Given an octagon, we need to find the ratio of longest diagonal to the shortest diagonal in the regular octagon.
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Geometry Q11
Qn : Diagonals of octagon (a) 3 : 1 (b) 2 : 1 (c) 2 : 3 (d) 2 : 1 What is the ratio of longest diagonal to the shortest diagonal in a regular octagon?
Soln : Diagonals of octagon Consider regular octagon ABCDEFGH What is the ratio of longest diagonal to the shortest diagonal in a regular octagon? B A C E D F H G P Q a a a a a a a a
Soln : Diagonals of octagon Its longest diagonal would be AE or BF or CG or DH. Let us try to find out AE. Join AD and draw BP AD and CQ AD. PQ = a AP = QD a 2 = BP 2 + AP 2 a 2 = 2 AP 2 {since BP=AP} a = 2AP AP = AD =AP + PQ + QD = + a + What is the ratio of longest diagonal to the shortest diagonal in a regular octagon?
Soln : Diagonals of octagon a + a 2 AE 2 = AD 2 + DE 2 AE 2 = ( a + a 2) 2 + a 2 AE 2 = ( a 2 + 2 x a x 2 2 + 2a 2 ) + a 2 AE 2 = a 2 (1 + 2 2 + 2) + a 2 a 2 (4 + 2 2) Shortest diagonal = AC or CE AC 2 = AB 2 + BC 2 – 2AB × BC cos135 What is the ratio of longest diagonal to the shortest diagonal in a regular octagon?
Soln : Diagonals of octagon (Alternatively, we can deduce this using AC 2 = AQ 2 + QC 2 . We use cosine rule just to get some practice on a different method .) = a 2 + a 2 – 2a 2 × ( ) = 2a 2 + 2a 2 = a 2 (2 + 2) AE 2 = a 2 (4 + 2 2 ) = = 2 What is the ratio of longest diagonal to the shortest diagonal in a regular octagon?
Soln : Diagonals of octagon = 2 Remember, for a regular octagon. Each internal angle = 135 Each external angle = 45 So, we get a bunch of squares and isosceles right–angled s if we draw diagonals. A regular hexagon breaks into equilateral triangles. A regular octagon breaks into isosceles right angled triangles. Answer choice (d) What is the ratio of longest diagonal to the shortest diagonal in a regular octagon?