Subject Code :151002
Name Of Subject :Engineering Electromagnetics
Name of Unit :Energy and potential
Topic :Energy density in electrostatic field
Name of Faculty : Miss. Tanvi Shah
Mr. Niraj Tevar
Name of Students : (I) Savalia Avani(100870111020)
(ii) Patel Jay (100870111021)
Energy Density
Definition:
Energy density is the amount of energy stored in a
given system or region of space per unit mass.
Often only the useful or extractable energy is
quantified, which is to say that chemically
inaccessible energy such as rest mass energy is
ignored.
Sub: EM Topic: Energy Density in Electrostatic Field
Consider a point charge
Q
1
transferred
from infinity to position r
1
i
n the system. It takes no
work to bring the first
charge from infinity since
there is no electric field to
fight against (as
the system is empty i.e.
charge free).
Hence, W
1
= 0 J
Sub: EM Topic: Energy Density in Electrostatic Field
Now bring in another point
charge
Q
2
from infinity to position r2
in the system. In this case we
have to do work against the
electric field generated by the
first charge Q
1
.
Hence, W
2
= Q
2
V
21
where V
21
is the electrostatic
potential at point r
2
due to Q
1
.
- Work done W
2
is also given
as:
Sub: EM Topic: Energy Density in Electrostatic Field
And then the work required to bring Q3 to a distance
R13 from Q1 and distance R23 from Q2 is
W
3
= Q
3
V
31
+ Q
3
V
32
= Q
3
( V
31
+ V
32
)
where V
31
and V
32
are electrostatic potential at point
r
3
due to Q
1
and Q
2
respectively.
The work done is simply the sum of the
work done against the electric field generated
by point charge Q
1
and Q
2
taken in isolation:
Sub: EM Topic: Energy Density in Electrostatic Field
Thus the total work done in assembling the
three charges is given as:
W
E
= W
1
+ W
2
+ W
3
= 0 + Q
2
V
21
+ Q
3
( V
31
+ V
32
)
• Also total work done ( W
E
) is given as:
Sub: EM Topic: Energy Density in Electrostatic Field
If the charges were positioned in reverse order,
then the total work done in assembling them is given
as:
W
E
= W
3
+ W
2
+ W
1
= 0 + Q
2
V
23
+ Q
3
( V
12
+ V
13
)
where V
23
is the electrostatic potential at point r
2
due
to Q
3
and V
12
and V
13
are electrostatic potential at
point r
1
due to Q
2
and Q
3
respectively.
Sub: EM Topic: Energy Density in Electrostatic Field
Adding the above two equations we have,
2W
E
= Q
1
( V
12
+ V
13
) + Q
2
( V
21
+ V
23
) + Q
3
( V
31
+ V
32
)=
Q
1
V
1
+ Q
2
V
2
+ Q
3
V
3
Hence, W
E
=1 / 2 [Q
1
V
1
+ Q
2
V
2
+ Q
3
V
3
]
where V
1
, V
2
and V
3
are total potentials at position r
1
,
r
2
and r
3
respectively.
The result can be generalized for N point charges as:
Sub: EM Topic: Energy Density in Electrostatic Field
The above equation has three interpretation:
a) This equation represents the potential energy of
the system.
b) This is the work done in bringing the static
charges from infinity and assembling them in the
required system.
c) This is the kinetic energy which would be released
if the system gets dissolved i.e. the charges returns
back to infinity.
Sub: EM Topic: Energy Density in Electrostatic Field
In place of point charge, if
the system has continuous charge distribution ( line,
surface or volume charge), then the total work done
in assembling them is given as:
Sub: EM Topic: Energy Density in Electrostatic Field
Since ρ
v
= . D and E = - V,
∇ ∇
Substituting the values in the above equation, work
done in assembling a volume charge distribution in
terms of electric field and flux density is given as:
The above equation tells us that the potential
energy of a continuous charge distribution is stored
in an electric field.
Sub: EM Topic: Energy Density in Electrostatic Field
The electrostatic energy density w
E
is defined as:
Sub: EM Topic: Energy Density in Electrostatic Field