Geometry Consider a right–angled triangle with inradius 2 cm and circumradius of 7 cm. What is the area of the triangle? (a) 32 sq cms (b) 31.5 sq cms (c) 32.5 sq cms ( d) 33 sq cms
Geometry r = 2 R = 7 = Hypotenuse = 14 r = 2 = a + b – 14 = 4 Consider a right–angled triangle with inradius 2 cm and circumradius of 7 cm. What is the area of the triangle?
Geometry a + b = 18 a 2 + b 2 = 14 2 a 2 + (18 – a) 2 = 196 a 2 + 324 + a 2 – 36a = 196 2a 2 – 36a + 128 = 0 a 2 – 18a + 64 = Consider a right–angled triangle with inradius 2 cm and circumradius of 7 cm. What is the area of the triangle?
Geometry Now the 2 roots to this equation will effectively be a, 18 – a. Product of the roots = 64. Area = × product of roots (How? Come on, you can figure this out .) = 32 sq. cms Answer choice (a) Consider a right–angled triangle with inradius 2 cm and circumradius of 7 cm. What is the area of the triangle?
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