er STE 4, D
ME lag ES = A

u,

4. Quick Revision

Se HEC? Cov'= 1m ; P= thax

Ts

Ref Electrode

SRP for SHE = Ov

SHE
eo
Anode — Catmde

kaa

Ga Reduction Potential of Std Hydangen Electrocts = Zero
\

5. Standard hydrogen electrode:

SRP of SHE has been assigned OV.

Finely divided
platinum coated
on platinum foil

The potential of individual half-cell cannot be measured. We can measure only the
difference between the two half-cell potentials that gives the emf of the cell.

6. id®= And

4À
z aur +> — 20? +364 Y
Red Por 5
e aes ph nea) Red" 3 Carod
cale —0-14V =)
cum * Ama. - 0-34V

€ AO Re
ca” paz Cdt E? = -ou- (-074)
0 6 E

SEN ES
COL Carat And re “ou: 01

E° = 0uv | Am
COL ==

7. Electsochemicel

Gibbs Fotee enoy = AG
col
AG = — Useful workdone by the ye ee
AG= —U 4 = |

lec work, AV

Y
=D
Pot: diff = Work done, Y, El.
Change ee PES = AVXx

8. ee q= ne

one
Charge 09 mo ee IF

3

Change onone c=1-6x10

Change on one male E = ley,

Y Nmmol mt Corre?
des Charge. on ime c= que e
w =. Br tes
Elec, " Fea 7. 4 ~ 6500 €
ie ea ee Oe

9. i) Ot Gy &,,= 200
Anz Abba free Ene y Change.
UP = Sta: 9 ibba Pree enor
0) Ar, =2
E oo
E) ba = hall propor BS u, Hk,

3) d= Extensive Property (depend on Anne)
SSR eg
Zh —2R are

a Non - Add. opty:
pa 3) Intensive propor Y
be AR Ear )

ar — 28 EE

10. Aga PE
F = boo
N= Wo: of € rat:

Ara MEE

11. o À x eS
a renacido
A+8 — c+?
a @=C Product)
CReatiant]
il :
Ma) Os (000)

Eu] [pe ean donc pots

=F ¿n=
Fer ne T=Te AO Lay:
ar vie mp [ater Ln m =
[m ] Palco NT mee ee doy re:

12. ae un

E

= I Ch

Cel)

E me 0641 fog 1
LY 7 5 ")

M

I

F=%500
Rak sy

Lame Rod dog m

a

@

13. y, + —
IN, 3H, NM,

Q = E Oroduct)
CReattant)
Q= E NH) YA

ON Em Y

14. IS: GD age

Standard d frge energy and predict feasibility of cell
—_

vr
Zn’ n“2(1M) || Cu*?(1M) | Cu zZ
E° a SA
= + 0.34V er a: 0% — (-0°14) Ce Carmen Ana
u2+ du = +0. Cathode.
ae “an = Ot 0-16 Fa 96500 ¢

Car [lov burs NF Et, de

AGP —2x 96800 x 1:10

15. Gier OS
sar Y
Calculate the standard reduction electrode potential of the (E: ectrode when the
cell potential for the cell[Ni/Ni2* (1M) |] Cu?* (1M) | Cülis 0.05 V.

Given that (E°%,2+icu = 0.34 V).
geet Anode ll Cathode oo VEIA

+, N)
sg _p Cox) (Red E
cal Cae ee 0:54 © 021

(5

oor = 084 —

it 5
Ge)

16. D. F e
Eur M4 ot @
iz eV Y
€
What will be the spontaneous reaction when the following half reactions are combined?

, OMe ZEN Y > OIL Lats We
(i) Fe +e°—> Fe? © = 40.779) > Anode Hall

lmin ¡4
(ii) MnO,"+8H*+5e"—> Mn®* + 4H,0((°=+1.49 Vp PZ
Er

What is the value of E°,.1;? Cathode. hot (ed & pe ae,
Ae y A sacl hig ==
5 x( Fe > C M quin À À Redes
> Ref
ut sen

T noz rem tan + 4H o

=p Y? - 4
SFe + Mnoy +e ase} iP pay [ND

17. In a simple electrochemical cell, which is in the standard state, the half cell reactions

with their appropriate reduction potentials are: SRP 4 +
Sn ®
Pb?*(aq) + 2e-—> Pb(s); A (E°=-013V) Anode Hagen Losefe ~|#
Ag: (aq) + ea —> Ag(s): € (E°=+0.80V) Cather Ha ca RC quin ye
(a) Whatis the cell reaction for the cell?
(b) Calculate the e.m.f. of the cell. ES ai $
+
* Pro U are a #

=> no 2)
hor] — ph Hay

(aos 419)

18. o

o &

Es as Pre And
o

El, stove - (2013)
COR

COL

Bye Ovo + O13
ES = 0937
CUL

19. Oy
yk me
The electrode potentials for ee = cut (69) => A > 26,

ml e +

Cu?*(aq) + e-—> Cu*(aq) O°IS V E Cat 7 00
(aq) =

and Cu*(aq) + e- —> Cu(dq) are 0.15 V x SY

and d +0.50 V respectively. The value of E%.?*icy wade Cu

(A) 0.150v (nec) (3) 0500V

+
Re NRC Y 0.650
@) 0325v pect

Na CUA) —*

a O v
EE OPE AEE, a

72 Os FRONT + (IE Kom
*

20. —— fs à ao arde