R=f2 E £
% 2 Ay E = Sen = Cert mil
I M mol) à
Fa em
f RE er ae,
A = O
Ke pak Kxlooo _ Soa à She
LL i
= N ey
S m ;
Chick Revision PR
®
Im = loocm
ey = Speutre neh:
Im x im = loo com x lowe"
mt = loom yy
O) Conducnity dec], (Rate of Flow
É Deer J Im, Neg, y Conductance Ene?
Resistviry= Sheutre Resiste,
Upon Pilutim
Le un
a iat th
BEIN HA = H° +A E "Treagent)
ue dE dx + ca
n° d=0 c o 6
= ” ZU)
hy = Mole Conduttivirg Lz ENG Ck = AA
ok tone ‘ce? de =) a
Da = Molar cones Km Io
at Cont 2040 Ney ye,
OR
We an
Problem 1: Firstly, passing direct current (DC) changes the composition of the solution.
Solution1: Wewe AC dc RC ui not Change The Compositon,
Of Electrolyte
Problem 2: Secondly, a solution cannot be connected to the bridge like a metallic wire or
other solid conductor. oe
nn
Solution 2: The second problem is solved by using a specially designed vessel called
conductivity cell.
Bel Lg Unknown ‘Rea:
Based on wheat stone bridge principle, standard solution of KCI is used [K of KCl is
taken]. “+= 8
Experiment (1)
Kxa > Known Y
Ro,
ANS
Ry
|
ute So y i
+ Elect roly ae
YO Y
O
Resistance of a conductivity cell filled with 0.1 mol L-! KCI solution is 1000. If the
resistance of the same cell when filled with 0.02 mol L-! KCl solution is 520 0. Calculate
the conductivity and molar conductivity of 0.02 mol L-! KCI solution. The conductivity of
a mer
0.1 mol L-! KCI solution is 1.29 S/m. R= Bao kz?
= = 1129 =
Rz bon K Sr [= 0:02 mafLit font
Pa esmas | x
; Berl 4 A RE
K=lx2 : > OY Sot ne
OR 52 Y
KKR tA Neen KK 1000 A
rex ve À N
eae ; Y
AA i 697
The electrical resistance of a column of 0.05 mol L-! NaOH solution of diameter 1 cm
and length 50 cm is 5.55 x 103 ohm. Calculate its resistivity, conductivity and molar
conductivity.
YY
At infinite dilution ions move freely, that means movement of ions doesn't depend upon
the presence of co-ions (i.e. cations and anions).
ig conductivity of an electrolyte at infinite dilution is sum of molar conductivities of
its constituent ions in the electrolyte.
o = 0
e. CCH, cook) A (ayer r 4, (4)
N Cea) * N, :
m(CH one)” Y A (Naxa) = 2
SoY y :
= a ES 13 na? Nel + ce
In the primary batteries, the reaction occurs only once and after use over a period of
time battery becomes dead and cannot be reused again.
PR
after its
The most familiar example of this type is the dry cell|(known as Leclanche cell
discoverer) which is used commonly in our transistors and [clocks]
In the primary batteries, the reaction occurs only once and after
use over a period of time battery becomes dead and [cannot be
reused again.
The most familiar example of this type is the dry cell (known as
Leclanche cell after its discoverer) which is used commonly in
our transistors and clocks.
Y
ont Anode : Zn(s) > Zn?* +2e-
Cathode : MnO, + NH,* + e” >|MnO(OH)
(Y) Ge >
der inasCRed”)’
And >am cup
+
NH,
Any coh
'arbon rod
(cathode)
Zinc cup MnO, +
(anode) carbon black
+ NH,CI paste
Mercury cell, suitable for|low current devices like hearing aids, watches, etc. consists of
zinc - mercury amalgam as anode and a paste of HgO and carbon as the cathode. The
electrolyte is a paste of KOH and ZnO
0 te .
Anode : Zn(Hg) + 20H > ZnO(S) + H,O + 2e- joa Me im vs)
Cathode : HgO + H,O + 2e- > Hg(I) + 20H-
G 5 n
+ <A da (Red y)
Emp = kame Separator Cathode C°1! an
G ashore Aguda and Sip
A secondary cell after use can be recharged by passing current through it in the
opposite direction so that it can be used again.
A good secondary cell can undergo a
large number of discharging and charging cycles.
@
ah De
commonly used in automobiles and invertors. It Le lead anode and a grid of
lead packed with lead dioxide (PbO,) as cathode.| A(38%)solution of sulphuric acid is
used as an electrolyte.
Galvanic cells that are designed to convert the energy of combustion of fuels like
hydrogen, methane, methanol, etc. directly into electrical energy are called fuel cells.
Reg") : dew In os à Sop AN
Cathode: 0,(g) + 2H,0(1) + 4e- > 40H-(aq) SS t