Electrochemistry 10 _ Class Notes __ Parishram 2025.pdf

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1. FOR CLASS 127

Chemistry

Electrochemi sty 7

Lecture - 10

By- Bharti Ma’am

E. Walla"

O

2. TOPICS .,....., 5

@ Quick Revision :
@ Fouey ao na
@ e

Oo) Conductance, ConducHvity Molar. conductance

3. CHAPTER NAM

3

A
Electrochemistry

nt
2

pe
ve

Er STE 4, D
ME lag ES = A

u,

4. Quick Revision,

First law: The amount of chemical reaction which occurs at any electrode during
electrolysis by a current is proportional to the quantity of electricity passed through the
electrolyte (solution or melt)

v2 Ges nix =

WFS RT

5. b=2 Txt Y =2
GR =
¿ade
Gui ESA
1H X [See
unit = el
$
IA, Ferien WE

When we
Pars Ic Current Wer

6. Change on one mode Élection :-

“14
Chaxge on one € = éxlo €

Le a
No: of € in one mol= 6-02x10

€ = 3
hasge m one mole € = borrxiorx EX C

\F = 4500 €

a

7. wy Que ®
mole & = IF Na ea De
ar O a Fou
3 mole= SE | BESTE: ra mass a otre
Tmoez 7F | ZT
Lo mol = 20F

Eqwivaleut wi. (E) = Molax Mass

; Gee ‘a
| E = Ep. wt ae sf

res

wee AX

8. -I

Mg +2€ ur)
Dmole e = mole mg > 243

Ree Ih
Imole € 7 mole MY ~> pr

IF = [more m
2

/E= 124 Mm

CE) =

/F = Eq, wot

Anh

9. Sin

*

IF = Eqm
WB500c = E gm
ies em

46500

= 2XEXE
wzz(ie Charge po)

22 =

soo

is

10. W= zxTrt
v0 = wh of Product] Amount of chemical
2= E Nacken
46500 2 = Electrochemical Equivalent
226
Ws E „T«t Abe
Sco aie T= Cut CA)
À = time Chee)
E = Es wot

JF = qSooc

11. 4 we have two Metal

w, = Era
96502

w,= EXI

46500

SF Chasye te £ame( 4) Tree Teh

CE

= E
E

oy

e

Wy
E

12. > À «= VU
pane

+ Metelo
Second law: The amounts of different substances liberated by the same ay of
electricity passing through the electrolytic solution are proportional to their chemical
IAS IA To Ser

equivalent weights.

24 Law

13. +=lomin T=bh5A

A solution of CuSO, is electrolysed for 10 minutes with a current of 1.5 amperes. What is

the mass of copper deposited at the cathode?
: Cu= 635
@=zxt ES E
er I +22 — CUY a
= 5xXlox : =
Qa hd er: vole € — nie Cu gee ee 16
R= wc : JE = [mote cu
: à molee = 2k

LE = 63-54
OU Goo = cry

(es 635
2160
Doc= (35 yee = alent)

TRA

lovnele T= lok

14. If a current of 0.5 ampere flows through a metallic wire for 2 hours, then how many
=

electrons would flow through the wire? er
Tac Lex? C
times 2hr ; no: fe"
no of =? j
Q = Ext -1
Ivo = NX 6x1 C

= O'SX2X fox be

u
=

= 34500
Q= &oo0¢ Texte"

15. Consider the reaction: Cr,0,2- + 14H* + 6e- —> 2Cr9* + 7H,0

What is the quantity of electricity in coulombs needed to reduce 1 mole of Cr,0,?-?

16. NE ».)

How much charge is required for the following reductions:
(i) 1 mol ofAl* to Al? DE

Lf 1 mol of Cu?* to Cu?2F 13
(fü 1 mol ma OI AL

= <=!

à) An ee Jmol e = mol AA == 1+3
mole af = mel Cu 3E = Imo! AL it +H A

2B) = | mol cw 2 x 4500 © M — MA

CS

2X %500 = (mol CA

ov

x
Mino — Mar

2 + 2x = +

Os det), Cred’)
Ze mite

Se Ubo0G

17. 4

si Ni I=54 = 20min
A solution of Lis electrolysed between platinum electrodes using a current of 5

amperes for 20 minutes. What mass of Ni is deposited at the cathode?

nie —> Ni G Sd
PR Qa BAK 20% Eo
dE - mole = (ococ
ARS 545
booots aye |, L
2X USooc = QE 2% 46500 —
SE)

2x 6560

18. + Electronic metallic
« Electrolytic (ions)

19. Type of Conduct

Metallic Conduder Electrolytic Conduvs

= Electric Curreut dur to Low
> Electric Current lua to Flow pal Plow of
ge
> Chemical Henn at Slectrede
— No Chemical, Heactton in Metallic y
Conductor > Masten deposition 0% Electrode. gly
— No deposition af Matter Chemie Reaction
> de not Follow Foraday Law: > Follow Faraday Law of Elec
> follow ohm's Lavo y * polo Ohm's la À of Uke

20. Electrical conductance through metals is called metallic or electronic conductance and is
due to the movement of electrons.
As the electrons enter at one end and go out through the other end, the composition of
the metallic conductor remains unchanged. A
Phe electronic conductance depends on Chemical Reaction 1%
ij the nature and structure of the metal

it). the number of valence electrons per atom Phe Cond. + |
11) temperature (it decreases with increase of temperature). Te i
SEDA

np 7

21. The conductance of electricity by ions present in the solutions is called electrolytic or
PELE Sn

ionic conductance.
Besen

22. (The nature of the electrolyte added
(ii Size of the ions produced and their solvation

(if) The nature of the solvent and its viscosity

Gv) Concentration of the electrolyte
‚(9 Temperature (it increases with the increase of temperature).

SSS

J
t
ye Jak Cond. & Temp: Sap:

23. on

= Brit

K A = ery

RK © ?
N: NEN R= Raistane
k E Kap, Lana a = ig = Conductance
R= ek L- Gt +
A i (CUA Conta

24. Conductance

Rate of Flow of Change im Electrolytic Solution,

Conductonce() = L
R

ike [E33 Chol’
u Electrolyte

a

25. @

Unit of conductance (61) = Js ieee
R ie | Seimem] [mo
CES
(E mno

®s

26. Factors Of fecking Conducante

(D Conductance & No: of Ton

© Conductance, of a Electrolyte >> Conductome of weak

Elect

K
Comduttunte © |
3 On du Can te At Lame cow" of Electrolyte

Change vn Lun

© Conductance CXR Size of Lon,

27. 5) Conductance of Hr ion always greater than an otre Cm NY

6) Conductance of OH Im alwa greater than os Other Anion:

28. Q we have thee Cations Nar, ma, A Lohich ion

Conductance

y
Condo _|

D mp
D ae?
d) Both Aland. mt?

An EER

Will Show max: @

Less charge — Cond Max:

29. @ Max Conducta = Mk
& onductane hy: Nat KR À cha > ar

a) Na

b) KT Me
GE k > May:
GI Rb Rh’ Be
a) All ul a

Size af Len $e

Cond A Size Arm

O

30. —— fs à ao arde